/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 68 Bender Electronics buys keyboard... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Bender Electronics buys keyboards for its computers from another company. The keyboards are received in shipments of 100 boxes, each box containing 20 keyboards. The quality control department at Bender Electronics first randomly selects one box from each shipment and then randomly selects 5 keyboards from that box. The shipment is accepted if not more than 1 of the 5 keyboards is defective. The quality control inspector at Bender Electronics selected a box from a recently received shipment of keyboards. Unknown to the inspector, this box contains 6 defective keyboards. a. What is the probability that this shipment will be accepted? b. What is the probability that this shipment will not be accepted?

Short Answer

Expert verified
The probability that the shipment will be accepted can be calculated using binomial distribution with the probabilities summed for 0 and 1 defective keyboards. The probability of not accepting the shipment is the complement of this, calculated as 1 minus the probability of acceptance.

Step by step solution

01

Calculate Probability of Acceptance

To calculate if a box will be accepted, we need to calculate the probability that 0 or 1 out of the 5 keyboards selected are defective. The total number of ways to select 5 keyboards out of 20 is \( C(20,5) \). The number of ways to select a defective keyboard is \( C(6,k) \), where \( k = 0 \) or \( 1 \). The number of ways to select the remaining good keyboards is \( C(14, 5-k) \). So the probability of selecting k defective keyboards is \[ P(K=k) = \frac{C(6, k) - C(14, 5-k)} {C(20,5)} \] Now, the probability of acceptance \( P(A) \) is \( P(K=0) + P(K=1) \).
02

Calculate Probability of Rejection

The probability of not accepting the shipment is the complement of the probability of accepting. This can be calculated as \[ P(NA) = 1 - P(A) \] where \( P(NA) \) is the probability of not accepting the shipment, and \( P(A) \) is the probability of accepting the shipment as calculated in the previous step.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quality Control
Quality control is a vital process in manufacturing and retail to ensure products meet required standards before reaching consumers. At Bender Electronics, quality control involves a systematic inspection of keyboards in each shipment. The process starts by selecting one box randomly from a shipment of 100 boxes. Within this chosen box, 5 keyboards are randomly picked for testing quality. If more than one keyboard is found defective among the selected, the entire shipment is rejected. This method serves to maintain a satisfactory level of quality without inspecting all 2,000 keyboards per shipment.
By focusing on representative samples rather than complete inspections, companies can efficiently monitor product quality while reducing time and costs. This approach also balances the effort between ensuring quality and maintaining operational efficiency.
Probability Calculation
Probability calculation is used in this context to estimate the likelihood of certain outcomes during quality control tests. It follows a systematic approach to quantify the likelihood of accepting or rejecting a shipment based on a sample test.
To find the probability of acceptance, we identify the probability of having up to one defective keyboard out of the 5 sampled. We use the formula for combinations to calculate the different ways to pick keyboards from the box:
  • The total ways to select 5 keyboards: \( C(20,5) \).
  • The combinations for selecting 0 or 1 defective keyboards are \( C(6,0) \) and \( C(6,1) \).
  • And for the remaining good keyboards: \( C(14,5-0) \) and \( C(14,5-1) \).
Then, adding the probabilities for these scenarios gives the overall probability of the shipment being accepted.
This approach provides a mathematical basis for decision-making in quality control by showing potential outcomes using real data from sampling.
Sampling Methods
Sampling methods are crucial for efficiently evaluating product quality without the need to test every unit. Here, Bender Electronics uses a simple random sampling technique. From a batch of 100 boxes, one box is selected randomly, and then five keyboards are randomly chosen from that box.
This method, a subset of probability sampling, ensures each keyboard has an equal chance of selection, offering an unbiased view of the shipment's quality. By focusing on a small, representative subset, Bender Electronics can infer the overall quality of the shipment efficiently and cost-effectively.
Sampling methods like this allow businesses to maintain high standards with optimal resource use. It's essential to use randomization to avoid bias in the sample and get accurate results reflective of the entire shipment.
Defective Items
Defective items refer to products failing to meet the standard quality specifications. In this exercise, a defective keyboard is one that doesn’t meet the functional or visual standards required by Bender Electronics.
When the quality control process detects a high number of defective items within a sample, it indicates potential issues in the manufacturing or handling processes. Here, the maximum allowable defective count for the sample to still accept the shipment is one.
If more than one defective keyboard is found in the chosen box, it suggests a high overall defect rate, leading to the rejection of the entire shipment. This safeguard helps maintain the quality reputation of Bender Electronics, ensuring only high-quality products reach the end consumer.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

York Steel Corporation produces a special bearing that must meet rigid specifications. When the production process is running properly, \(10 \%\) of the bearings fail to meet the required specifications. Sometimes problems develop with the production process that cause the rejection rate to exceed \(10 \%\). To guard against this higher rejection rate, samples of 15 bearings are taken periodically and carefully inspected. If more than 2 bearings in a sample of 15 fail to meet the required specifications, production is suspended for necessary adjustments. a. If the true rate of rejection is \(10 \%\) (that is, the production process is working properly), what is the probability that the production will be suspended based on a sample of 15 bearings? b. What assumptions did you make in part a?

Customers arrive at the checkout counter of a supermarket at an average rate of 10 per hour. and these arrivals follow a Poisson distribution. Using each of the following two methods, find the probability that exactly 4 customers will arrive at this checkout counter during a 2-hour period. a. Use the arrivals in each of the two nonoverlapping 1 -hour periods and then add these. (Note that the numbers of arrivals in two nonoverlapping periods are independent of each other.) b. Use the arrivals in a single 2 -hour period.

Five percent of all cars manufactured at a large auto company are lemons. Suppose two cars are selected at random from the production line of this company. Let \(x\) denote the number of lemons in this sample. Write the probability distribution of \(x\). Draw a tree diagram for this problem.

Briefly explain the concept of the mean and standard deviation of a discrete random variable.

An instant lottery ticket costs \(\$ 2 .\) Out of a total of 10,000 tickets printed for this lottery, 1000 tickets contain a prize of \(\$ 5\) each, 100 tickets have a prize of \(\$ 10\) each, 5 tickets have a prize of \(\$ 1000\) each, and 1 ticket has a prize of \(\$ 5000\). Let \(x\) be the random variable that denotes the net amount a player wins by playing this lottery. Write the probability distribution of \(x\). Determine the mean and standard deviation of \(x\). How will you interpret the values of the mean and standard deviation of \(x\) ?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.