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Alpha Airlines claims that only \(15 \%\) of its flights arrive more than 10 minutes late. Let \(p\) be the proportion of all of Alpha's flights that arrive more than 10 minutes late. Consider the hypothesis test $$ H_{0}: p \leq .15 \text { versus } H_{1}: p>.15 $$ Suppose we take a random sample of 50 flights by Alpha Airlines and agree to reject \(H_{0}\) if 9 or more of them arrive late. Find the significance level for this test.

Short Answer

Expert verified
The significance level is the probability that the proportion \(p\) is greater or equal to our observed proportion \(0.18\) i.e. P(\(p ≥ 0.18\)) when the null hypothesis \(H_{0}: p \leq 0.15\) is true.

Step by step solution

01

Stating the Null Hypothesis ( \(H_{0}\) ) and Alternative Hypothesis ( \(H_{1}\) )

The null hypothesis \(H_{0}: p \leq .15\) suggests that the claim of the airline is true or overly positive, i.e., at most 15% of flights are late. The alternative hypothesis \(H_{1}: p>.15\) implies that more than 15% of flights are late.
02

Calculation of the Test Statistic

We have a sample size \(n = 50\) flights. The test statistic i.e., number of observed flights late is 9. We need to convert this to a proportion by dividing by the total number of flights i.e. \(p̂ = 9/50 = 0.18\).
03

Calculating the Critical Value

The critical value is the value for which if test statistic exceeds this, we reject the null hypothesis. The condition given in the problem is to reject \(H_{0}\) if 9 or more of the flights are late. So we convert this into a proportion by dividing by the total number of flights i.e. \(0.18\) in this case.
04

Determining the Significance Level

The significance level, often denoted by '\(\alpha\)', is the probability of rejecting the null hypothesis when it is indeed true. It corresponds to the critical region for which we reject \(H_{0}\). Thus, the significant level is the probability that the proportion \(p\) is greater or equal to our observed proportion \(0.18\) i.e. P(\(p ≥ 0.18\)) given that the null hypothesis \(H_{0}: p \leq 0.15\) is true. This can be found using the Normal approximation to the Binomial distribution and finding the associated probability for \(0.18\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
The null hypothesis, often abbreviated as \(H_0\), is a fundamental concept in hypothesis testing. It represents a statement or assumption that there is no effect or no difference, and it serves as the starting point for statistical testing. In the context of our exercise, the null hypothesis \(H_0: p \leq 0.15\) implies that Alpha Airlines’ claim is true, or, if not exact, errs on the side of optimism—meaning that no more than 15% of flights arrive more than 10 minutes late.
The null hypothesis is assumed true unless the evidence strongly suggests otherwise. We attempt to gather such evidence through data collection and analysis. If the data significantly deviates from what is stated in the null hypothesis, we might have grounds to consider the alternative hypothesis instead. The purpose of setting up a null hypothesis is to provide a clear criterion for collecting evidence against the baseline assumption (that \(p \leq 0.15\) in this scenario).
Alternative Hypothesis
In contrast to the null hypothesis, the alternative hypothesis, denoted as \(H_1\), proposes what researchers aim to prove. For our scenario, \(H_1: p > 0.15\) suggests that more than 15% of Alpha Airlines' flights are running more than 10 minutes late.
  • The alternative hypothesis is considered 'accepted' if we find sufficient statistical evidence to reject the null hypothesis.
  • This framework helps researchers challenge claims and attempt to establish new assertions or identify changes and effects in data. In hypothesis testing, the outcome hinges significantly on how favorably the accumulated data reflect the alternative hypothesis over the null.
This hypothesis is pivotal because it defines a direction or focus for testing — here, specifically observing whether the delay rate is worse than what the airline claims.
Significance Level
The significance level, denoted by \(\alpha\), is a critical threshold in hypothesis testing that decides the cutoff for rejecting the null hypothesis. It's the probability of making a Type I error — rejecting the null hypothesis when it is actually true.
Typically, a common significance level used is \(0.05\), but this value can vary depending on the specific requirements or traditions in different fields.
  • In our context, identifying the significance level involves understanding how probable it is, given the null hypothesis, to observe a sample proportion as extreme as or more extreme than the observed 0.18.
  • By calculating this, researchers gauge whether the observed data falls into the critical region where \(H_0\) is refuted.
It's crucial because it balances the risk of making erroneous decisions based on sample evidence, ensuring that any conclusions drawn are statistically trustworthy.
Test Statistic
A test statistic is a standardized value used to determine whether to reject the null hypothesis. In hypothesis testing, it's crucial for comparing the observed data with what would be expected under the null hypothesis.
In our example, the test statistic is originally reflected by the number of late flights (9 out of 50), but it's more informative to convert this count into a proportion \(\hat{p} = \frac{9}{50} = 0.18\).
  • It's used to determine how far the actual observations deviate from those expected under \(H_0\).
  • This step provides a tangible basis for decision-making, serving as a primary input for evaluating whether the observed proportion is significantly higher than the hypothesized 15%.
Understanding the role of the test statistic allows researchers to measure and interpret the strength of evidence against the null hypothesis, facilitating actionable conclusions based on empirical data.

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Most popular questions from this chapter

A computer company that recently introduced a new software product claims that the mean time it takes to learn how to use this software is not more than 2 hours for people who are somewhat familiar with computers. A random sample of 12 such persons was selected. The following data give the times taken (in hours) by these persons to learn how to use this software. $$ \begin{array}{llllll} 1.75 & 2.25 & 2.40 & 1.90 & 1.50 & 2.75 \\ 2.15 & 2.25 & 1.80 & 2.20 & 3.25 & 2.60 \end{array} $$ Test at the \(1 \%\) significance level whether the company's claim is true. Assume that the times taken by all persons who are somewhat familiar with computers to learn how to use this software are approximately normally distributed.

Consider \(H_{0}: p=.70\) versus \(H_{1}: p \neq .70 .\) 1\. A random sample of 600 observations produced a sample proportion equal to .68. Using \(\alpha=.01\), would you reject the null hypothesis? b. Another random sample of 600 observations taken from the same population produced a sample proportion equal to .76. Using \(\alpha=.01\), would you reject the null hypothesis?

Records in a three-county area show that in the last few years, Girl Scouts sell an average of \(47.93\) boxes of cookies per year, with a population standard deviation of \(8.45\) boxes per year. Fifty randomly selected Girl Scouts from the region sold an average of \(46.54\) boxes this year. Scout leaders are concerned that the demand for Girl Scout cookies may have decreased. a. Test at the \(10 \%\) significance level whether the average number of boxes of cookies sold by all Girl Scouts in the three-county area is lower than the historical average. b. What will your decision be in part a if the probability of a Type I error is zero? Explain.

A paint manufacturing company claims that the mean drying time for its paints is not longer than 45 minutes. A random sample of 20 gallons of paints selected from the production line of this company showed that the mean drying time for this sample is \(49.50\) minutes with a standard deviation of 3 minutes. Assume that the drying times for these paints have a normal distribution. a. Using the \(1 \%\) significance level, would you conclude that the company's claim is true? b. What is the Type I error in this exercise? Explain in words. What is the probability of making such an error?

The administrative office of a hospital claims that the mean waiting time for patients to get treatment in its emergency ward is 25 minutes. A random sample of 16 patients who received treatment in the emergency ward of this hospital produced a mean waiting time of \(27.5\) minutes with a standard deviation of \(4.8\) minutes. Using the \(1 \%\) significance level, test whether the mean waiting time at the emergency ward is different from 25 minutes. Assume that the waiting times for all patients at this emergency ward have a normal distribution.

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