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91Ó°ÊÓ

A population data set produced the following information. $$ N=250, \quad \Sigma x=9880, \quad \Sigma y=1456, \quad \Sigma x y=85,080, \quad \Sigma x^{2}=485,870 $$ Find the population regression line.

Short Answer

Expert verified
The regression line is given by \(y = \beta_{0} + \beta_{1}x\), where \(\beta_{0}\) and \(\beta_{1}\) are the values we computed.

Step by step solution

01

Calculate the slope, \(\beta_{1}\)

Substitute the given values into the formula to get \(\beta_{1} = \frac{250*85080 - 9880*1456}{250*485870 - 9880^2}\).
02

Simplify and Compute \(\beta_{1}\)

Perform the necessary subtraction and division to get the value of \(\beta_{1}\).
03

Calculate the intercept, \(\beta_{0}\)

Substitute the given values and the value we got for \(\beta_{1}\) in to the formula for \(\beta_{0}\): \(\beta_{0} = \frac{1456}{250} - \beta_{1} * \frac{9880}{250}\).
04

Simplify and Compute \(\beta_{0}\)

Perform the necessary subtraction and multiplication to get the value of \(\beta_{0}\).
05

Write down the regression line

Now that we found both \(\beta_{0}\) and \(\beta_{1}\), write down the regression line as \(y = \beta_{0} + \beta_{1}x.\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Slope Calculation in Population Regression
The slope in a population regression line represents the rate at which the dependent variable changes in relation to the independent variable. It essentially tells you how much "y" changes for every one-unit change in "x."
In the context of regression analysis, calculating the slope, denoted \( \beta_{1} \), involves using specific formulas that consider the population data available.
In step 1 of the solution provided, the slope formula used is:
  • \( \beta_{1} = \frac{N \cdot \Sigma xy - \Sigma x \cdot \Sigma y}{N \cdot \Sigma x^2 - (\Sigma x)^2} \)
This formula helps us understand the relationship between the variables in terms of their multiplication and summation across the dataset.
By substituting the given values in the formula, simplify and perform calculations for a precise value of the slope \( \beta_{1} \).
This slope is a crucial component of the regression line, guiding how steep or flat the line will be.
Deciphering Intercept Calculation in Regression Analysis
The intercept, represented as \( \beta_{0} \), is also critical in determining the regression line. This value captures where the regression line crosses the y-axis, giving us the starting point of the regression line.
In simpler terms, it's the value of "y" when "x" is zero.
The intercept calculation is slightly different from slope calculation since it involves both the mean of "y" and adjustments based on the slope.
The formula for calculating the intercept is:
  • \( \beta_{0} = \frac{\Sigma y}{N} - \beta_{1} \cdot \frac{\Sigma x}{N} \)
Here, the mean values of "y" and "x" are modified by the slope to find a precise intercept.
This adjustment considers the influence of every data point, thus ensuring our regression line appropriately reflects the dataset.
Once the slope is determined, substituting it and performing basic arithmetic gives you the intercept \( \beta_{0} \).
Essentials of Linear Regression
Linear regression is a statistical method used to model the relationship between two variables by fitting a linear equation to observed data.
It helps in predicting outcomes by detailing how changes in one variable influence the other.
A simple linear regression model assumes one independent variable (x) and one dependent variable (y), and it takes the form:
  • \( y = \beta_{0} + \beta_{1}x \)
Here, \( \beta_{0} \) is the intercept, and \( \beta_{1} \) is the slope of the line.
The strength of this model is in its simplicity, yet it provides valuable insight into the data's structure.
Linear regression makes it possible to understand and quantify relationships, predict outcomes, and test hypotheses regarding population data.
It's crucial, however, to ensure that the relationship between the variables is indeed linear and that other assumptions necessary for regression analysis (such as normal distribution and homoscedasticity) are met.
Insights on Statistical Analysis in Regression
Statistical analysis is the backbone of interpreting and understanding data within regression models. When determining a population regression line, analysis involves carefully evaluating both the slope and intercept.
Beyond calculating these values, statistical analysis in regression seeks to ensure the validity and accuracy of the predictions made by the model.
Key considerations include:
  • The correlation between x and y to determine if a linear relationship is present.
  • Assessing the goodness-of-fit, which tells you how well the regression line approximates the real data points.
  • Calculating residuals, which are the differences between observed values and the values predicted by the model.
These elements help capture how well your model represents the data, and allow adjustments to be made if necessary.
Moreover, statistical tools like R-squared can provide insights into the proportion of variance in the dependent variable that can be explained by the independent variable.
Overall, statistical analysis ensures that the outcomes of regression models are reliable and significant, serving as a guide for drawing meaningful conclusions from population data analysis.

