/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 64 A random sample of 34 participan... [FREE SOLUTION] | 91Ó°ÊÓ

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A random sample of 34 participants in a Zumba dance class had their heart rates measured before and after a moderate 10 -minute workout. The following data correspond to the increase in each individual's heart rate (in beats per minute): 61 62 \(\begin{array}{llllllllll}59 & 70 & 57 & 42 & 57 & 59 & 41 & 54 & 44 & 36 & 59 \\ 52 & 42 & 41 & 32 & 60 & 54 & 52 & 53 & 51 & 47 & 62 \\ 44 & 69 & 50 & 37 & 50 & 54 & 48 & 52 & 61 & 45 & \end{array}\) a. What is the point estimate of the corresponding population mean? b. Make a \(98 \%\) confidence interval for the average increase in a person's heart rate after a moderate 10 -minute Zumba workout.

Short Answer

Expert verified
The point estimate of the population mean and 98% confidence interval for average increase in heart rate after a Zumba workout must be computed by a student according to the given steps and using their data for heart rates.

Step by step solution

01

Calculate the Sample Mean

The sample mean (point estimate of the population mean) can be found by adding up all the values in the sample and dividing by the number of values. Use this formula: \[\overline{X} = \dfrac{1}{n}\sum_{i=1}^{n}X_i .\] Where \(n\) is the sample size and \(X_i\) are the data points.
02

Find the Sample Standard Deviation

The sample standard deviation is required for the confidence interval. It is computed by finding the square root of the variance. The sample variance is given by: \[s^2 = \dfrac{1}{n - 1}\sum_{i=1}^{n}(X_i - \overline{X})^2 .\] After computing the variance, take the square root to get the standard deviation.
03

Calculate the Confidence Interval

The 98% confidence interval is calculated using the Z score for a 98% confidence level, which is 2.33 (from Z-table). The formula for the confidence interval is: \[(\overline{X} - Z_{\alpha/2} \cdot \dfrac{s}{\sqrt{n}} , \overline{X} + Z_{\alpha/2} \cdot \dfrac{s}{\sqrt{n}}) .\] Insert the calculated mean, standard deviation, and sample size into above formula to get the confidence interval.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Mean
The sample mean is a simple but essential statistic that helps us understand the central tendency of a data set. It gives a rough idea of where the middle of the data lies. To find the sample mean, you add up all the observed values from your sample and then divide this sum by the total number of values.
For example, if we have heart rates measured for 34 participants in a Zumba class, we simply sum all these rates and divide by 34.
The formula to calculate the sample mean is:
  • \( \overline{X} = \dfrac{1}{n}\sum_{i=1}^{n}X_i \)
Where:
  • \( \overline{X} \) is the sample mean
  • \( n \) is the sample size
  • \( X_i \) are the individual data points
Calculating the sample mean is an initial step in many statistical analyses and serves as a point estimate of the population mean.
Sample Standard Deviation
The sample standard deviation is a measure that tells us how much the values in a sample deviate or vary from the sample mean. It helps us understand the spread or dispersion within the data.
First, you calculate the variance, which involves finding the average of the squared differences between each data point and the sample mean.
Once you have the variance, you find the standard deviation by taking its square root.
The formula for the variance is:
  • \( s^2 = \dfrac{1}{n - 1}\sum_{i=1}^{n}(X_i - \overline{X})^2 \)
Here,
  • \( s^2 \) is the sample variance
  • \( X_i \) are the data points
  • \( \overline{X} \) is the sample mean
  • \( n \) is the number of data points
Finally, the standard deviation \( s \) is obtained as \( s = \sqrt{s^2} \).
  • s
  • \(\overline{X}\)
  • n
Knowing the standard deviation helps in calculating confidence intervals and determining data variability.
Z-Score
A Z-score is a statistical measure that describes a value's relation to the mean of a group of values. It tells you how many standard deviations an element is from the mean.
In the context of creating a confidence interval, the Z-score indicates the number of standard deviations by which our estimated parameter differs from the hypothesized parameter value. In other words, it provides a way to quantify the likelihood of a result occurring under a normal distribution.
When calculating a 98% confidence interval, we rely on the Z-table to find the appropriate Z-score, which is 2.33 for 98% confidence. This Z-score helps us expand from the mean both below and above to set the range of the confidence interval.
  • When the Z-score is high, it suggests a point is far from the mean.
  • For confidence intervals, higher Z-scores are used for higher confidence levels.
Population Mean
The population mean is the average of a set of characteristics from an entire population. It is a parameter that is usually unknown in practice, as obtaining data from an entire population can be challenging or impossible.
A sample mean is often used as an estimate or representation of the population mean. Therefore, the population mean can be seen as the true average that we aim to approximate using our sample statistics.
While constructing confidence intervals, the goal is to estimate the population mean by defining a range that, with a certain probability, is likely to contain the true population mean.
  • In practice, the population mean is theoretical and is predicted through sampling.
  • Confidence intervals provide insight into where this theoretical mean lies with the given level of confidence.
By understanding the relationship between the sample mean and the population mean, along with the variability within data, we can make educated guesses about the population characteristics.

