/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 105 Find \(P(A\) or \(B\) ) for the ... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Find \(P(A\) or \(B\) ) for the following. a. \(P(A)=.18, \quad P(B)=.49\), and \(P(A\) and \(B)=.11\) b. \(P(A)=.73, \quad P(B)=.71\), and \(P(A\) and \(B)=.68\)

Short Answer

Expert verified
The results would be 0.56 for (a) and 0.76 for (b).

Step by step solution

01

Apply the appropriate formula

Use the formula \(P(A ∪ B) = P(A) + P(B) - P(A ∩ B)\). This formula is used to find the probability of either event A or event B occurring.
02

Substitute known probabilities (problem a)

Insert \(P(A)=.18\), \(P(B)=.49\), and \(P(A ∩ B)=.11\) into the formula. This gives \(.18+.49-.11\).
03

Perform the calculation (problem a)

Calculate as follows: \(.18+.49-.11\). This gives \(0.56\).
04

Substitute known probabilities (problem b)

Insert \(P(A)=.73\), \(P(B)=.71\), and \(P(A ∩ B)=.68\) into the formula. This gives \(.73+.71-.68\).
05

Perform the calculation (problem b)

Calculate as follows: \(.73+.71-.68\). This gives \(0.76\).

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Union of events
In probability theory, the concept of the union of events refers to the probability that at least one of several events occurs. This is often expressed as "event A or event B." To visualize this, imagine A and B as two sets of possible outcomes. The union (denoted as \(A \cup B\)) includes all outcomes that are in A, in B, or in both. This means that if any of these outcomes happen, the union has occurred.

The union is a fundamental aspect in combining probabilities and is crucial for calculating the likelihood of multiple events occurring. Knowing how to find the probability of the union helps in situations where you want to know the likelihood of either one event, the other event, or both happening.
  • Key point: Union combines the outcomes from both events.
  • Notation often used: \(A \cup B\).
  • Probability of union involves calculating the chances for at least one event happening.
Intersection of events
The intersection of events represents the probability of both events happening at the same time. When we discuss intersection in probability, we use the term "event A and event B." The intersection is depicted mathematically as \(A \cap B\). Think of it as the overlap area where both events share outcomes.

This overlap indicates that both events are simultaneously true, which is crucial when determining the joint probability. The probability of the intersection is often required when events are not mutually exclusive, meaning that they can occur together. Understanding the intersection helps in dissecting when and how two events relate in probability terms.
  • Key point: Intersection highlights the joint occurrence of events.
  • Notation often used: \(A \cap B\).
  • Determining intersection probability is vital for non-mutually exclusive events.
Addition rule of probability
The addition rule of probability is a core rule that helps to find the probability of the union of two events. This rule takes into account the probabilities of both events and subtracts the probability of their intersection to avoid counting it twice. The formula is expressed as: \[ P(A \cup B) = P(A) + P(B) - P(A \cap B) \]This formula is essential when you want to determine the probability that either one or both of two events happen. Let's explore this with an example:
  • Suppose \(P(A) = 0.18\), \(P(B) = 0.49\), and \(P(A \cap B) = 0.11\). Using the addition rule: \(P(A \cup B) = 0.18 + 0.49 - 0.11\), resulting in \(0.56\).
  • Similarly, if \(P(A) = 0.73\), \(P(B) = 0.71\), and \(P(A \cap B) = 0.68\), apply the formula: \(P(A \cup B) = 0.73 + 0.71 - 0.68\), which gives \(0.76\).
This rule is particularly useful for preliminary probability assessments, helping you to simplify complex overlap situations in probabilistic reasoning.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A company has installed a generator to back up the power in case there is a power failure. The probability that there will be a power failure during a snowstorm is \(.30\). The probability that the generator will stop working during a snowstorm is .09. What is the probability that during a snowstorm the company will lose both sources of power? Note that the two sources of power are independent.

Explain the meaning of the union of two events. Give one example.

According to a 2007 America's Families and Living Arrangements Census Bureau survey, \(52.1\) million children lived with both of their parents in the same household, whereas \(21.6\) million lived with at most one parent in the household. Assume that all U.S. children are included in this survey and that this information is true for the current population. If one child is selected at random, what are the two complementary events and their probabilities?

Two thousand randomly selected adults were asked if they think they are financially better off than their parents. The following table gives the two- way classification of the responses based on the education levels of the persons included in the survey and whether they are financially better off, the same as. or worse off than their parents. $$\begin{array}{lccc} \hline & \begin{array}{c} \text { Less Than } \\ \text { High School } \end{array} & \begin{array}{c} \text { High } \\ \text { School } \end{array} & \begin{array}{c} \text { More Than } \\ \text { High School } \end{array} \\ \hline \text { Better off } & 140 & 450 & 420 \\ \text { Same as } & 60 & 250 & 110 \\ \text { Worse off } & 200 & 300 & 70 \\ \hline \end{array}$$ a. Suppose one adult is selected at random from these 2000 adults. Find the following probabilities. i. \(P\) (better off and high school) ii. \(P(\) more than high school and worse off ) b. Find the joint probability of the events "worse off" and "better off." Is this probability zero? Explain why or why not.

Two thousand randomly selected adults were asked if they think they are financially better off than their parents. The following table gives the two- way classification of the responses based on the education levels of the persons included in the survey and whether they are financially better off, the same as. or worse off than their parents. $$\begin{array}{lccc} \hline & \begin{array}{c} \text { Less Than } \\ \text { High School } \end{array} & \begin{array}{c} \text { High } \\ \text { School } \end{array} & \begin{array}{c} \text { More Than } \\ \text { High School } \end{array} \\ \hline \text { Better off } & 140 & 450 & 420 \\ \text { Same as } & 60 & 250 & 110 \\ \text { Worse off } & 200 & 300 & 70 \end{array}$$ Suppose one adult is selected at random from these 2000 adults. Find the following probabilities. a. \(P(\) better off or high school \()\) b. \(P(\) more than high school or worse off \()\) c. \(P\) (better off or worse off)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.