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Most popular questions from this chapter

Construct a \(95 \%\) confidence interval for the mean value of \(y\) and a \(95 \%\) prediction interval for the predicted value of \(y\) for the following. a. \(\hat{y}=13.40+2.58 x\) for \(x=8\) given \(s_{e}=1.29, \bar{x}=11.30, \mathrm{SS}_{x x}=210.45\), and \(n=12\) b. \(\hat{y}=-8.6+3.72 x\) for \(x=24\) given \(s_{e}=1.89, \bar{x}=19.70, \mathrm{SS}_{x x}=315.40\), and \(n=10\)

The following table, reproduced from Exercise \(13.28\), lists the percentages of space for eight magazines that contain advertisements and the prices of these magazines. $$ \begin{array}{l|rrrrrrrr} \hline \text { Percentage containing ads } & 37 & 43 & 58 & 49 & 70 & 28 & 65 & 32 \\ \hline \text { Price }(\$) & 5.50 & 6.95 & 4.95 & 5.75 & 3.95 & 8.25 & 5.50 & 6.75 \\ \hline \end{array} $$ a. Find the standard deviation of errors. b. Compute the coefficient of determination. What percentage of the variation in price is explained by the least squares regression of price on the percentage of magazine space containing ads? What percentage of this variation is not explained?

The following information is obtained for a sample of 16 observations taken from a population. $$ \mathrm{SS}_{x x}=340.700, \quad s_{e}=1.951, \quad \text { and } \quad \hat{y}=12.45+6.32 x $$ a. Make a \(99 \%\) confidence interval for \(B\). b. Using a significance level of .025, can you conclude that \(B\) is positive? c. Using a significance level of .01, can you conclude that \(B\) is different from zero? d. Using a significance level of .02, test whether \(B\) is different from 4.50. (Hint: The null hypothesis here will be \(H_{0}: B=4.50\), and the alternative hypothesis will be \(H_{1}: B \neq 4.50\). Notice that the value of \(B=4.50\) will be used to calculate the value of the test statistic \(t\).)

The following table contains information on the amount of time that each of 12 students spends each day (on average) on social networks (Facebook, Twitter, etc.) and the Internet for social or entertainment purposes and his or her grade point average (GPA). $$ \begin{array}{l|rrrrrrrrrrrr} \hline \text { Time (hours per day) } & 4.4 & 6.2 & 4.2 & 1.6 & 4.7 & 5.4 & 1.3 & 2.1 & 6.1 & 3.3 & 4.4 & 3.5 \\ \hline \text { GPA } & 3.22 & 2.21 & 3.13 & 3.69 & 2.7 & 2.2 & 3.69 & 3.25 & 2.66 & 2.89 & 2.71 & 3.36 \\ \hline \end{array} $$a. Construct a scatter diagram for these data. Does the scatter diagram exhibit a linear relationship between grade point average and time spent on social networks and the Internet? b. Find the predictive regression line of GPA on time. c. Give a brief interpretation of the values of \(a\) and \(b\) calculated in part b. d. Plot the predictive regression line on the scatter diagram of part a, and show the errors by drawing vertical lines between scatter points and the predictive regression line. e. Calculate the predicted GPA for a college student who spends \(3.8\) hours per day on social networks and the Internet for social or entertainment purposes. f. Calculate the predicted GPA for a college student who spends 16 hours per day on social networks and the Internet for social or entertainment purposes. Comment on this finding.

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