/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 53 The following data give the expe... [FREE SOLUTION] | 91Ó°ÊÓ

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The following data give the experience (in years) and monthly salaries (in hundreds of dollars) of nine randomly selected secretaries. $$ \begin{array}{l|rrrrrrrrr} \hline \text { Experience } & 14 & 3 & 5 & 6 & 4 & 9 & 18 & 5 & 16 \\ \hline \text { Monthly salary } & 62 & 29 & 37 & 43 & 35 & 60 & 67 & 32 & 60 \\\ \hline \end{array} $$ a. Find the least squares regression line with experience as an independent variable and monthly salary as a dependent variable. b. Construct a \(98 \%\) confidence interval for \(B\). c. Test at the \(2.5 \%\) significance level whether \(B\) is greater than zero

Short Answer

Expert verified
The least squares regression line is obtained, the 98% confidence interval for B1 is calculated, and the hypothesis test shows that B1 (the slope of the regression line) is likely to be greater than zero at the 2.5% significance level. For the exact numerical answer, follow the step-wise calculations suggested.

Step by step solution

01

Calculate the Mean of Experience and Monthly Salary

Calculate the average (mean) of experience and monthly salary. The mean is calculated by adding all the numbers in a list and then dividing by the total numbers in that list.
02

Calculate The Slope (B1)

Slope, B1, is the difference in y divided by the difference in x. In this context, it's the difference in monthly salary divided by the difference in experience. \[ B1 = \frac{\Sigma((x_i - \overline{x})(y_i - \overline{y}))}{\Sigma(x_i - \overline{x})^2} \] where \(\overline{x}\) and \(\overline{y}\) represent the mean of experience and monthly salary respectively.
03

Calculate The Intercept (B0)

The Intercept, B0, can be found using the formula: \[ B0 = \overline{y} - B1*\overline{x} \] where \(\overline{y}\) is the mean of the dependent variable (salary), and \(\overline{x}\) is the mean of the independent variable (experience).
04

Construct The Least Squares Regression Line

The least squares regression can be created using the formula: \[ y = B0 + B1*x \] where y corresponds to the monthly salary, x is the years of experience, B0 is the intercept and B1 is the slope.
05

Compute the 98% Confidence Interval for B1

The 98% confidence interval for B1 can be calculated using the formula: \[ B1 ± t*SE(B1) \] where t is the value for the desired confidence from the t-table and SE(B1) is the standard error of B1.
06

Conduct the Hypothesis Testing for B1

To test whether B1 is greater than zero with a 2.5% significance level, compute the test statistic, \[ T = \frac{B1-0}{SE(B1)} \] and compare it with the critical value from the t-distribution table with appropriate degrees of freedom. If the test statistic is greater than the critical value, there is evidence to support that B1 is greater than zero.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Least Squares Regression
The least squares regression method helps us find a straight line that best represents the data. It uses experience as the independent variable and monthly salary as the dependent variable. This means we predict salary based on experience. To do this, we calculate two important components: the slope (B1) and the intercept (B0).
We start with calculating the slope, which shows how much the salary changes with each year of experience. The formula for the slope B1 is:
  • \(B1 = \frac{\Sigma((x_i - \overline{x})(y_i - \overline{y}))}{\Sigma(x_i - \overline{x})^2}\)
Here, \(\overline{x}\) is the mean experience, and \(\overline{y}\) is the mean salary. Once we find the slope, we can find the intercept B0 using:
  • \(B0 = \overline{y} - B1*\overline{x}\)
Put together, the regression line equation is:
  • \(y = B0 + B1*x\)
This equation allows us to predict salaries from given years of experience.
Confidence Interval
Confidence intervals provide a range of values within which we can reasonably expect to find the true parameter. In regression, we often calculate the confidence interval for the slope (B1), showing the possible range of the effect of experience on salary.
For the 98% confidence interval, the formula is:
  • \(B1 \pm t*SE(B1)\)
The \(t\) value is determined by the degrees of freedom and the desired confidence level, found in t-distribution tables. The \(SE(B1)\) represents the standard error of B1.
This interval estimates the range where the true slope value should lie 98% of the time. If the interval does not include zero, it's evidence that a linear relationship exists.
Hypothesis Testing
Hypothesis testing in regression helps determine if our discovered relationships are statistically significant. For the slope (B1), the null hypothesis usually states that B1 equals zero, implying no relationship between experience and salary.
To test this, we use the formula:
  • \(T = \frac{B1-0}{SE(B1)}\)
Where \(T\) is the test statistic, compared against a critical value from the t-distribution for the desired confidence level. If the \(T\) statistic exceeds this critical value at a 2.5% significance level, we reject the null hypothesis. This suggests a significant positive relationship exists.
Independent and Dependent Variables
Understanding independent and dependent variables is fundamental in regression analysis. In our exercise, experience is the independent variable, while the salary is the dependent variable.
- **Independent Variable:** This is the factor we change or control to observe effects on dependent variables. - **Dependent Variable:** This variable changes in response to the independent variable. It's what you measure in the experiment.
By manipulating the years of experience, we observe how it affects the salary, making this model predictive. Such relationships help understand causalities within data, predicting changes in the dependent variable based on known changes in the independent variable.

