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In a list of 15 households, 9 own homes and 6 do not own homes. Four households are randomly selected from these 15 households. Find the probability that the number of households in these 4 who own homes is \(\begin{array}{lll}\text { a. exactly } 3 & \text { b. at most } 1 & \text { c. exactly } 4\end{array}\)

Short Answer

Expert verified
a) The probability that exactly 3 households own homes is calculated using the formula of Hypergeometric distribution. b) The probability of at most 1 household owning a home is the sum of the probabilities of exactly 0 and exactly 1 households owning homes. c) The probability that exactly 4 households own homes is calculated using the formula of Hypergeometric distribution.

Step by step solution

01

Calculate the probability of exactly 3 households owning homes

Using the given formula, where \(N=15\) (total households), \(M=9\) (households owning homes), \(n=4\) (selected households), and \(k=3\) (desired households owning homes), compute the probability as follows: \[ P(X = 3) = \frac{{C(9, 3) * C(15-9, 4-3)}}{{C(15, 4)}} \]
02

Calculate the probability of at most 1 household owning a home

For 'at most', the probability encompasses 0 and 1 success. Therefore, sum up the probabilities of \(X = 0\) and \(X = 1\) as follows: \[ P(X \leq 1) = P(X = 0) + P(X = 1) = \frac{{C(9, 0) * C(15-9, 4-0)}}{{C(15, 4)}} + \frac{{C(9, 1) * C(15-9, 4-1)}}{{C(15, 4)}} \]
03

Calculate the probability of exactly 4 households owning homes

Similarly, use the given formula with \(k=4\) to calculate the required probability as follows: \[ P(X = 4) = \frac{{C(9, 4) * C(15-9, 4-4)}}{{C(15, 4)}} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinatorics
Combinatorics is a fascinating area of mathematics focused on counting and arranging objects. It's extremely useful when solving probability questions, especially those involving selection and arrangement. For instance, when trying to find the probability of certain households owning homes from a group, we rely on combinatorial formulas.

In the context of our exercise, the combinations function, denoted as \( C(n, k) \), plays a central role. This function counts the number of ways to select \( k \) objects from a set of \( n \) objects, without regard to order, and is calculated as \( \frac{n!}{k!(n-k)!} \). Here's how it works:
  • "\( n! \)" means "n factorial," which is the product of all positive integers up to \( n \).
  • The formula accounts for every possible combination by adjusting for repeated objects (hence the use of factorials in the denominator).
These combinations are essential for determining probabilities in situations where order does not matter, such as selecting households at random where ownership status is the interest, not the order of selection.
Hypergeometric distribution
The hypergeometric distribution is a probability distribution perfect for scenarios like our current exercise. It describes the likelihood of successes in a sequence of draws without replacement. This distribution is helpful when dealing with dependent events, meaning the outcome of one draw affects the next.

In our setting, where we randomly pick households to see how many own homes, the hypergeometric distribution is used to calculate the probability of getting exactly \( k \) successful outcomes (households owning homes) in \( n \) draws from a finite population of \( N \) households. Here's the formula it depends on:
  • \( \frac{{C(M, k) \times C(N-M, n-k)}}{{C(N, n)}} \) is the equation used.
  • \( M \) is the total number of homes owned.
  • \( N-M \) represents homes not owned.
  • \( n \) is the number of draws made.
This formula calculates the probability by evaluating all possible successful combinations over the total possible outcomes. It offers an exact probability rather than an estimate, making it very powerful for such problems.
House hypothesis testing
House hypothesis testing is not a standard statistical term but it relates well to understanding how hypothesis testing in statistics applies to real-world scenarios like determining homeownership amongst selected households. When we conduct hypothesis testing, we're fundamentally evaluating assumptions or hypotheses against observational data.

For instance, you might start with a null hypothesis such as "the number of households owning a home among the selected is 3." You then assess the probability of this assumption given the data, using the hypergeometric distribution as a tool to test the hypothesis through calculated probabilities.
  • Establish a null hypothesis (e.g., a certain number of homeowners).
  • Calculate the probability of observing your data under the null hypothesis.
  • Decide if the observed data significantly deviates from what's expected under your hypothesis. This decision process is akin to evaluating polling results to check assumptions about population behavior.
By applying what we've calculated using the hypergeometric distribution and combinatorial techniques, we can make informed decisions about household ownership profiles, just as we would validate other hypotheses.

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