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According to the records of an electric company serving the Boston area, the mean electricity consumption during winter for all households is 1650 kilowatt-hours per month. Assume that the monthly electric consumptions during winter by all households in this area have a normal distribution with a mean of 1650 kilowatt-hours and a standard deviation of 320 kilowatt-hours. The company sent a notice to Bill Johnson informing him that about \(90 \%\) of the households use less electricity per month than he does. What. is Bill Johnson's monthly electricity consumption?

Short Answer

Expert verified
Bill Johnson's monthly electricity consumption is approximately 2056.2 kilowatt-hours.

Step by step solution

01

Identify the Z-value

First, we must identify the z-value for the 90th percentile. Using the z-table, we can find the z-value associated with an area of 0.9000 under the curve, which is approximately \(1.282\). This comes from 90th percentile or 0.90 probability. Because only 10% of the population will be above this score, we want to know when the cumulative probability is 0.90.
02

Apply the formula

Next, apply the Z-score formula to find out Johnson's electricity consumption. Conceptually, the Z-score represents the number of standard deviations an observation is away from the mean. The formula for the Z-score is:\[Z = \frac{X - \mu}{\sigma}\]Here, X represents the consumption of Bill Johnson (which we're trying to find), while 饾渿 and 饾湈 represent the mean and standard deviation respectively. Rearranging the formula to solve for X gives us:\[X = Z . \sigma + \mu\]
03

Calculation

Finally, we insert the values into the formula to calculate Bill Johnson鈥檚 electricity consumption:\[X = 1.282 . 320 + 1650 \approx 2056.2\] Kilowatt-hours

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Mean and Standard Deviation
In the context of a normal distribution, the mean and standard deviation are crucial concepts to understand. The mean, often denoted as \( \mu \), represents the average value in a set of data. In simpler terms, it's what you might call the 'typical' value. For the given problem about electricity consumption, the mean is 1650 kilowatt-hours, suggesting that on average, households in the Boston area use this amount per month during winter.

The standard deviation, denoted as \( \sigma \), measures how much the values in a data set vary from the mean. In this case, the standard deviation is 320 kilowatt-hours. This implies that a majority of the household electricity consumptions are expected to be within 320 units of the mean (either above or below).

Why is this important? Well, understanding the spread and average of your data helps in making informed predictions about individual data points. For instance, even if most households use around 1650 units, the standard deviation tells us that there is still significant variation around this average, providing insights into the diversity of consumption habits among households.
Z-score
The Z-score is a way of standardizing individual points within a normal distribution. It indicates how far and in what direction, a single data point deviates from the mean, measured in terms of standard deviations. For example, if a household's consumption is exactly at the mean, its Z-score is 0, indicating no deviation.

To compute a Z-score, you can use the formula:\[ Z = \frac{X - \mu}{\sigma} \]

- \( X \) is the value you want to standardize.
- \( \mu \) is the mean of the distribution.
- \( \sigma \) is the standard deviation.

In the problem, Bill Johnson's household is in the 90th percentile of electricity usage, which means only 10% of households use more electricity than he does. Therefore, his Z-score is approximately 1.282, indicating that his consumption is 1.282 standard deviations above the mean. This allows us to precisely understand his consumption level relative to all other households.
Percentiles
Percentiles are a great way to understand how an individual data point relates to the rest of the data in a normal distribution. A percentile indicates the value below which a percentage of data falls. For instance, being in the 90th percentile means a data point is higher than 90% of all other values in the data set.

In our problem about electricity consumption, Bill Johnson's household usage is in the 90th percentile. This shows that about 90% of the other households have lower electricity usage than him. It provides a context to understand where he stands in comparison to the 'average' household. This concept is very useful in various real-world applications, such as determining scores on tests, understanding spending habits, or, as in this problem, consumption patterns.

Understanding percentiles can help make strategic decisions, as they provide perspective not just on individual scores, but on how these scores fit into the larger data distribution, offering a view of both average and extraordinary values within a dataset.

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Most popular questions from this chapter

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