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A researcher took a sample of 25 electronics companies and found the following relationship between \(x\) and \(y\), where \(x\) is the amount of money (in millions of dollars) spent on advertising by a company in 2011 and \(y\) represents the total gross sales (in millions of dollars) of that company for 2011 . $$ \hat{y}=3.6+11.75 x $$ a. An electronics company spent $$\$ 2$$ million on advertising in 2011 . What are its expected gross sales for 2011 ? b. Suppose four electronics companies spent $$\$ 2$$ million each on advertising in \(2011 .\) Do you expect these four companies to have the same actual gross sales for 2011 ? Explain. c. Is the relationship between \(x\) and \(y\) exact or nonexact?

Short Answer

Expert verified
a. The expected gross sales for a company that spent $2 million on advertising in 2011 is approximately $27.1 million. b. No, the four electronics companies that each spent $2 million on advertising in 2011 are not expected to have the same actual gross sales. The given equation is statistical and so it can only provide an estimate of gross sales, but actual results can vary due to other factors. c. The relationship between \(x\) and \(y\) according to the given equation is non-exact.

Step by step solution

01

Predicting Sales based on Advertising Spend

The equation provided in the exercise, \(\hat{y} = 3.6 + 11.75x\), gives an estimate of the gross sales \(y\) for a given amount of advertising spend \(x\). To find the expected gross sales of a company that spent $2 million on advertising, substitute \(x = 2\) into the equation: \(\hat{y} = 3.6 + 11.75 \times 2\).
02

Understanding Sales Outcomes for Multiple Companies

The equation only provides an estimate of the gross sales for a company based on the amount it spent on advertising. Because it is an estimate, other factors not included in this equation can influence a company's gross sales. Therefore, it is entirely possible for four companies spending the same amount on advertising to have different gross sales amounts.
03

Determining the Exactness of the Relationship

The relationship between advertising spend \(x\) and predicted gross sales \(\hat{y}\) in this equation is nonexact, also termed a statistical relationship. This is because it is based on a sample of data and may not represent all companies. Furthermore, many factors can influence gross sales beyond just advertising spend, such as market conditions, product quality, and business strategy.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Predictive Modeling
Predictive modeling is a statistical technique used to predict future outcomes based on historical data. In the context of our exercise with electronics companies, the predictive model in question is a linear regression.

This model uses the formula \[\hat{y} = 3.6 + 11.75x\]where \(x\) represents the advertising spend. The coefficient 11.75 suggests how much a company's sales are expected to increase for each additional million dollars spent on advertising. Predictive modeling helps businesses make informed decisions by estimating outcomes like sales based on quantifiable inputs, like advertising spend. While exceptionally useful, keep in mind that these models are based on patterns observed in data and cannot account for every possible variable.

The scenario given—calculating expected gross sales—demonstrates how predictive modeling aids in business forecasting. By plugging \(x = 2\) into the formula, we obtain \(\hat{y} = 3.6 + 11.75 \times 2 = 27.1\). Thus, if a company spends \(2 million on advertising, its expected gross sales would be \)27.1 million.
Statistical Estimation
Statistical estimation involves using sample data to infer or estimate a population parameter. In the exercise, the relationship provided between advertising spend and sales is an example of statistical estimation. Although the equation \(\hat{y} = 3.6 + 11.75x\) is derived from a sample of 25 companies, it estimates the potential sales for the broader market.

This process often involves coefficients, such as 3.6 and 11.75, which are derived using techniques like least squares to minimize error and improve the accuracy of predictions. The intercept 3.6 represents the baseline level of sales, presuming no advertising. The slope 11.75 indicates the estimated increase in sales per million dollars in advertising.

Remember, estimates are not exact but provide a best guess based on available information. Factors not included in the original sample can lead to different actual outcomes, explaining why identical advertising investments might yield varying results among companies.
Correlation Analysis
Correlation analysis examines the strength and direction of a relationship between two variables. In linear regression models, such as in our exercise, correlation analysis helps understand how closely advertising spend (\(x\)) and gross sales (\(y\)) are related.

While the equation allows us to predict expected sales, the relationship itself is termed nonexact or statistical. This is because it doesn’t imply a perfect correlation, partly due to the existence of other factors affecting sales, like market competition or economic conditions. Nonexact relations are typical in real-world scenarios, as there are always various unaccounted influences.

In summary, even though we can use the model to estimate sales based on advertising, correlation analysis emphasizes that the relationship is an approximation. It reminds us that we shouldn’t expect precisely the same outcome for every company investing the same advertising amount. Thus, correlation analysis is crucial to realizing the limits and capabilities of predictive models.

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Most popular questions from this chapter

Construct a \(99 \%\) confidence interval for the mean value of \(y\) and a \(99 \%\) prediction interval for the predicted value of \(y\) for the following. a. \(\hat{y}=3.25+.80 x\) for \(x=15\) given \(s_{e}=.954, \bar{x}=18.52, \mathrm{SS}_{x x}=144.65\), and \(n=10\) b. \(\hat{y}=-27+7.67 x\) for \(x=12\) given \(s_{e}=2.46, \bar{x}=13.43, \mathrm{SS}_{x x}=369.77\), and \(n=10\)

Explain the difference between exact and nonexact relationships between two variables. Give one example of each.

The following table contains information on the amount of time that each of 12 students spends each day (on average) on social networks (Facebook, Twitter, etc.) and the Internet for social or entertainment purposes and his or her grade point average (GPA). $$ \begin{array}{l|rrrrrrrrrrrr} \hline \text { Time (hours per day) } & 4.4 & 6.2 & 4.2 & 1.6 & 4.7 & 5.4 & 1.3 & 2.1 & 6.1 & 3.3 & 4.4 & 3.5 \\ \hline \text { GPA } & 3.22 & 2.21 & 3.13 & 3.69 & 2.7 & 2.2 & 3.69 & 3.25 & 2.66 & 2.89 & 2.71 & 3.36 \\ \hline \end{array} $$a. Construct a scatter diagram for these data. Does the scatter diagram exhibit a linear relationship between grade point average and time spent on social networks and the Internet? b. Find the predictive regression line of GPA on time. c. Give a brief interpretation of the values of \(a\) and \(b\) calculated in part b. d. Plot the predictive regression line on the scatter diagram of part a, and show the errors by drawing vertical lines between scatter points and the predictive regression line. e. Calculate the predicted GPA for a college student who spends \(3.8\) hours per day on social networks and the Internet for social or entertainment purposes. f. Calculate the predicted GPA for a college student who spends 16 hours per day on social networks and the Internet for social or entertainment purposes. Comment on this finding.

A population data set produced the following information. $$ N=460, \quad \Sigma x=3920, \quad \Sigma y=2650, \quad \Sigma x y=26,570, \quad \sum x^{2}=48,530 $$ Find the population regression line.

The following table lists the midterm and final exam scores for seven students in a statistics class. $$ \begin{array}{l|ccccccc} \hline \text { Midterm score } & 79 & 95 & 81 & 66 & 87 & 94 & 59 \\ \hline \text { Final exam score } & 85 & 97 & 78 & 76 & 94 & 84 & 67 \\ \hline \end{array} $$ a. Do you expect the midterm and final exam scores to be positively or negatively related? b. Plot a scatter diagram. By looking at the scatter diagram, do you expect the correlation coefficient between these two variables to be close to zero, 1, or \(-1\) ? c. Find the correlation coefficient. Is the value of \(r\) consistent with what you expected in parts a and \(\mathrm{b}\) ? d. Using a \(1 \%\) significance level, test whether the linear correlation coefficient is positive.

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