/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 106 Suppose the owner of a salvage c... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Suppose the owner of a salvage company is considering raising a sunken ship. If successful, the venture will yield a net profit of \(\$ 10\) million. Otherwise, the owner will lose \(\$ 4\) million. Let \(p\) denote the probability of success for this venture. Assume the owner is willing to take the risk to go ahead with this project provided the expected net profit is at least \(\$ 500,000\). a. If \(p=.40\), find the expected net profit. Will the owner be willing to take the risk with this probability of success? b. What is the smallest value of \(p\) for which the owner will take the risk to undertake this project?

Short Answer

Expert verified
a. The expected net profit for \(p = 0.40\) is \$1.6 million, so the owner would be willing to take the risk. b. The smallest value of \(p\) for which the owner will take the risk is approximately \(0.33333\) or \(33.33%\).

Step by step solution

01

Calculate Expected Net Profit for \(p=0.40\)

Substitute \(p=0.40\) into the formula for expected net profit: \( E = p \cdot \$10M + (1 - p) \cdot -\$4M = 0.40 \cdot \$10M + (1 - 0.40) \cdot -\$4M = \$4M - \$2.4M = \$1.6M\). Therefore, the expected net profit is \$1.6 million.
02

Evaluate Owner's Willingness to Take Risk at \(p=0.40\)

The owner is willing to take the risk if the expected net profit is at least \$500,000. Since \$1.6 million is greater than \$500,000, the owner would be willing to take the risk given a \(p\) value of 0.40.
03

Calculate Minimum Value of \(p\) for Owner to Take Risk

The owner will take the risk if the expected net profit reaches at least \$500,000. Therefore, set the expected net profit equal to \$500,000 and solve the equation for \(p\): \( \$500,000 = p \cdot \$10M + (1 - p) \cdot -\$4M\). After solving this linear equation for \(p\), the result is \(p \approx 0.33333\) or \(33.33%\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

York Steel Corporation produces a special bearing that must meet rigid specifications. When the production process is running properly, \(10 \%\) of the bearings fail to meet the required specifications. Sometimes problems develop with the production process that cause the rejection rate to exceed \(10 \%\). To guard against this higher rejection rate, samples of 15 bearings are taken periodically and carefully inspected. If more than 2 bearings in a sample of 15 fail to meet the required specifications, production is suspended for necessary adjustments. a. If the true rate of rejection is \(10 \%\) (that is, the production process is working properly), what is the probability that the production will be suspended based on a sample of 15 bearings? b. What assumptions did you make in part a?

In a poll, men and women were asked, "When someone yelled or snapped at you at work, how did you want to respond?" Twenty percent of the women in the survey said that they felt like crying (Time, April 4, 2011 ). Suppose that this result is true for the current population of women employees. A random sample of 24 women employees is selected. Use the binomial probabilities table (Table I of Appendix C) or technology to find the probability that the number of women employees in this sample of 24 who will hold the above opinion in response to the said question is A. at least 5 b. 1 to 3 c, at most 6

A fast food chain store conducted a taste survey before marketing a new hamburger. The results of the survey showed that \(70 \%\) of the people who tried this hamburger liked it. Encouraged by this result, the company decided to market the new hamburger. Assume that \(70 \%\) of all people like this hamburger. On a certain day, eight customers bought it for the first time. a. L.et \(x\) denote the number of customers in this sample of eight who will like this hamburger. Using the binomial probabilities table, obtain the probability distribution of \(x\) and draw a graph of the probability distribution. Determine the mean and standard deviation of \(x\). b. Using the probability distribution of part a, find the probability that exactly three of the eight customers will like this hamburger.

Spoke Weaving Corporation has eight weaving machines of the same kind and of the same age. The probability is .04 that any weaving machine will break down at any time. Find the probability that at any given time a. all eight weaving machines will be broken down b. exactly two weaving machines will be broken down c. none of the weaving machines will be broken down

Customers arrive at the checkout counter of a supermarket at an average rate of 10 per hour. and these arrivals follow a Poisson distribution. Using each of the following two methods, find the probability that exactly 4 customers will arrive at this checkout counter during a 2-hour period. a. Use the arrivals in each of the two nonoverlapping 1 -hour periods and then add these. (Note that the numbers of arrivals in two nonoverlapping periods are independent of each other.) b. Use the arrivals in a single 2 -hour period.

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.