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In a random sample of 800 men aged 25 to 35 years, \(24 \%\) said they live with one or both parents. In another sample of 850 women of the same age group, \(18 \%\) said that they live with one or both parents. a. Construct a \(95 \%\) confidence interval for the difference between the proportions of all men and all women aged 25 to 35 years who live with one or both parents. b. Test at a 2\% significance level whether the two population proportions are different. c. Repeat the test of part b using the \(p\) -value approach.

Short Answer

Expert verified
To create a 95% confidence interval for the difference in proportions, calculate the proportions, and apply them in the formula: \(p1 - p2 \pm Z \sqrt{ \frac{p1(1 - p1)}{n1} + \frac{p2(1 - p2)}{n2} }\). For the hypothesis test, formulate \(H0: p1 - p2 = 0\) and \(H1: p1 - p2 \neq 0\). The test statistic Z is calculated using the formula. If the absolute value of Z is more than 2.33, reject \(H0\). Using the p-value approach, reject \(H0\) if the p-value is less than 2%.

Step by step solution

01

Calculate Proportion

First, calculate the proportions of men (\(p1\)) and women (\(p2\)) living with their parents. Given, \(p1 = 24\% = 0.24\) and \(p2 = 18\% = 0.18\). The sample sizes for men (\(n1\)) and women (\(n2\)) are \(n1 = 800\) and \(n2 = 850\) respectively.
02

Confidence Interval Calculation

The 95% confidence interval for the difference between two proportions is given by the formula: \(p1 - p2 \pm Z \sqrt{ \frac{p1(1 - p1)}{n1} + \frac{p2(1 - p2)}{n2} }\). The Z-score for a 95% confidence level is 1.96. Substituting the calculated proportions and sample sizes gives \(0.24 - 0.18 \pm 1.96 \sqrt{ \frac{0.24(1 - 0.24)}{800} + \frac{0.18(1 - 0.18)}{850} }\)
03

Hypothesis Test

For the two-tailed test at a 2% significance level, the null hypothesis is \(H0: p1 - p2 = 0\) (that is, the population proportions are the same for men and women). The alternative hypothesis is \(H1: p1 - p2 \neq 0\) (that is, the proportions are different). The test statistic Z is given by \(Z = \frac{(p1 - p2) - 0}{\sqrt{ \frac{p1(1 - p1)}{n1} + \frac{p2(1 - p2)}{n2} }}\).
04

Accept or Reject Null Hypothesis

If the absolute value of Z is more than the critical value at the 2% level of significance (which is 2.33 for a two-tailed test), reject the null hypothesis. If not, fail to reject the null hypothesis.
05

p-value Approach

The p-value approach involves determining the smallest level of significance (\(\alpha\)) that would lead to rejection of the null hypothesis. The null hypothesis is rejected if the p-value is less than the level of significance (2%). The p-value for the test statistic can be found using standard statistical tables or statistical software based on the Z value calculated in step 3.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Proportions
Proportions are a way to express a part of a whole in terms of percentage or fraction. In the context of our example, proportions help us understand what fraction of men and women, aged 25 to 35, live with one or both parents. The given proportions are 24% for men and 18% for women. These proportions are expressed in decimal form as 0.24 and 0.18 respectively.
Proportions serve as the foundation for statistical comparison because they represent the estimated probability of a given outcome in a population.
  • They allow us to compare different groups, like men and women.
  • Aids in quantifying differences between groups over similar attributes.
  • Helps in estimating the likelihood of an event occurring in different samples.
Understanding proportions is crucial when comparing groups, as we do in this exercise by determining if there is a significant difference between the living situations of men and women.
Hypothesis Testing
Hypothesis testing is a statistical method that allows us to make decisions about data. In our example, we want to determine if the proportion of men and women living with parents is different. To do this, we set up two hypotheses:
The null hypothesis (\(H_0\)): There is no difference in the proportions (\(p_1 - p_2 = 0\)).
The alternative hypothesis (\(H_1\)): The proportions are different (\(p_1 - p_2 eq 0\)).
  • We test the null hypothesis with statistical evidence to decide whether it can be rejected.
  • If evidence strongly contradicts the null hypothesis, we accept the alternative hypothesis.
A significant level is chosen (in this case, 2%), which sets a threshold for deciding when to reject the null hypothesis. This forms the basis for statistical decision-making and helps in understanding group differences in the real world.
p-value
The p-value is a critical component of hypothesis testing. It tells us the probability of observing the test results under the null hypothesis. In our exercise, once we calculate the test statistic (Z-score), we use it to find the p-value.
  • A smaller p-value indicates stronger evidence against the null hypothesis.
  • If the p-value is less than the chosen significance level (2%), we reject the null hypothesis.
  • It quantifies the strength of evidence in favor of the alternative hypothesis.
By using the p-value, we can determine whether the observed differences in proportions are due to random chance or if they are statistically significant. In simpler terms, the p-value helps us gauge how unusual the observed data would be if the null hypothesis were true.
z-score
The z-score is a measure that tells us how many standard deviations an element is from the mean. When comparing proportions, the z-score helps us understand how significant the difference between two proportions is.In this exercise, we calculate the z-score to determine if there is a significant difference between the proportion of men and women living with parents.
  • The formula for the z-score in this context is:\[ Z = \frac{(p_1 - p_2)}{\sqrt{\frac{p_1(1-p_1)}{n_1} + \frac{p_2(1-p_2)}{n_2}}} \]
  • It standardizes the difference into a measure we can use to make statistical inferences.
  • We compare the calculated z-score to critical values from statistical tables to make decisions in hypothesis testing.
A high absolute z-score (greater than the critical value) suggests the difference in proportions is statistically significant, leading us to reject the null hypothesis. The z-score is a key part of understanding statistical significance in hypothesis testing.

