/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 63 According to an October 27, 2006... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

According to an October 27, 2006 article in Newsweek, \(65 \%\) of Americans said that they take expired medicines. Suppose that this result is true of the current population of Americans. Find the probability that the number of Americans in a random sample of 22 who take expired medicines is a. exactly 17 b. none c. exactly 9

Short Answer

Expert verified
The probability that out of a sample of 22 Americans, exactly 17 take expired medicine, none take expired medicine, and exactly 9 take expired medicine can be calculated using the binomial distribution formula. The corresponding probabilities will be calculated in Steps 3, 4 and 5 respectively.

Step by step solution

01

Identify the binomial distribution parameters

The parameters for a binomial distribution are n and p, where n is the number of trials and p is the probability of success. Here, n=22 (the number of Americans in a random sample), p=0.65 (the probability that an American takes expired medicines)
02

Formulate the binomial distribution formula

The formula to calculate the binomial distribution is \[P(k; n, p) = C(n, k) * (p^k) * (1-p)^{n-k}\] where P(k; n, p) is the probability of getting k successes in n trials, C(n, k) is the combination of n items taken k at a time, p is the probability of success, and 1-p is the probability of failure.
03

Calculate the probability for exactly 17 successes

Plug n=22, k=17 and p=0.65 into the formula \[P(17; 22, 0.65) = C(22, 17) * (0.65^{17}) * (0.35^{5})\] Calculate the value to get the probability.
04

Calculate the probability for no success

Next, calculate the probability for no success (none takes expired medicines). Plug n=22, k=0 and p=0.65 into the formula \[P(0; 22, 0.65) = C(22, 0) * (0.65^{0}) * (0.35^{22})\] Calculate the value to get the probability.
05

Calculate the probability for exactly 9 successes

Finally, calculate the probability for exactly 9 successes. Plug n=22, k=9 and p=0.65 into the formula. \[P(9; 22, 0.65) = C(22, 9) * (0.65^{9}) * (0.35^{13})\] Calculate the value to get the probability.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Probability Calculation
Probability calculation is a fundamental concept in statistics that measures the likelihood of an event occurring. In the context of our exercise, we're looking at specific cases within a population sample to see how likely they are.
Probability ranges from 0 to 1, where 0 indicates that an event is impossible and 1 means that it is certain.
  • In practical terms, this means if you calculated a probability of 0.6, there's a 60% chance of the event happening.
  • For calculating specific probabilities within our exercise, we need to use the binomial distribution formula, which we'll discuss in detail next.
Understanding probability is crucial in many fields, like finance, science, and especially in making informed decisions based on data. It helps you assess risk and can improve everything from managing businesses to playing games.
Binomial Probability Formula
The binomial probability formula is pivotal when you deal with experiments that have two possible outcomes, success or failure.
In our exercise, taking expired medicine is a 'success', simply as a term. The formula is expressed as:
\[P(k; n, p) = C(n, k) \cdot (p^k) \cdot (1-p)^{n-k}\]
  • Here, \(n\) is the number of trials (in our exercise, the number of Americans sampled).
  • \(k\) is the number of successes (e.g., the number of people taking expired medicines).
  • \(p\) is the probability of success on a given trial (65% or 0.65).
  • \(1-p\) represents the probability of failure (not taking expired medicine).
Additionally, \(C(n, k)\) is a mathematical function called "combinations", used to find the number of ways to choose \(k\) successes from \(n\) trials. This formula is helpful to calculate how likely specific outcomes are. It factors in the number of ways those outcomes can happen and adjusts for the probability of them occurring. It's a tool that allows us to understand real-world patterns and probabilities using statistical methods.
Random Sample Analysis
Random sample analysis involves selecting a subset from a larger population in such a way that every individual in the larger set has an equal chance of selection.
This process is crucial for ensuring that the sample accurately reflects the broader population, providing reliable statistical insights.
  • In our exercise, we're analyzing a random sample of 22 Americans to infer about the entire population's behavior regarding expired medication consumption.
  • This random selection helps minimize bias, ensuring that the obtained results are representative and can be generalized to the broader population.
Understanding how to take and analyze random samples is essential, as it allows scientists, businesses, and analysts to predict trends, understand behaviors, and make educated forecasts without having to survey every single individual in a population.
This method provides a foundation for accurate, actionable insights based on manageable, smaller datasets.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

According to a March 25,2007 Pittsburgh Post-Gazette article, \(30 \%\) to \(40 \%\) of U.S. taxpayers cheat on their returns. Suppose that \(30 \%\) of all current U.S. taxpayers cheat on their returns. Use the binomial probabilities table (Table I of Appendix C) or technology to find the probability that the number of U.S. taxpayers in a random sample of 14 who cheat on their taxes is a. at least 8 \(\mathrm{b}\), at most 3 c. 3 to 7

GESCO Insurance Company charges a \(\$ 350\) premium per annum for a \(\$ 100,000\) life insurance policy for a 40 -year-old female. The probability that a 40 -year-old female will die within 1 year is \(.002 .\) a. Let \(x\) be a random variable that denotes the gain of the company for next year from.a \(\$ 100,000\) life insurance policy sold to a 40 -year-old female. Write the probability distribution of \(x\) b. Find the mean and standard deviation of the probability distribution of part a. Give a brief interpretation of the value of the mean.

Briefly explain the following. a. A binomial experiment b. A trial c. A binomial random variable

Consider the Uses and Misuses section in this chapter on poker, where we learned how to calculate the probabilities of specific poker hands. Find the probability of being dealt a. three of a kind b. two pairs \(\mathrm{c}\). one pair

According to a 2008 Pew Research Center survey of adult men and women, close to \(70 \%\) of these adults said that men and women possess equal traits for being leaders. Suppose \(70 \%\) of the current population of adults holds this view. a. Using the binomial formula, find the probability that in a sample of 16 adults, the number who will hold this view is \(\begin{array}{ll}\text { i. exactly } 13 & \text { ii. exactly } 16\end{array}\) b. Use the binomial probabilities table (Table I of Appendix C) or technology to find the probability that the number of adults in this sample who will hold this view is i. at least 11 ii. at most 8 iii. 9 to 12

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.