/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 42 The following data set belongs t... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

The following data set belongs to a sample: \(\begin{array}{llllll}14 & 18 & -1 & 08 & 8 & -16\end{array}\) Calculate the range, variance, and standard deviation.

Short Answer

Expert verified
The range of the dataset is 34, the variance is 90.971, and the standard deviation is 9.536.

Step by step solution

01

Calculate the Range

Firstly, to calculate the range, the highest and lowest numbers in the dataset need to be identified. Here, the highest number is 18 and the lowest number is -16. The range is calculated by subtracting the lowest number from the highest. Hence, the range would be \(18 - (-16) = 34\).
02

Calculate the Variance

To compute the variance, firstly, the mean (average) of the dataset needs to be calculated. The mean is calculated by adding all the values in the dataset and then dividing by the count of numbers in the dataset. The mean of this dataset is \((14 + 18 - 1 + 8 + 8 - 16) / 6 = 5.167\). Then subtract the mean from each number in the dataset and square the result. These squared results should then be averaged. Thus, the variance is \([ (14 - 5.167)^2 + (18 - 5.167)^2 + (-1 - 5.167)^2 + (8 - 5.167)^2 + (8 - 5.167)^2 +(-16 - 5.167)^2] / 6 = 90.971\)
03

Calculate the Standard Deviation

The standard deviation is the square root of the variance. Hence, the standard deviation would be \(\sqrt{90.971} = 9.536\)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding the Range
The range is a simple yet powerful statistical tool that tells us about the spread of a dataset. It measures how much the numbers in a dataset vary by indicating the difference between the largest and smallest values. In the dataset \( \{14, 18, -1, 8, 8, -16\} \), the largest number is 18, and the smallest is -16. To find the range, subtract the smallest number from the largest. Thus,
- **Range Formula:** \( \text{Range} = \text{Largest Number} - \text{Smallest Number} \)
- **Range for this dataset:** \( 18 - (-16) = 34 \).
Understanding the range helps us to quickly grasp how spread out the values in a dataset are, indicating its variability. The larger the range, the more spread out the numbers. Conversely, a smaller range suggests that the numbers are closer to each other.
Diving Into Variance
Variance is a measure that describes how far each number in a dataset is from the mean, indicating its spread. Calculating variance involves several steps, but the result helps us understand the data's overall variability exceedingly well.
- **Step 1: Calculate the Mean** To find the mean of the dataset \( \{14, 18, -1, 8, 8, -16\} \), add all numbers together and divide by the total count: \( \text{Mean} = \frac{14 + 18 + (-1) + 8 + 8 + (-16)}{6} = 5.167 \).
- **Step 2: Compute Each Deviation from the Mean** For each number, subtract the mean and then square the result: - \((14 - 5.167)^2, (18 - 5.167)^2, (-1 - 5.167)^2, (8 - 5.167)^2, (8 - 5.167)^2, (-16 - 5.167)^2\)
- **Step 3: Average the Squared Deviations** Adding these squared values and dividing by the number of observations gives us the variance: \( \text{Variance} = \frac{727.971}{6} = 90.971 \).
Variance gives you a numerical value that highlights how much the dataset does or doesn’t differ from the mean value, offering insight into the dataset's dynamics.
Exploring Standard Deviation
Standard deviation is a pivotal concept in statistics, fundamentally linked to variance. It is the square root of the variance and provides a practical measure of the dataset's dispersion.
- **Why Standard Deviation?** While variance gives us a number in squared units, standard deviation converts that back to the original units of data, making it easier to interpret.
- **Calculation of Standard Deviation** From our previous steps, we know the variance is 90.971. The standard deviation is simply: \( \text{Standard Deviation} = \sqrt{90.971} = 9.536 \).
Standard deviation tells us, on average, how much the data deviates from the mean. A lower standard deviation means the data points are generally close to the mean, while a higher one signifies greater spread. Understanding standard deviation helps in comprehending concepts of data consistency and variability.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The following data set belongs to a population: $$ \begin{array}{ccccccc} 5 & -7 & 2 & 0 & -9 & 1 & 61 \end{array} $$ Calculate the range, variance, and standard deviation.

Refer to the data of Exercise \(3.109\) on the current annual incomes (in thousands of dollars) of the 10 members of the class of 2000 of the Metro Business College who were voted most likely to succeed. \(\begin{array}{llllllllll}59 & 68 & 84 & 78 & 107 & 382 & 56 & 74 & 97 & 60\end{array}\) a. Determine the values of the three quartiles and the interquartile range. Where does the value of 74 fall in relation to these quartiles? b. Calculate the (approximate) value of the 70 th percentile. Give a brief interpretation of this percentile. c. Find the percentile rank of 97 . Give a brief interpretation of this percentile rank.

Seven airline passengers in economy class on the same flight paid an average of \(\$ 361\) per ticket. Because the tickets were purchased at different times and from different sources, the prices varied. The first five passengers paid \(\$ 420, \$ 210, \$ 333, \$ 695\), and \(\$ 485\). The sixth and seventh tickets were purchased by a couple who paid identical fares. What price did each of them pay?

it possible for a (quantitative) data set to have no mean, no median, or no mode? Give an example of a data set for which this summary measure does not exist.

The test scores for a very large statistics class have a bell-shaped distribution with a mean of 70 points. a. If \(16 \%\) of all students in the class scored above 85, what is the standard deviation of the scores? b. If \(95 \%\) of the scores are between 60 and 80, what is the standard deviation?

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.