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Most popular questions from this chapter

A consumer organization tested two paper shredders, the Piranha and the Crocodile, designed for home use. Each of 10 randomly selected volunteers shredded 100 sheets of paper with the Piranha, and then another sample of 10 randomly selected volunteers each shredded 100 shects with the Crocodile. The Piranha took an average of 203 seconds to shred 100 sheets with a standard deviation of 6 seconds. The Crocodile took an average of 187 seconds to shred 100 sheets with a standard deviation of 5 seconds. Assume that the shredding times for both machines are normally distributed with equal but unknown standard deviations. a. Construct a \(99 \%\) confidence interval for the difference between the two population means. b. Using a \(1 \%\) significance level, can you conclude that the mean time taken by the Piranha to shred 100 sheets is higher than that for the Crocodile? c. What would your decision be in part \(\mathrm{b}\) if the probability of making a Type 1 error were zero? Explain.

The global recession has led more and more people to move in with relatives, which has resulted in a large number of multigenerational households. An October 2011 Pew Research Center poll showed that \(11.5 \%\) of people living in multigenerational households were living below the poverty level, and 14.6\% of people living in other types of households were living below the poverty level (www. pewsocialtrends.org/201 1/10/03/fighting-poverty-in-a-bad- cconomy-americans-move-in-with-relatives/? sre-pre-headline). Suppose that these results were based on samples of 1000 people living in multigenerational households and 2000 people living in other types of households. a. Let \(p_{1}\) be the proportion of all people in multigenerational households who live below the poverty level and \(p_{2}\) be the proportion of all people in other types of households who live below the poverty level. Construct a 98\% confidence interval for \(p_{1}-p_{2}\) - b. Using a \(2.5 \%\) significance level, can you conclude that \(p_{1}\) is less than \(p_{2}\) ? Use the critical-value approach. c. Repeat part b using the \(p\) -value approach.

A sample of 1000 observations taken from the first population gave \(x_{1}=290 .\) Another sample of 1200 observations taken from the second population gave \(x_{2}=396\). a. Find the point estimate of \(p_{1}-p_{2}\) b. Make a \(98 \%\) confidence interval for \(p_{1}-p_{2}\) c. Show the rejection and nonrejection regions on the sampling distribution of \(\hat{p}_{1}-\hat{p}_{2}\) for \(H_{0}=p_{1}=p_{2}\) versus \(H_{1}: p_{1}

Describe the sampling distribution of \(\bar{x}_{1}-\bar{x}_{2}\) for two independent samples when \(\sigma_{1}\) and \(\sigma\), are known and either both sample sizes are large or both populations are normally distributed. What are the mean and standard deviation of this sampling distribution?

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