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A marketing researcher wants to find a \(95 \%\) confidence interval for the mean amount that visitors to a theme park spend per person per day. She knows that the standard deviation of the amounts spent per person per day by all visitors to this park is \(\$ 11\). How large a sample should the researcher select so that the estimate will be within \(\$ 2\) of the population mean?

Short Answer

Expert verified
The researcher should select a sample size of 34 to ensure the estimate will be within $2 of the population mean with 95% confidence.

Step by step solution

01

Identify the known variables

The standard deviation \(σ\) is given as \( \$ 11\). The error margin \(E\) is defined by the researcher as \( \$ 2\) which is the maximum difference we allow between our sample mean and the true population mean. For a \(95 \%\) confidence interval, we correspondingly pick a Z value from a standard normal distribution. The Z score associated with a \(95 \%\) confidence interval is \(1.96\).
02

Substitute the known values into the formula

We substitute \(Z = 1.96\), \(σ = \$ 11\) and \(E = \$ 2\) into the sample size formula \(n = ((Z * σ) / E)^2\). To find \(n\), we then calculate \(((1.96 * 11) / 2)^2 = 33.64\).
03

Round up to the nearest whole number

As we can't take a portion of a person as a sample, hence we need to round up to the nearest whole number. Therefore, the smallest appropriate sample size for this research is \(34\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Standard Deviation
When analyzing data, the standard deviation is a key measurement used to understand how spread out numbers are around the mean in a dataset. In simpler terms, it helps us see how much variation exists from the average value.
A lower standard deviation means numbers are closer to the mean, showing consistency. In contrast, a higher standard deviation indicates numbers are spread out over a wider range, suggesting more variability. In the context of our exercise, we have a standard deviation of \(\sigma = 11\) dollars. This tells us how much the amounts spent by visitors deviate from the average expenditure on a daily basis. Knowing this helps us estimate how much we would typically expect a visitor's spending to vary, aiding in establishing confidence intervals.
Sample Size Determination
Determining an appropriate sample size is crucial in statistics, especially when estimating a population parameter like the mean. Using the right sample size ensures that the confidence interval is accurate and reliable.
The general formula for sample size \(n\) is given by:\[ n = \left( \frac{Z * \sigma}{E} \right)^2 \]
  • \Z\ is the Z score corresponding to the desired confidence level.
  • \sigma\ is the standard deviation of the population.
  • E is the margin of error we are willing to accept.
By substituting these values into the formula, we ensure that our estimate for the population mean is precise within our defined margin of error. Applying it to our scenario, the calculated sample size ensures that the average spending per person is within the acceptable range set by the researcher.
Z Score
A Z score, also known as a standard score, is used in statistics to compare an individual data point's position relative to the mean of a group of data. It essentially tells us how many standard deviations a value is from the mean.
For confidence intervals, the Z score helps establish how much deviation is acceptable based on the desired level of confidence. In this case, with a 95% confidence interval, the associated Z score is 1.96.
This value derives from a standard normal distribution table and indicates that 95% of data is within 1.96 standard deviations of the mean. By using this score in our sample size determination, we ensure that our estimation process accounts for a high level of confidence.
Margin of Error
The margin of error in statistics is the maximum amount we expect our sample mean to differ from the population mean. It reflects the uncertainty or potential error in our estimate.
In our example, the margin of error is set at \\(2\, meaning the researcher is comfortable with the sample mean being up to \\)2\ away from the true population mean.Margin of error directly affects how precise our confidence interval is. A smaller margin of error means a more precise estimate, but often requires a larger sample size. Conversely, a larger margin allows for more variation, making larger sample sizes less necessary.
Understanding and deciding on an appropriate margin of error is essential for balancing accuracy with practicality in research.

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Most popular questions from this chapter

When calculating a confidence interval for the population mean \(\mu\) with a known population standard deviation \(\sigma\), describe the effects of the following two changes on the confidence interval: (1) doubling the sample size, (2) quadrupling (multiplying by 4) the sample size. Give two reasons why this relationship does not hold true if you are calculating a confidence interval for the population mean \(\mu\) with an unknown population standard deviation.

Salaried workers at a large corporation receive 2 weeks' paid vacation per year. Sixteen randomly selected workers from this corporation were asked whether or not they would be willing to take a \(3 \%\) reduction in their annual salaries in return for 2 additional weeks of paid vacation. The following are the responses of these workers. \(\begin{array}{llllllll}\text { No } & \text { Yes } & \text { No } & \text { No } & \text { Yes } & \text { No } & \text { No } & \text { Yes } \\ \text { Yes } & \text { No } & \text { No } & \text { No } & \text { Yes } & \text { No } & \text { No } & \text { No }\end{array}\) Construct a \(97 \%\) confidence interval for the percentage of all salaried workers at this corporation who would accept a \(3 \%\) pay cut in return for 2 additional weeks of paid vacation.

A consumer agency wants to estimate the proportion of all drivers who wear seat belts while driving. Assume that a preliminary study has shown that \(76 \%\) of drivers wear seat belts while driving. How large should the sample size be so that the \(99 \%\) confidence interval for the population proportion has a margin of error of \(.03 ?\)

For a population data set, \(\sigma=14.50\). a. What should the sample size be for a \(98 \%\) confidence interval for \(\mu\) to have a margin of error of estimate equal to \(5.50 ?\) b. What should the sample size be for a \(95 \%\) confidence interval for \(\mu\) to have a margin of error of estimate equal to \(4.25\) ?

A dentist wants to find the average time taken by one of her hygienists to take X-rays and clean teeth for patients. She recorded the time to serve 24 randomly selected patients by this hygienist. The data (in minutes) are as follows: \(\begin{array}{llllllllllll}36.80 & 39.80 & 38.60 & 38.30 & 34.30 & 32.60 & 38.70 & 34.50 & 37.00 & 36.80 & 40.90 & 33.80 \\ 37.10 & 33.00 & 35.10 & 38.20 & 36.60 & 38.80 & 39.60 & 39.70 & 35.10 & 38.20 & 32.70 & 39.50\end{array}\) Assume that such times for this hygienist for all patients are approximately normal. a. What is the point estimate of the corresponding population mean. b. Construct a \(99 \%\) confidence interval for the average time taken by this hygienist to take X-rays and to clean teeth for all patients.

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