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Let \(x\) be a continuous random variable that is normally distributed with a mean of 25 and a standard deviation of 6 . Find the probability that \(x\) assumes a value a. between 29 and 36 b. between 22 and 35

Short Answer

Expert verified
To find the probabilities required, convert the given x values to z-scores using the formula \(Z=\frac{X-\mu}{\sigma}\), then use the Z-table to find the desired probabilities. The exact answers depend on the specific values in the Z-table.

Step by step solution

01

Normal Distribution Parameters

The given continuous random variable \(x\) follows a normal distribution where the mean \(\mu\) is 25 and the standard deviation \(\sigma\) is 6.
02

Conversion to Standard Normal Distribution

The values from a normal distribution can be standardized and converted to a standard normal distribution using the formula \(Z=\frac{X-\mu}{\sigma}\).
03

Calculate Z-scores for part a

In part a, we are interested in the probability of \(x\) assuming a value between 29 and 36. Find the associated Z-scores by substituting the given X values (29 and 36) in our formula. The calculations will be done as follows: \For 29, it's \(Z1=\frac{29-25}{6}\) and for 36, it's \(Z2=\frac{36-25}{6}\).
04

Lookup Z-table for Probabilities for part a

After calculating the Z-scores (Z1 and Z2) from Step 3, we use the standard normal distribution Z-table to find the associated probabilities. Let's denote the looked up values as \(P1\) and \(P2\) respectively. The probability \(x\) lying between \(29\) and \(36\) (\(P_{29 < x <36}\)) equals \(P2 - P1\).
05

Calculate Z-scores for part b

In part b, we are interested in the probability of \(x\) assuming a value between 22 and 35. Find the associated Z-scores by substituting the given X values (22 and 35) in our formula. The calculations will be done as follows: \For 22, it's \(Z1'=\frac{22-25}{6}\) and for 35, it's \(Z2'=\frac{35-25}{6}\).
06

Lookup Z-table for Probabilities for part b

After calculating the Z-scores (Z1' and Z2') from Step 5, we use the standard normal distribution Z-table to find the associated probabilities. Let's denote the looked up values as \(P1'\) and \(P2'\) respectively. The probability \(x\) lying between \(22\) and \(35\) (\(P_{22 < x <35}\)) equals \(P2' - P1'\).

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