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At Jen and Perry Ice Cream Company, a machine fills 1-pound cartons of Top Flavor ice cream. The machine can be set to dispense, on average, any amount of ice cream into these cartons. However, the machine does not put exactly the same amount of ice cream into each carton; it varies from carton to carton. It is known that the amount of ice cream put into each such carton has a normal distribution with a standard deviation of 18 ounce. The quality control inspector wants to set the machine such that at least \(90 \%\) of the cartons have more than 16 ounces of ice cream. What should be the mean amount of ice cream put into these cartons by this machine?

Short Answer

Expert verified
The machine should be set to put an average of approximately 43.61 ounces of ice cream into each carton.

Step by step solution

01

Find the z-score that corresponds to a 90% confidence interval

A z-score represents how many standard deviations an element is from the mean. For a normal distribution, approximately 90% of the values lie within \(\pm 1.645\) standard deviations from the mean. So, the z-score in this case is 1.645.
02

Apply the z-score formula

The z-score formula is \(Z = \frac{X - \mu}{\sigma}\), where \(Z\) is the z-score, \(X\) is a value from the data set (in this case, 16 ounces), \(\mu\) is the mean and \(\sigma\) is the standard deviation. We can rewrite this formula to find \(\mu\), the mean: \(\mu = X - Z \cdot \sigma\). Plugging in the given values, we can solve for \(\mu\).
03

Substitute the given values into the formula

Substitute \(X = 16\) ounces, \(Z = 1.645\), and \(\sigma = 18\) ounces into the formula to get: \(\mu = 16 - 1.645 \cdot 18 \approx 12.99\) ounces. However, we interpret this as the machine needs to put less than specified to meet the 90% requirement, which is a contradiction. So, we need to add the value of \(Z \cdot \sigma\) instead of subtracting.
04

Correct interpretation of result

Substitute \(X = 16\) ounces, \(Z = 1.645\), and \(\sigma = 18\) ounces into the formula, considering that \(Z \cdot \sigma\) should be added, we get: \(\mu = 16 + 1.645 \cdot 18 \approx 43.61\) ounces.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Z-Score
The z-score is a key mathematical concept in statistics used to describe a data point's relation to the mean of a group of data points. In simple terms, the z-score tells you how many standard deviations away a particular value is from the mean. To calculate the z-score, you use the formula: \[ Z = \frac{X - \mu}{\sigma} \] where:
  • \( Z \) is the z-score
  • \( X \) is the value from the data set
  • \( \mu \) is the mean
  • \( \sigma \) is the standard deviation
Understanding z-scores is crucial in statistics for comparing different data points within a dataset. It's particularly useful in determining how unusual or typical a data point is within the distribution. For instance, with the ice cream cartons, the objective was to ensure 90% of them contain more than 16 ounces. By using the z-score of 1.645 for 90%, it reveals the means required to meet this threshold.
Exploring Confidence Interval
A confidence interval gives an estimated range of values that likely includes an unknown population parameter. It is derived from the normal distribution and provides a range within which you can be confident that the parameter lies, given a certain percentage of certainty. In the case of the ice cream machine, a 90% confidence interval implies that if you were to sample multiple carts, you'd expect 90% of those samples to contain more than a specified amount of ice cream, suggesting more than 16 ounces. The z-score of 1.645 corresponds to this, which means 90% of data falls within this range around the mean. Confidence intervals are crucial for making estimations about populations based on sample data, offering insight into the reliability of these estimations. It quantifies the level of uncertainty or certainty in a sampling method.
Decoding the Standard Deviation
Standard deviation is a measure of the dispersion or spread of a set of values. It tells how much variation there is from the average (mean). In simpler terms, if the data points are close to the mean, the standard deviation is smaller. If they are spread out over a wider range, the standard deviation is larger. Using the ice cream example, the standard deviation is 18 ounces. This means that the amount of ice cream dispensed can vary typically by 18 ounces from the mean value. This metric is essential for quality control processes, like setting machines to specific thresholds, as it helps determine how consistent the production is and how far it can deviate from the mean. It's a critical concept that implies the reliability of the data.
Significance of the Mean
The mean is a fundamental concept in statistics, representing the average value of a set of numbers. Calculated by adding all the values together and dividing by the number of values, the mean provides a central value. In the case of the ice cream problem, the mean was adjusted to ensure that at least 90% of cartons have more than 16 ounces of ice cream. The calculated mean needed to be \( 43.61 \) ounces to accommodate the adjustments required by taking into account the z-score and standard deviation. The mean is essential because it provides a single value that summarizes the characteristics of a dataset and is crucial for making informed decisions based on that data. By understanding its role in statistical analysis, you can interpret data efficiently and effectively.

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Most popular questions from this chapter

The highway police in a certain state are using aerial surveillance to control speeding on a highway with a posted speed limit of 55 miles per hour. Police officers watch cars from helicopters above a straight segment of this highway that has large marks painted on the pavement at 1 -mile intervals. After the police officers observe how long a car takes to cover the mile, a computer estimates that car's speed. Assume that the errors of these estimates are normally distributed with a mean of 0 and a standard deviation of 2 miles per hour. a. The state police chief has directed his officers not to issue a speeding citation unless the aerial unit's estimate of speed is at least 65 miles per hour. What is the probability that a car traveling at 60 miles per hour or slower will be cited for speeding? b. Suppose the chief does not want his officers to cite a car for speeding unless they are \(99 \%\) sure that it is traveling at 60 miles per hour or faster. What is the minimum estimate of speed at which a car should be cited for speeding?

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A soft-drink vending machine is supposed to pour 8 ounces of the drink into a paper cup. However, the actual amount poured into a cup varies. The amount poured into a cup follows a normal distribution with a mean that can be set to any desired amount by adjusting the machine. The standard deviation of the amount poured is always \(.07\) ounce regardless of the mean amount. If the owner of the machine wants to be \(99 \%\) sure that the amount in each cup is 8 ounces or more, to what level should she set the mean?

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