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91Ó°ÊÓ

The following data give the hourly wage rates of eight employees of a company. \(\begin{array}{llllllll}\$ 22 & 22 & 22 & 22 & 22 & 22 & 22 & 22\end{array}\) Calculate the standard deviation. Is its value zero? If yes, why?

Short Answer

Expert verified
Yes, the standard deviation is zero. This is because all of the wage rates are identical; hence there is no spread or variance in the data.

Step by step solution

01

Compute the Mean

The mean (average) of a dataset is computed by adding all of the values together and then dividing by the total number of values. In this case, all values are identical, so the mean is simply \$22.
02

Subtract the Mean and Compute Deviation Scores

To find the deviation score of each value, subtract the mean from each value. Since all the values in the set are the same and equal to the mean, the deviation scores are all zero.
03

Find Squared Deviations

Square each of the deviation scores calculated in the previous step. As all our deviation scores are zero, once squared, they will still yield zero.
04

Compute the Average of Squared Deviations

To find the average of squared deviations (also called variance), add all the squared deviations and divide them by the total number of values (which is eight in this case). Since our squared deviations are all zero, the average is also zero.
05

Compute the Standard Deviation

The standard deviation is the square root of the variance. Hence, taking the square root of zero gives us a standard deviation of zero.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Mean
The concept of a mean is fundamental in statistical analysis. It is often referred to as the average, and it represents the center of a dataset. To compute the mean, sum all data points in your dataset and divide this sum by the total number of data points. In our example, each employee earns an identical hourly wage of $22. Thus, when you add up all the wages and divide by the number of employees, the mean remains $22.
This value tells us that when all wages are perfectly equal, each data point contributes equally to the mean. Therefore, if you alter any single data point while others remain the same, the mean will change to reflect this alteration.
Understanding the mean provides a baseline for further calculations and helps to contextualize the variance and standard deviation.
Exploring Variance
Variance is vital in understanding how much a dataset's values differ from the mean, offering insight into data spread and distribution. To find the variance, you first determine the deviation scores by subtracting the mean from each data value. Then, square each of these deviation scores and compute their average. This result is the variance.
In our given data set, each employee's wage is the same, meaning every deviation score is zero. Consequently, the squared deviations result in zero. Hence, the variance in this dataset is zero, indicating no variability.
  • Zero variance implies that all data points are identical.
  • Higher variance indicates a wider spread of data points around the mean.
Understanding variance is crucial for determining the consistency and reliability of the data.
Essentials of Statistical Analysis
Statistical analysis serves as a framework for collecting, reviewing, and drawing conclusions from data. It enables the examination of data for patterns and consistencies, aiding in decision-making.
Calculating measures like mean, variance, and standard deviation provides essential insights into the data structure and behavior. Here’s why each is important:
  • Mean: Shows the central point of the dataset and is used for comparison.
  • Variance: Reveals the data's variability and disorder from the mean.
  • Standard Deviation: Illustrates the average deviation from the mean, offering a more interpretable measure than variance.
Utilizing these statistical tools, you can better understand and interpret quantitative data, supporting informed analyses and conclusions.
Significance of Deviation Scores
Deviation scores play a crucial role in understanding how each individual data point relates to the mean. They are calculated by subtracting the mean from each data value, indicating how far and in what direction each score deviates from the average.
In the case of the provided wage data, where each value equals the mean of $22, every deviation score results in zero. This outcome demonstrates no variation or distribution about the mean.
  • A deviation score of zero means the value is exactly at the mean.
  • Negative scores show values below the mean, while positive scores indicate above.
This simple calculation is foundational in arriving at both variance and standard deviation. Appreciating deviation scores helps in assessing the reliability and precision of datasets.

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Most popular questions from this chapter

According to an article in the Washington Post ( Washington Post, January 5, 2009), the average employee share of health insurance premiums at large U.S. companies is expected to be \(\$ 3423\) in \(2009 .\) Suppose that the current annual payments by all such employees toward health insurance premiums have a bell-shaped distribution with a mean of \(\$ 3423\) and a standard deviation of \(\$ 520\). Using the empirical rule, find the approximate percentage of employees whose annual payments toward such premiums are between a. \(\$ 1863\) and \(\$ 4983\) b. \(\$ 2903\) and \(\$ 3943\) c. \(\$ 2383\) and \(\$ 4463\)

The following data represent the numbers of tornadoes that touched down during 1950 to 1994 in the 12 states that had the most tornadoes during this period (Storm Prediction Center, 2009). The data for these states are given in the following order: CO, FL, IA, IL, KS, LA, MO, MS, NE, OK, SD, TX. \(\begin{array}{llllllllllll}1113 & 2009 & 1374 & 1137 & 2110 & 1086 & 1166 & 1039 & 1673 & 2300 & 1139 & 5490\end{array}\) a. Calculate the mean and median for these data. b. Identify the outlier in this data set. Drop the outlier and recalculate the mean and median. Which of these two summary measures changes by a larger amount when you drop the outlier? c. Which is the better summary measure for these data, the mean or the median? Explain.

The following data give the prices of seven textbooks randomly selected from a university bookstore. \(\begin{array}{lllllll}\$ 89 & \$ 170 & \$ 104 & \$ 113 & \$ 56 & \$ 161 & \$ 147\end{array}\) a. Find the mean for these data. Calculate the deviations of the data values from the mean. Is the sum of these deviations zero? b. Calculate the range, variance, and standard deviation.

When is the value of the standard deviation for a data set zero? Give one example. Calculate the standard deviation for the example and show that its value is zero.

One disadvantage of the standard deviation as a measure of dispersion is that it is a measure of absolute variability and not of relative variability. Sometimes we may need to compare the variability of two different data sets that have different units of measurement. The coefficient of variation is one such measure. The coefficient of variation, denoted by CV, expresses standard deviation as a percentage of the mean and is computed as follows: For population data: \(\mathrm{CV}=\frac{\sigma}{\mu} \times 100 \%\) For sample data: \(\quad \mathrm{CV}=\frac{s}{\bar{x}} \times 100 \%\) The yearly salaries of all employees who work for a company have a mean of \(\$ 62,350\) and a standard deviation of \(\$ 6820\). The years of experience for the same employees have a mean of 15 years and a standard deviation of 2 years. Is the relative variation in the salaries larger or smaller than that in years of experience for these employees?

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