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According to an estimate, \(11 \%\) of junk mail is thrown out without being opened (Source: www. uoregon.edu/ recycle/events_topics_junkmail_text.htm). Suppose that this percentage is based on a random sample of 1400 pieces of junk mail. a. What is the point estimate of the corresponding population proportion? b. Construct a \(95 \%\) confidence interval for the proportion of all pieces of junk mail that is thrown out without being opened. What is the margin of error for this estimate?

Short Answer

Expert verified
a. The point estimate of the population proportion is 0.11. b. The 95% confidence interval for the proportion of all pieces of junk mail that is thrown out without being opened can be calculated using the formula CI = p ± Z*SE. The exact values of CI will be found after calculating the SE and margin of error from the above steps.

Step by step solution

01

Point Estimate of the Population Proportion

The point estimate of the corresponding population proportion is the given percentage of 11%. This can be represented as a decimal 0.11
02

Finding the Standard Error

The standard error (SE) for a proportion can be found using the formula \(SE = \sqrt {p(1-p)/n}\). Here, p is the sample proportion (0.11 in this case) and n is the sample size (1400 in this case). So, \(SE = \sqrt {0.11 (1-0.11) / 1400} \). You can solve further to find SE.
03

Determining Z-Score

For a 95% confidence interval, the z-score (Z) is approximately 1.96 (this value comes from z-table).
04

Constructing Confidence Interval and Finding Margin of Error

The confidence interval (CI) can now be found using the formula \(CI = p \pm Z*SE\). Substituting in the values from the previous steps will give the required confidence interval. The margin of error is \(Z*SE\). This can be calculated from the same formula.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Proportion
The population proportion is an important concept to grasp when working with statistics. It refers to the fraction of the total population that exhibits a certain characteristic. In the context of our problem, it is the proportion of all junk mail that is thrown out without being opened.

The population proportion is usually represented by the symbol \( p \). Finding this proportion can often be done by examining a sample, just as we have done with the 1400 junk mail pieces. Here, the point estimate for the population proportion is given as \( 0.11 \) or 11%. This means that, based on the sample, roughly 11% of all junk mail is expected to be discarded without being opened.
  • This estimate helps in understanding the behavior of the entire population.
  • It is derived from the data collected in the sample.
  • It serves as the foundation for constructing confidence intervals.
Understanding the population proportion allows researchers to make informed predictions about the population based on a sample.
Standard Error
Standard error is a crucial concept in statistics, especially when estimating population parameters. It measures the variability of a sample statistic, such as the sample proportion, from the true population parameter.

For population proportion, the standard error provides insight into how much the sample proportion \( (\hat{p}) \) could vary from the actual population proportion \( (p) \). It is calculated using the formula: \[SE = \sqrt{\dfrac{p(1-p)}{n}}\]where \( p \) is the sample proportion, and \( n \) is the sample size.
  • The standard error decreases as the sample size increases, providing a more precise estimate.
  • It helps in determining how representative the sample statistics are of the population.
  • It is used to construct confidence intervals and calculate the margin of error.
In this exercise, our calculation would use \( p = 0.11 \) and \( n = 1400 \) to find the standard error. This value plays a significant role in understanding the accuracy of the point estimate.
Margin of Error
The margin of error is a statistical measure that provides a range around the sample estimate within which the true population parameter is expected to lie with a certain level of confidence. It reflects the amount of random sampling error in a survey's results.

To calculate the margin of error (ME), use the formula:\[ME = Z \times SE\]where \( Z \) is the z-score associated with the desired confidence level, and \( SE \) is the standard error. For a 95% confidence interval, the \( Z \) value typically used is 1.96.
  • The margin of error indicates the level of precision of the sample estimate.
  • It provides upper and lower bounds for the confidence interval, offering a broader context for interpretation.
  • It helps communicate the inherent uncertainty in any sample-based estimate of a population parameter.
In this problem, computing the margin of error will allow us to construct a confidence interval around our sample proportion, indicating how close our estimate might be to the true population proportion.
Point Estimate
A point estimate gives us a single value estimate for a population parameter based on sample data. In statistics, such estimates are used to infer characteristics of a population without examining every member.

In the given exercise, the point estimate works to represent the proportion of junk mail that is discarded unopened across the entire population. From the sample, the point estimate is provided as 11%, or \( 0.11 \) in decimal form.
  • Point estimates are simple but provide essential insights into the population being studied.
  • They are often accompanied by measures such as confidence intervals to account for variability.
  • They form the basis for further statistical inference, including hypothesis testing.
While a point estimate gives a precise figure, it's critical to remember it is still just an estimate, subject to the typical limitations of sample data.

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Most popular questions from this chapter

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