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When one is attempting to determine the required sample size for estimating a population mean, and the information on the population standard deviation is not available, it may be feasible to take a small preliminary sample and use the sample standard deviation to estimate the required sample size, \(n .\) Suppose that we want to estimate \(\mu\), the mean commuting distance for students at a community college, to within 1 mile with a confidence level of \(95 \%\). A random sample of 20 students yields a standard deviation of \(4.1\) miles. Use this value of the sample standard deviation, \(s\), to estimate the required sample size, \(n\). Assume that the corresponding population has a normal distribution.

Short Answer

Expert verified
The required sample size, when calculated from given information, will provide the number of samples necessary to estimate the mean commuting distance with a given level of confidence and margin of error. The calculated value using the formula would typically be rounded up to the nearest whole number, as you cannot have a fraction of a sample.

Step by step solution

01

Identify the given information

First, we identify the given information from the exercise. We are given the level of confidence (95%), the sample standard deviation (4.1 miles), the desired margin of error (1 mile), and the sample size of the small preliminary sample (20 students).
02

Use standard normal value for the 95% confidence level

We use the standard normal value \(Z_{0.025}\) for a 95% confidence level, which is 1.96. This value is found in a standard normal table with alpha/2 value for a two-tailed test.
03

Apply the formula for required sample size

We apply the formula for the required sample size when the population standard deviation is unknown. The formula is: \(n = (\frac{s \cdot Z_{\alpha/2}}{E})^2\). In this formula, \(s\) is the sample standard deviation, \(Z_{\alpha/2}\) is the value of the standard normal variable for two-tailed test at given confidence level, and \(E\) is the desired margin of error.
04

Calculate the required sample size

Now we substitute our values into the formula: \(n = (\frac{4.1 \cdot 1.96}{1})^2 \). This will give us the estimate for required sample size.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Mean
Understanding the concept of a population mean is crucial when dealing with data analysis. The population mean represents the average value of a particular characteristic across an entire dataset or population. For example, if we're estimating the mean commuting distance for a group of students, the population mean would be the average commuting distance for all students at that community college. The symbol for the population mean is \( \mu \). Often, we can't calculate \( \mu \) because it's impractical to gather data from an entire population. Instead, we approximate the population mean using sample data, which is a smaller, manageable subset of the population.When we use a sample to estimate the population mean, it's essential to ensure that the sample is representative of the population. This helps to achieve a more accurate approximation. By using sample data, statisticians aim to generalize and make inferences about the entire population.
Sample Standard Deviation
Sample standard deviation is a measure of the amount of variability or dispersion in a sample dataset. It tells us how spread out the values in the sample are around the mean.In our exercise, a sample standard deviation (\( s \)) of 4.1 miles was calculated from a preliminary sample of 20 students. This value gives us a sense of how much the commuting distances vary among those students.Calculating the sample standard deviation involves:
  • Finding the mean of the sample.
  • Subtracting the mean from each data point to find the deviation of each point.
  • Squaring these deviations.
  • Averaging the squared deviations by dividing by the number of data points minus one (this is known as Bessel's correction).
  • Taking the square root of this average to find the standard deviation.
Understanding sample standard deviation is important because it plays a crucial role in estimating the sample size needed when exact population parameters are unknown.
Confidence Level
The confidence level is the probability that the value of a parameter falls within a specified range of values. In statistics, it's used to signify how certain we are that our sample accurately reflects the overall population. In our exercise, we use a 95% confidence level. This means that if we were to take 100 different samples and compute a confidence interval for each sample, we would expect about 95 of those intervals to contain the population mean. Key points about confidence levels:
  • A high confidence level means greater certainty but often requires a larger sample size.
  • The choice of confidence level can impact the width of the confidence interval. A higher level means a wider interval.
  • Common confidence levels are 90%, 95%, and 99%.
Choosing the right confidence level depends on how much uncertainty is acceptable in your estimate.
Margin of Error
The margin of error shows the amount of error you are willing to accept in your sample estimate. It's a critical factor in determining how precise your estimate is. In our example, we want the estimate of the mean commuting distance to be within 1 mile. This stipulation defines our margin of error as 1 mile. Understanding the margin of error involves:
  • Realizing it's directly influenced by both the sample standard deviation and the confidence level chosen.
  • Recognizing that reducing the margin of error increases precision but often requires collecting a larger sample.
  • Knowing that the formula for the required sample size reflects the desired margin of error.
In essence, the margin of error tells you the range in which the true population parameter is expected to lie and helps in planning effective sample size strategies.

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Most popular questions from this chapter

A sample of 18 observations taken from a normally distributed population produced the following data. \(\begin{array}{lllllllll}28.4 & 27.3 & 25.5 & 25.5 & 31.1 & 23.0 & 26.3 & 24.6 & 28.4\end{array}\) \(\begin{array}{llllllll}37.2 & 23.9 & 28.7 & 27.9 & 25.1 & 27.2 & 25.3\end{array}\) \(\begin{array}{ll}22.6 & 22.7\end{array}\) a. What is the point estimate of \(\mu\) ? b. Make a \(99 \%\) confidence interval for \(\mu .\) c. What is the margin of error of estimate for \(\mu\) in part b?

Briefly explain the similarities and the differences between the standard normal distribution and the \(t\) distribution.

A gas station attendant would like to estimate \(p\), the proportion of all households that own more than two vehicles. To obtain an estimate, the attendant decides to ask the next 200 gasoline customers how many vehicles their households own. To obtain an estimate of \(p\), the attendant counts the number of customers who say there are more than two vehicles in their households and then divides this number by 200. How would you critique this estimation procedure? Is there anything wrong with this procedure that would result in sampling and/or nonsampling errors? If so, can you suggest a procedure that would reduce this error?

An insurance company selected a sample of 50 auto claims filed with it and investigated those claims carefully. The company found that \(12 \%\) of those claims were fraudulent. a. What is the point estimate of the percentage of all auto claims filed with this company that are fraudulent? b. Make a \(99 \%\) confidence interval for the percentage of all auto claims filed with this company that are fraudulent.

A couple considering the purchase of a new home would like to estimate the average number of cars that go past the location per day. The couple guesses that the number of cars passing this location per day has a population standard deviation of 170 . a. On how many randomly selected days should the number of cars passing the location be observed so that the couple can be \(99 \%\) certain the estimate will be within 100 cars of the true average? b. Suppose the couple finds out that the population standard deviation of the number of cars passing the location per day is not 170 but is actually 272 . If they have already taken a sample of the size computed in part a, what confidence does the couple have that their point estimate is within 100 cars of the true average? c. If the couple has already taken a sample of the size computed in part a and later finds out that the population standard deviation of the number of cars passing the location per day is actually 130 , they can be \(99 \%\) confident their point estimate is within how much of the true average?

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