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Consider a large population with \(\mu=90\) and \(\sigma=18\). Assuming \(n / N \leq, 05\), find the mean and standard deviation of the sample mean, \(\bar{x}\), for a sample size of a. 10 b. 35

Short Answer

Expert verified
For a sample size of 10, the mean and standard deviation of the sample mean are 90 and 5.70 respectively. For a sample size of 35, the mean and standard deviation of the sample mean are 90 and 3.04 respectively.

Step by step solution

01

Determine the Sample Mean

The mean (\(\mu\)) of the sample mean (\(\bar{x}\)) is equal to the population mean. So, for both sample sizes of 10 and 35, the sample mean is \(\mu = 90\).
02

Determine the Standard Deviation for a Sample Size of 10

The standard deviation (\(\sigma\)) of the sample mean (\(\bar{x}\)) is calculated by dividing the population standard deviation by the square root of the sample size (n). Hence, for a sample size of 10, \(\sigma = 18 / \sqrt{10} = 5.70\).
03

Determine the Standard Deviation for a Sample Size of 35

Following the formula from the previous step, for a sample size of 35, the standard deviation (\(\sigma\)) is computed as \(\sigma = 18 / \sqrt{35} = 3.04\).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Mean
The population mean, often symbolized by the Greek letter µ, is the average of all data points in a population. It provides a central value which is representative of the entire population. In statistics, knowing the population mean is crucial for making predictions and assessing differences between groups.

For example, in our exercise, the population mean is given as 90. This tells us that if you could catalog every single individual's value in the population, on average, you would get 90.

The population mean acts as a benchmark to compare sample means against and is often used in various statistical analyses and tests. Understanding the population mean can help in interpreting how typical or atypical a sample or an outcome might be.
Standard Deviation
Standard deviation, denoted by the Greek letter σ, measures the amount of variability or dispersion within a set of data points. A lower standard deviation means that the values tend to be close to the mean, while a higher standard deviation means the values are spread out over a wider range.

In our scenario, the population standard deviation is 18. This tells us that individual data points can deviate from the mean by 18 units on average.

Understanding standard deviation is essential for gauging how varied the data points are, which can offer insights into the reliability and predictability of data.
  • High standard deviation: Data is spread out, less predictable.
  • Low standard deviation: Data is clustered closely around the mean, more predictable.
Sample Mean
The sample mean, represented by the symbol \(\bar{x}\), refers to the average of a sample taken from a larger population. When you take a sample from a population and calculate its mean, it serves as an estimate of the population mean.

According to the problem, since the population mean is 90, the sample mean for both sample sizes (10 and 35) is also expected to be 90. This is because, in theory, and especially with large sample sizes, the sample mean approaches the population mean.

The sample mean is particularly useful because it allows us to make inferences about the population without needing to collect data from everyone. It's like a snapshot that can give us information about the bigger picture.
Sample Size
Sample size, symbolized by \(n\), crucially affects the precision of the sample mean and standard deviation of a dataset. It's the number of observations or data points collected in a sample.

A larger sample size generally means a more accurate estimate of the population parameters.

In the given exercise, two different sample sizes are considered: 10 and 35.
  • For a sample size of 10, we calculated the sample standard deviation as \(5.70\) using the formula \(\sigma_{\bar{x}} = \frac{\sigma}{\sqrt{n}}\).
  • At a sample size of 35, this variation reduces to \(3.04\), depicting how larger sample sizes result in a smaller standard deviation of the mean.

Larger sample sizes lead to lower variability in the sample mean estimates, making them more reliable in representing the population.

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Most popular questions from this chapter

Johnson Electronics Corporation makes electric tubes. It is known that the standard deviation of the lives of these tubes is 150 hours. The company's research department takes a sample of 100 such tubes and finds that the mean life of these tubes is 2250 hours. What is the probability that this sample mean is within 25 hours of the mean life of all tubes produced by this company?

As mentioned in Exercise \(7.33\), among college students who hold part-time jobs during the school year, the distribution of the time spent working per weck is approximately normally distributed with a mean of \(20.20\) hours and a standard deviation of \(2.6\) hours. Find the probability that the average time spent working per week for 18 randomly selected college students who hold part-time jobs during the school year is a. not within 1 hour of the population mean b. \(20.0\) to \(20.5\) hours c. at least 22 hours d. no more than 21 hours

A population of \(N=5000\) has \(\sigma=25 .\) In cach of the following cases, which formula will you usc to calculate \(\sigma_{\bar{x}}\) and why? Using the appropriate formula, calculate \(\sigma_{\bar{k}}\) for each of these cases. a. \(n=300\) b. \(n=100\)

A machine at Katz Steel Corporation makes 3 -inch-long nails. The probability distribution of the lengths of these nails is normal with a mean of 3 inches and a standard deviation of \(.1\) inch. The quality control inspector takes a sample of 25 nails once a week and calculates the mean length of these nails. If the mean of this sample is either less than \(2.95\) inches or greater than \(3.05\) inches, the inspector concludes that the machine needs an adjustment. What is the probubility that based on a sample of 25 nails, the inspector will conclude that the machine needs an adjustment?

According to the American Diabetes Association (www.diabetes.org), \(23.1 \%\) of Americans aged 60 years or older had diabetes in 2007 . Assume that this percentage is true for the current population of Americans aged 60 years or older. Let \(\hat{p}\) be the proportion in a random sample of 460 Americans aged 60 years or older who have diabetes. Find the mean and standard deviation of the sampling distribution of \(\hat{p}\), and describe its shape.

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