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What assumptions must hold true to use the \(t\) distribution to make a confidence interval for \(\mu ?\)

Short Answer

Expert verified
To use the t-distribution to make a confidence interval for μ, three assumptions should hold: normal distribution (or large sample size), data independence, and interval (or higher) level of measurement.

Step by step solution

01

Understand the t-distribution

The t-distribution is a type of probability distribution that is similar to the normal distribution but has thicker tails. It is often used when the sample size is small (usually less than 30) and the population standard deviation is unknown.
02

The Assumptions

Here are the necessary assumptions for using the t-distribution to build a confidence interval for μ: \n\n1. The population from which the sample is drawn is normally distributed, or the sample size is large enough (via central limit theorem).\n\n2. The data values are independent.\n\n3. The scale of measurement is at least interval.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Confidence Interval
A confidence interval provides a range where we expect the true population parameter, like the mean \(\mu\), to lie. It gives us an estimated range derived from sample data. When we talk about confidence, we usually refer to how "sure" we are that the interval we calculated actually contains the population parameter. This is generally expressed as a percentage, such as a 95% confidence interval.

To construct a confidence interval, especially when using the t-distribution, certain conditions or assumptions need to be met:
  • Normality: The data should ideally be drawn from a population that follows a normal distribution.
  • Independence: Each data point must be collected independently of others.
  • Measurement Scale: Data should be measured at least on an interval scale.
These assumptions help ensure the reliability of the interval estimates. If these criteria are not met, the confidence interval may not accurately reflect the true population parameter.
Normal Distribution
Normal distribution, often called the bell curve due to its shape, is a probability distribution that is symmetric about the mean. It describes how the values of a variable are distributed. Most values cluster around a central region, with values tapering off as they go further from the mean.

Key characteristics of a normal distribution include:
  • Symmetric bell-shaped curve.
  • Mean, median, and mode are all equal and located at the center.
  • Standard deviation determines the spread of the curve.
Normal distribution is crucial in statistics, especially because many tests and statistical models assume a normal distribution of the data. This assumption allows for the application of various inferential statistics techniques, including those involving the t-distribution. When dealing with smaller sample sizes, the t-distribution assumes normal distribution in the population to make reliable confidence intervals.
Central Limit Theorem
The central limit theorem (CLT) is a fundamental concept in statistics. It states that the distribution of the sample mean will tend to be normal or nearly normal if your sample size is sufficiently large, regardless of the original distribution of the population.

Here's why the CLT is important:
  • Simplifies Analysis: When the sample size is large, you can often assume a normal distribution, even if the population is not normally distributed.
  • Applies to Various Data Types: The CLT holds true whether you are sampling data that is numerical or categorical, although there are certain nuances regarding variance.
  • Makes Inferencing Possible: Allows us to use probability to make inferences about population parameters, using sample statistics.
The CLT underpins many statistical methodologies, serving as a backbone to the use of the t-distribution for confidence intervals in samples where the sample size is small. That means even if your data doesn't look normal in the population but you have a sufficiently large sample size, you can still reliably estimate the population mean using techniques like the confidence interval.

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Most popular questions from this chapter

Check if the sample size is large enough to use the normal distribution to make a confidence interval for \(p\) for each of the following cases. a. \(n=80\) and \(\hat{p}=.85\) b. \(n=110\) and \(\hat{p}=.98\) c. \(n=35\) and \(\hat{p}=.40\) d. \(n=200\) and \(\hat{p}=.08\)

A sample of 11 observations taken from a normally distributed population produced the following data. \(\begin{array}{lllllllllll}-7.1 & 10.3 & 8.7 & -3.6 & -6.0 & -7.5 & 5.2 & 3.7 & 9.8 & -4.4 & 6.4\end{array}\) a. What is the point estimate of \(\mu\) ? b. Make a \(95 \%\) confidence interval for \(\mu\). c. What is the margin of error of estimate for \(\mu\) in part b?

a. How large a sample should be selected so that the margin of error of estimate for a \(99 \%\) confidence interval for \(p\) is \(.035\) when the value of the sample proportion obtained from a preliminary sample is \(.29\) ? b. Find the most conservative sample size that will produce the margin of error for a \(99 \%\) confidence interval for \(p\) equal to \(.035\).

KidPix Entertainment is in the planning stages of producing a new computer- animated movie for national release, so they need to determine the production time (labor-hours necessary) to produce the movie. The mean production time for a random sample of 14 big-screen computer-animated movies is found to be 53,550 labor-hours. Suppose that the population standard deviation is known to be 7462 labor-hours and the distribution of production times is normal. a. Construct a \(98 \%\) confidence interval for the mean production time to produce a big-screen computer-animated movie. b. Explain why we need to make the confidence interval. Why is it not correct to say that the average production time needed to produce all big-screen computer-animated movies is 53,550 labor-hours?

A hospital administration wants to estimate the mean time spent by patients waiting for treatment at the emergency room. The waiting times (in minutes) recorded for a random sample of 35 such patients are given below. \(\begin{array}{lrrrrrr}30 & 7 & 68 & 76 & 47 & 60 & 51 \\ 64 & 25 & 35 & 29 & 30 & 35 & 62 \\ 96 & 104 & 58 & 32 & 32 & 102 & 27 \\ 45 & 11 & 64 & 62 & 72 & 39 & 92 \\ 84 & 47 & 12 & 33 & 55 & 84 & 36\end{array}\) Construct a \(99 \%\) confidence interval for the corresponding population mean. Use the \(t\) distribution.

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