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Indicate in which of the following cases the central limit theorem will apply to describe the sampling distribution of the sample proportion. a. \(n=20\) and \(p=.45\) b. \(n=75\) and \(p=.22\) c. \(n=350\) and \(p=.01\) d. \(n=200\) and \(p=.022\)

Short Answer

Expert verified
The central limit theorem can be applied for case a and case b, but it cannot be applied to case c and case d due to failure in satisfying both the conditions.

Step by step solution

01

Evaluate Case a

For case a, where \(n=20\) and \(p=.45\), evaluate \(n \cdot p\) and \(n \cdot (1-p)\). So, \(20 \cdot 0.45 = 9\) and \(20 \cdot (1-0.45) = 11\). Since both these values are greater than 5, the central limit theorem can be applied.
02

Evaluate Case b

For case b, where \(n=75\) and \(p=.22\), evaluate \(n \cdot p\) and \(n \cdot (1-p)\). So, \(75 \cdot 0.22 = 16.5\) and \(75 \cdot (1-0.22) = 58.5\). Since both these values are greater than 5, the central limit theorem can be applied.
03

Evaluate Case c

For case c, where \(n=350\) and \(p=.01\), evaluate \(n \cdot p\) and \(n \cdot (1-p)\). So, \(350 \cdot 0.01 = 3.5\) and \(350 \cdot (1-0.01) = 346.5\). Since \(n \cdot p\) is not greater than 5, the central limit theorem cannot be applied.
04

Evaluate Case d

For case d, where \(n=200\) and \(p=.022\), evaluate \(n \cdot p\) and \(n \cdot (1-p)\). So, \(200 \cdot 0.022 = 4.4\) and \(200 \cdot (1-0.022) = 195.6\). Since \(n \cdot p\) is not greater than 5, the central limit theorem cannot be applied.

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