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Check if the sample size is large enough to use the normal distribution to make a confidence interval for \(p\) for each of the following cases. a. \(n=80\) and \(\hat{p}=.85\) b. \(n=110 \quad\) and \(\quad \hat{p}=.98\) c. \(n=35\) and \(\hat{p}=.40\) d. \(n=200\) and \(\hat{p}=.08\)

Short Answer

Expert verified
The sample size is large enough to use the normal distribution to make a confidence interval for cases a, c and d but not for case b.

Step by step solution

01

- Check for case a

First calculate \(np\) and \(n(1-p)\) for case a: \(n=80\) and \(\hat{p}=.85\). Therefore, \(np = 80*0.85 = 68 \) and \( n(1-p) = 80(1-0.85) = 12 \). Since both of these values are greater than 10, the sample size is large enough to approximate the binomial distribution with a normal distribution.
02

- Check for case b

Next, we do the same for case b: \(n=110\) and \(\hat{p}=.98\) to get \(np = 110*0.98 = 107.8 \) and \( n(1-p) = 110(1-0.98) = 2.2 \). Here \( n(1-p) = 2.2 \) is less than 10, so the sample size is not large enough to use the normal distribution to make a confidence interval.
03

- Check for case c

For case c: \(n=35\) and \(\hat{p}=.40\), we get \(np = 35*0.40 = 14 \) and \( n(1-p) = 35(1-0.40) = 21 \). Both values are greater than 10, so the sample size is large enough.
04

- Check for case d

Finally, for case d: \(n=200\) and \(\hat{p}=.08\), we find \(np = 200*0.08 = 16 \) and \( n(1-p) = 200(1-0.08) = 184 \). These values both are also above 10, so the sample size for this case is also large enough.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Size
Sample size is a critical factor in creating statistical models, especially when approximating distributions. It refers to the number of observations or data points in a sample, often denoted by the variable \(n\). The size of a sample affects the accuracy and reliability of the statistical results we obtain.
In general, the larger the sample size, the more information it provides about the underlying population. This makes the estimates more reliable and less susceptible to random error. Determining whether a sample size is large enough often depends on the context and the statistical tests being conducted.
  • A large sample size reduces variability, giving a clearer picture of the mean and standard deviation of the sample.
  • It helps in estimating the parameters of the population with greater precision.
  • For the normal approximation to the binomial distribution, a rule of thumb is that both \(np\) and \(n(1-p)\) should be greater than 10.
The choice of a correct sample size ensures that statistical analyses are robust and conclusions drawn are valid.
Normal Distribution
Normal distribution, often referred to as the Gaussian distribution, is one of the most important probability distributions in statistics. Characterized by its bell-shaped curve, it's defined by two parameters: the mean (µ) and the standard deviation (σ).
Normal distribution is widely used in statistical methods because of the Central Limit Theorem, which states that the sum of a large number of independent and identically distributed variables will approximately follow a normal distribution, regardless of the underlying distribution.
Key properties of the normal distribution include:
  • The mean, median, and mode of a normal distribution are equal.
  • The curve is symmetric around the mean.
  • About 68% of values lie within one standard deviation from the mean, 95% within two, and 99.7% within three, often referred to as the 68-95-99.7 rule.
These properties make the normal distribution extremely useful for making confidence intervals and conducting hypothesis testing.
Binomial Distribution
The binomial distribution describes the number of successes in a fixed number of independent and identically distributed binary experiments, known as trials. Each trial has only two possible outcomes: success or failure. The probability of success is denoted as \(p\) and the number of trials as \(n\).
This distribution is important for understanding processes where outcomes are discrete, like flipping a coin or answering true/false questions.
Some characteristics of the binomial distribution are:
  • It is determined by two parameters: the number of trials \(n\) and the probability of success in each trial \(p\).
  • Its mean is \(np\), and its variance is \(np(1-p)\).
  • As \(n\) becomes larger, the binomial distribution looks more like a normal distribution, which leads to using normal approximation.
The approximation is useful when both \(np\) and \(n(1-p)\) are greater than 10, ensuring enough sample size for the approximation to be valid.
Statistical Approximation
Statistical approximation refers to methods used to estimate a distribution or infer population parameters when exact calculations are complex or impractical. In practice, approximations provide simpler models that are easier to work with.
One common scenario is using the normal approximation of the binomial distribution. This is applicable when the number of trials is large, and success probability is not too near either 0 or 1. The approximating curve can help to efficiently calculate probabilities.
  • It's used when the computation of binomial probabilities is cumbersome due to large \(n\).
  • Approximations lead to ease of calculation when forming confidence intervals or conducting hypothesis testing.
  • Accurate approximation is contingent on guidelines like the 10-rule, ensuring that \(np\) and \(n(1-p)\) are greater than 10.
Such approximations are instrumental in many fields, allowing researchers to derive answers quickly while maintaining a high degree of accuracy.

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Most popular questions from this chapter

Determine the sample size for the estimate of \(\mu\) for the following. a. \(E=.17, \quad \sigma=.90\), confidence level \(=99 \%\) b. \(E=1.45, \quad \sigma=5.82\) confidence level \(=95 \%\) c. \(E=5.65, \quad \sigma=18.20\), confidence level \(=90 \%\)

A consumer agency that proposes that lawyers' rates are too high wanted to estimate the mean hourly rate for all lawyers in New York City. A sample of 70 lawyers taken from New York City showed that the mean hourly rate charged by them is \(\$ 570\). The population standard deviation of hourly charges for all lawyers in New York City is \(\$ 110\). a. Construct a \(99 \%\) confidence interval for the mean hourly charges for all lawyers in New York City. b. Suppose the confidence interval obtained in part a is too wide. How can the width of this interval be reduced? Discuss all possible alternatives. Which alternative is the best?

In a random sample of 50 homeowners selected from a large suburban area, 19 said that they had serious problems with excessive noise from their neighbors. a. Make a \(99 \%\) confidence interval for the percentage of all homeowners in this suburban area who have such problems. b. Suppose the confidence interval obtained in part a is too wide. How can the width of this interval be reduced? Discuss all possible alternatives. Which option is best?

A random sample of 36 mid-sized cars tested for fuel consumption gave a mean of \(26.4\) miles per gallon with a standard deviation of \(2.3\) miles per gallon. a. Find a \(99 \%\) confidence interval for the population mean, \(\mu .\) b. Suppose the confidence interval obtained in part a is too wide. How can the width of this interval be reduced? Describe all possible alternatives. Which alternative is the best and why?

At the end of Section \(8.2\), we noted that we always round up when calculating the minimum sample size for a confidence interval for \(\mu\) with a specified margin of error and confidence level. Using the formula for the margin of error, explain why we must always round up in this situation.

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