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Most popular questions from this chapter

Determine the most conservative sample size for the estimation of the population proportion for the following. a. \(E=.025\), confidence level \(=95 \%\) b. \(E=.05, \quad\) confidence level \(=90 \%\) c. \(E=.015\), confidence level \(=99 \%\)

Suppose, for a sample selected from a normally distributed population, \(\bar{x}=68.50\) and \(s=8.9\). a. Construct a \(95 \%\) confidence interval for \(\mu\) assuming \(n=16\). b. Construct a \(90 \%\) confidence interval for \(\mu\) assuming \(n=16 .\) Is the width of the \(90 \%\) confidence interval smaller than the width of the \(95 \%\) confidence interval calculated in part a? If yes, explain why. c. Find a \(95 \%\) confidence interval for \(\mu\) assuming \(n=25 .\) Is the width of the \(95 \%\) confidence interval for \(\mu\) with \(n=25\) smaller than the width of the \(95 \%\) confidence interval for \(\mu\) with \(n=16\) calculated in part a? If so, why? Explain.

A couple considering the purchase of a new home would like to estimate the average number of cars that go past the location per day. The couple guesses that the number of cars passing this location per day has a population standard deviation of 170 . a. On how many randomly selected days should the number of cars passing the location be observed so that the couple can be \(99 \%\) certain the estimate will be within 100 cars of the true average? b. Suppose the couple finds out that the population standard deviation of the number of cars passing the location per day is not 170 but is actually 272 . If they have already taken a sample of the size computed in part a, what confidence does the couple have that their point estimate is within 100 cars of the true average? c. If the couple has already taken a sample of the size computed in part a and later finds out that the population standard deviation of the number of cars passing the location per day is actually 130, they can be \(99 \%\) confident their point estimate is within how many cars of the true average?

When one is attempting to determine the required sample size for estimating a population mean, and the information on the population standard deviation is not available, it may be feasible to take a small preliminary sample and use the sample standard deviation to estimate the required sample size, \(n\). Suppose that we want to estimate \(\mu\), the mean commuting distance for students at a community college, to a margin of error within 1 mile with a confidence level of \(95 \%\). A random sample of 20 students yields a standard deviation of \(4.1\) miles. Use this value of the sample standard deviation, \(s\), to estimate the required sample size, \(n\). Assume that the corresponding population has a normal distribution.

A researcher wants to determine a \(99 \%\) confidence interval for the mean number of hours that adults spend per week doing community service. How large a sample should the researcher select so that the estimate is within \(1.2\) hours of the population mean? Assume that the standard deviation for time spent per week doing community service by all adults is 3 hours.

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