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Find \(P(A\) or \(B)\) for the following. a. \(P(A)=.28, \quad P(B)=.39\), and \(P(A\) and \(B)=.08\) b. \(P(A)=.41, \quad P(B)=.27\), and \(P(A\) and \(B)=.19\)

Short Answer

Expert verified
For the first scenario, the probability of A or B occurring is .59 and for the second scenario it's .49

Step by step solution

01

Understand the Problem Statement

The problem provides probabilities of two separate events A and B, as well as their intersection (i.e., them occurring simultaneously). We are to find the probability of A or B occurring, which can happen in one of three ways: only A occurs, only B occurs, both A and B occur. The formula for the Addition Rule will be applied to find these.
02

Apply the Addition Rule for P(A or B) for first scenario

Given \(P(A)=.28, P(B)=.39\), and \(P(A and B)=.08\). Apply the Addition Rule: \(P(A or B) = P(A) + P(B) - P(A and B)\). Replacing the given values we get \(P(A or B) = .28 + .39 - .08\)
03

Apply the Addition Rule for P(A or B) for second scenario

Given \(P(A)=.41, P(B)=.27\), and \(P(A and B)=.19\). Apply the Addition Rule: \(P(A or B) = P(A) + P(B) - P(A and B)\). Replacing the given values we get \(P(A or B) = .41 + .27 - .19\)
04

Evaluate the Expressions

Now the final step is to simplify the expressions from steps 2 and 3. For the first scenario we get: \(P(A or B) = .28 + .39 - .08 = .59\). For the second scenario we get: \(P(A or B) = .41 + .27 - .19 = .49\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability of A or B
The probability of either event A or event B occurring is an important concept in probability theory. It is represented as \( P(A \text{ or } B) \). This determines the likelihood of at least one of these events happening. To calculate this, we use the Addition Rule for probability. The rule is especially helpful when dealing with overlapping events where some outcomes can satisfy both events A and B simultaneously. The formula for this is:
  • \( P(A \text{ or } B) = P(A) + P(B) - P(A \text{ and } B) \)
This equation accounts for the total possibilities of either event occurring, and then subtracts the probability of both events happening at the same time, so it isn't counted twice. By using this rule, you'll get an accurate result without overestimating the probability of A or B.
Intersection of Events
An intersection of events, denoted as \( P(A \text{ and } B) \), is a critical concept in understanding probabilities involving multiple events. It refers to the probability that both event A and event B occur at the same time. To visualize this, imagine the overlap portion in a Venn diagram where circles representing A and B intersect.Understanding the intersection helps in calculating the combined probabilities using the Addition Rule. Typically, when you calculate the intersection of two events, you are dealing with dependent or mutually non-exclusive events because they can happen simultaneously. The intersection probability is essential for avoiding double-counting outcomes when determining \( P(A \text{ or } B) \). Always remember:
  • If the events are mutually exclusive (cannot occur together), \( P(A \text{ and } B) = 0 \).
  • If events can occur together, \( P(A \text{ and } B) > 0 \).
Event Probability Calculation
Calculating event probabilities involves breaking down the components of complex scenarios to determine the chance of a specific outcome or combination of outcomes. When multiple probabilities are given, such as \( P(A), P(B) \), and \( P(A \text{ and } B) \), it's important to understand how these relate to one another.To apply the Addition Rule, gather the following data:
  • Probability of event A: \( P(A) \)
  • Probability of event B: \( P(B) \)
  • Probability of both events: \( P(A \text{ and } B) \)
Substitute these into the Addition Rule formula to find the combined probability. Solving this requires simple arithmetic but it’s crucial to remember not to overlook double-counting intersections. For the exercises provided:
  • First scenario: \( P(A \text{ or } B) = .28 + .39 - .08 = .59 \)
  • Second scenario: \( P(A \text{ or } B) = .41 + .27 - .19 = .49 \)
Being thorough in calculating these values ensures accuracy in predicting the likelihood of events, which is a fundamental skill in probability and statistics.

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Most popular questions from this chapter

A thief has stolen Roger's automatic teller machine (ATM) card. The card has a four-digit personal identification number (PIN). The thief knows that the first two digits are 3 and 5 , but he does not know the last two digits. Thus, the PIN could be any number from 3500 to \(3599 .\) To protect the customer, the automatic teller machine will not allow more than three unsuccessful attempts to enter the PIN. After the third wrong PIN, the machine keeps the card and allows no further attempts. a. What is the probability that the thief will find the correct PIN within three tries? (Assume that the thief will not try the same wrong PIN twice.) b. If the thief knew that the first two digits were 3 and 5 and that the third digit was either 1 or 7 , what is the probability of the thief guessing the correct PIN in three attempts?

Explain the meaning of the intersection of two events. Give one example.

Powerball is a game of chance that has generated intense interest because of its large jackpots. To play this game, a player selects five different numbers from 1 through 59, and then picks a Powerball number from 1 through \(39 .\) The lottery organization randomly draws 5 different white balls from 59 balls numbered 1 through 59 , and then randomly picks a Powerball number from 1 through \(39 .\) Note that it is possible for the Powerball number to be the same as one of the first five numbers. a. If a player's first five numbers match the numbers on the five white balls drawn by the lottery organization and the player's Powerball number matches the Powerball number drawn by the lottery organization, the player wins the jackpot. Find the probability that a player who buys one ticket will win the jackpot. (Note that the order in which the five white balls are drawn is unimportant.) b. If a player's first five numbers match the numbers on the five white balls drawn by the lottery organization, the player wins about \(\$ 200,000\). Find the probability that a player who buys one ticket will win this prize.

According to the U.S. Census Bureau's most recent data on the marital status of the 242 million Americans aged 15 years and older, \(124.2\) million are currently married and \(74.5\) million have never been married. If one person from these 242 million persons is selected at random, find the probability that this person is currently married or has never been married. Explain why this probability is not equal to \(1.0\).

Given that \(P(A \mid B)=.44\) and \(P(A\) and \(B)=.33\), find \(P(B)\).

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