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For each of the following significance levels, what is the probability of making a Type I error? a. \(\alpha=.10\) b. \(\alpha=.02\) c. \(\alpha=.005\)

Short Answer

Expert verified
The probability of making a Type I error for significance level \( \alpha = .10 \) is 0.10, for \( \alpha = .02 \) it is 0.02, and for \( \alpha = .005 \) it is 0.005.

Step by step solution

01

Understanding Type I Error and Significance Level

A Type I error is the incorrect rejection of a true null hypothesis. The probability of making a Type I error is denoted as \( \alpha \), which is also known as the level of significance. Therefore, the probability of making a Type I error is simply the given significance level.
02

Determine Probability of Making a Type I Error for \( \alpha = .10 \)

Here the significance level \( \alpha = .10 \), so the probability of making a Type I error is 0.10.
03

Determine Probability of Making a Type I Error for \( \alpha = .02 \)

Here the significance level \( \alpha = .02 \), so the probability of making a Type I error is 0.02.
04

Determine Probability of Making a Type I Error for \( \alpha = .005 \)

Here the significance level \( \alpha = .005 \), so the probability of making a Type I error is 0.005.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Significance Level
The significance level is a crucial aspect within hypothesis testing in statistics. It is symbolized by the Greek letter \( \alpha \). This level is basically a threshold set by the researcher to determine when to reject the null hypothesis. Often, you will see significance levels such as 0.05, 0.01, or 0.10 being used in experiments. When you set a significance level, you are actually deciding how much risk of a Type I error is acceptable in your test. In simpler terms, you decide the probability of rejecting a true null hypothesis. For example:
  • \( \alpha = 0.10 \) indicates a 10% chance
  • \( \alpha = 0.02 \) indicates a 2% chance
  • \( \alpha = 0.005 \) indicates a 0.5% chance
The choice of \( \alpha \) depends on how sure you need to be before discarding the null hypothesis. Lower significance levels mean you need stronger evidence to reject the null. This reduces the odds of making a Type I error, but may increase Type II error.
Null Hypothesis
The null hypothesis is the starting assumption in hypothesis testing. It assumes that there is no effect or no difference between groups or variables being tested. Symbolized as \( H_0 \), the null hypothesis provides a baseline that the alternative hypothesis (\( H_a \)) seeks to prove wrong.If you imagine yourself in a courtroom trial, the defendant is considered 'not guilty' until proven otherwise. Similarly, the null hypothesis is presumed 'true' until evidence contradicts it.The test's aim is to collect enough data evidence to either reject or not reject \( H_0 \). In research scenarios:
  • Failing to reject \( H_0 \) means there isn't strong enough evidence against it
  • Rejecting \( H_0 \) indicates strong evidence that supports the alternative hypothesis

  • Setting your significance level helps determine when the data is sufficiently convincing to reject this hypothesis.
Probability of Error
The probability of error pertains to the chances of making incorrect decisions in hypothesis testing. This often refers to Type I and Type II errors.In the context of Type I error, it is the probability of rejecting the true null hypothesis. This is always equal to the significance level \( \alpha \). Thus, if \( \alpha = 0.10 \), then there is a 10% probability of this error occurring.Errors in hypothesis testing:
  • Type I error: Concluding there is an effect when there isn't one
  • Type II error: Missing an effect that exists
Balancing these errors is key. Setting a high \( \alpha \) reduces the Type II error risk (failing to detect a true effect). However, it increases the chance of a Type I error. Selecting the right \( \alpha \) ensures there's an equilibrium between evidence strength and acceptable risk levels.

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Most popular questions from this chapter

According to the American Diabetes Association (www.diabetes.org), \(23.1 \%\) of Americans aged 60 years or older had diabetes in 2007. A recent random sample of 200 Americans aged 60 years or older showed that 52 of them have diabetes. Using a \(5 \%\) significance level, perform a test of hypothesis to determine if the current percentage of Americans aged 60 years or older who have diabetes is higher than that in 2007 . Use both the \(p\) -value and the critical-value approaches.

The president of a university claims that the mean time spent partying by all students at this university is not more than 7 hours per week. A random sample of 40 students taken from this university showed that they spent an average of \(9.50\) hours partying the previous week with a standard deviation of \(2.3\) hours. Test at the \(2.5 \%\) significance level whether the president's claim is true. Explain your conclusion in words.

Consider \(H_{0}: \mu=40\) versus \(H_{1}: \mu>40\) a. A random sample of 64 observations taken from this population produced a sample mean of 43 and a standard deviation of \(5 .\) Using \(\alpha=.025\), would you reject the null hypothesis? b, Another random sample of 64 observations taken from the same population produced a sample mean of 41 and a standard deviation of 7 . Using \(\alpha=.025\), would you reject the null hypothesis?

Records in a three-county area show that in the last few years, Girl Scouts sell an average of \(47.93\) boxes of cookies per year, with a population standard deviation of \(8.45\) boxes per year. Fifty randomly selected Girl Scouts from the region sold an average of \(46.54\) boxes this year. Scout leaders are concerned that the demand for Girl Scout cookies may have decreased. a. Test at the \(10 \%\) significance level whether the average number of boxes of cookies sold by all Girl Scouts in the three-county area is lower than the historical average. b. What will your decision be in part a if the probability of a Type I error is zero? Explain.

An carlier study claimed that U.S. adults spent an average of 114 minutes with their families per day. A recently taken sample of 25 adults from a city showed that they spend an average of 109 minutes per day with their families. The sample standard deviation is 11 minutes. Assume that the times spent by adults with their families have an approximately normal distribution. a. Using the \(1 \%\) significance level, test whether the mean time spent currently by all adults with their families in this city is different from 114 minutes a day. b. Suppose the probability of making a Type I error is zero. Can you make a decision for the test of part a without going through the five steps of hypothesis testing? If yes, what is your decision? Explain.

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