/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 115 An economist wants to find a \(9... [FREE SOLUTION] | 91Ó°ÊÓ

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An economist wants to find a \(90 \%\) confidence interval for the mean sale price of houses in a state. How large a sample should she select so that the estimate is within \(\$ 3500\) of the population mean? Assume that the standard deviation for the sale prices of all houses in this state is \(\$ 31,500\)

Short Answer

Expert verified
The required sample size, to the nearest whole number, calculated using the above steps will give the economist the necessary sample size in order to estimate the mean sale price with a \$3500 margin of error at a 90% confidence level.

Step by step solution

01

Understand the formula for sample size

The formula to calculate sample size for a given level of confidence and error margin based on a normal distribution is given by: \(n = [Z(\alpha/2) * \sigma / E]^2\). Here, \(n\) is the sample size, \(Z(\alpha/2)\) is the z-score given a confidence level, \(\sigma\) is the population standard deviation, and \(E\) is the margin for error.
02

Calculate the Z-score

The Z-score for a 90% confidence level is 1.645. This value reflects the standard deviations we need to go left and right from the mean in a normal distribution to cover 90% of the data.
03

Substitute Z-score, standard deviation and error margin in the formula and compute sample size

Plug the Z-score (1.645), standard deviation \$31,500 and error margin (\$3500) values into the sample size formula. \(n = (1.645 * 31500 / 3500)^2\).
04

Round up to the nearest integer

When dealing with sample sizes, it must be a whole number. In case the calculated value isn't a whole number, usually we round up to ensure the required confidence level and error margin. So go ahead and round up the obtained value.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Sample Size Calculation
When an economist wants to estimate a population mean, she must determine the appropriate sample size. This is crucial as it impacts both accuracy and confidence in her results. The formula used is\[n = \left(\frac{Z(\alpha/2) \times \sigma}{E}\right)^2\]where:
  • \(n\) is the sample size,
  • \(Z(\alpha/2)\) is the Z-score associated with the confidence level,
  • \(\sigma\) is the standard deviation of the population,
  • \(E\) is the margin of error.
To begin, choose a desired confidence level, like 90%. Calculate the sample size with the non-rounded result and remember to round up. This ensures she's not underestimating the sample size, providing more accurate and reliable estimates of the population mean.
Standard Deviation
Standard deviation (\(\sigma\)) is a measure that indicates the amount of variation or dispersion in a set of values. In this exercise, it's given as $31,500 for the sale prices of houses. This denotes how much individual house prices typically deviate from the average sale price. A larger standard deviation means more spread out data, while a smaller one signifies values that are closer to the mean.

Understanding this helps in interpreting the reliability of the data. In sampling, a higher standard deviation would generally require a larger sample size for precise estimates, to ensure the sample sufficiently represents the diverse population.
Standard deviation also plays a crucial role in calculating the confidence interval, affecting both the width of the interval and the necessary sample size.
Margin of Error
The margin of error (\(E\)) is the range within which the true population parameter is expected to lie. This exercise targets a margin of error of \(\$3500\). The smaller the margin of error, the more precise the estimate—but achieving this often requires a larger sample size.

Selecting an appropriate margin of error involves a trade-off between precision and practicality. A smaller margin means increased data collection and analysis efforts. It is also determined by how critical precision is for the decision or policy formulation based on the data.
In essence, the margin of error helps in defining the "room for error" in your estimates, giving you a buffer around the population mean that accounts for natural sample variability.

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Most popular questions from this chapter

When calculating a confidence interval for the population mean \(\mu\) with a known population standard deviation \(\sigma\), describe the effects of the following two changes on the confidence interval: (1) doubling the sample size, (2) quadrupling (multiplying by 4) the sample size. Give two reasons why this relationship does not hold true if you are calculating a confidence interval for the population mean \(\mu\) with an unknown population standard deviation.

a. How large a sample should be selected so that the margin of error of estimate for a \(98 \%\) confidence interval for \(p\) is \(.045\) when the value of the sample proportion obtained from a preliminary sample is \(.53\) ? b. Find the most conservative sample size that will produce the margin of error for a \(98 \%\) confidence interval for \(p\) equal to \(.045\).

A bank manager wants to know the mean amount of mortgage paid per month by homeowners in an area. A random sample of 120 homeowners selected from this area showed that they pay an average of \(\$ 1575\) per month for their mortgages. The population standard deviation of such mortgages is \(\$ 215\) a. Find a \(97 \%\) confidence interval for the mean amount of mortgage paid per month by all homeowners in this area. b. Suppose the confidence interval obtained in part a is too wide. How can the width of this interval be reduced? Discuss all possible alternatives. Which alternative is the best?

The principal of a large high school is concerned about the amount of time that his students spend on jobs to pay for their cars, to buy clothes, and so on. He would like to estimate the mean number of hours worked per week by these students. He knows that the standard deviation of the times spent per week on such jobs by all students is \(2.5\) hours. What sample size should he choose so that the estimate is within \(.75\) hour of the population mean? The principal wants to use a \(98 \%\) confidence level.

You are working for a supermarket. The manager has asked you to estimate the mean time taken by a cashier to serve customers at this supermarket. Briefly explain how you will conduct this study. Collect data on the time taken by any supermarket cashier to serve 40 customers. Then estimate the population mean. Choose your own confidence level.

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