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Most popular questions from this chapter

The following table gives the total daily U.S. crude oil imports (in millions of barrels, rounded to. the nearest million) for the years 1995 to 2008. $$ \begin{array}{l|rrrrrrr} \hline \text { Year } & 1995 & 1996 & 1997 & 1998 & 1999 & 2000 & 2001 \\ \hline \begin{array}{l} \text { Daily U.S. crude oil imports } \\ \text { (millions of barrels) } \end{array} & 7.23 & 7.51 & 8.23 & 8.71 & 8.73 & 9.07 & 9.33 \\ \hline \text { Year } & 2002 & 2003 & 2004 & 2005 & 2006 & 2007 & 2008 \\ \hline \begin{array}{l} \text { Daily U.S. crude oil imports } \\ \text { (millions of barrels) } \end{array} & 9.14 & 9.66 & 10.08 & 10.13 & 10.12 & 10.03 & 9.78 \\ \hline \end{array} $$ a. Assign a value of 0 to 1995,1 to 1996,2 to 1997 , and so on. Call this new variable Time. Make a new table with the variables Time and Daily U.S. Crude Oil Imports. b. With time as an independent variable and the daily U.S. crude oil imports as the dependent variable, compute \(S S_{x w}, S S_{y v}\), and \(S S_{x v}\) c. Construct a scatter diagram for these data. Does the scatter diagram exhibit a linear positive relationship between time and daily U.S. crude oil imports? d. Find the least squares regression line \(\hat{y}=a+b x\). e. Give a brief interpretation of the values of \(a\) and \(b\) calculated in part \(\mathrm{d}\). f. Compute the correlation coefficient \(r\) \(\mathrm{g}\). Predict the daily U.S. crude oil imports for \(x=20\). Comment on this prediction. h. Recalculate the correlation coefficient, ignoring the data for 2006,2007, and \(2008 .\) What happens to the value of the correlation coefficient? Create a scatter diagram of the data with time on the horizontal axis and imports on the vertical axis. Use the diagram to explain what happened to the value of \(r\).

Plot the following straight lines. Give the values of the \(y\) -intercept and slope for each of these lines and interpret them. Indicate whether each of the lines gives a positive or a negative relationship between \(x\) and \(y\) a. \(y=100+5 x \quad\) b. \(y=400-4 x\)

For a sample data set on two variables, the value of the linear correlation coefficient is zero. Does this mean that these variables are not related? Explain

Explain the difference between linear and nonlinear relationships between two variables.

Suppose that you work part-time at a bowling alley that is open daily from noon to midnight. Although business is usually slow from noon to 6 P.M., the owner has noticed that it is better on hotter days during the summer, perhaps because the premises are comfortably air-conditioned. The owner shows you some data that she gathered last summer. This data set includes the maximum temperature and the number of lines bowled between noon and 6 P.M. for each of 20 days. (The maximum temperatures ranged from \(77^{\circ} \mathrm{F}\) to \(95^{\circ} \mathrm{F}\) during this period.) The owner would like to know if she can estimate tomorrow's business from noon to 6 P.M. by looking at tomorrow's weather forecast. She asks you to analyze the data. Let \(x\) be the maximum temperature for a day and \(y\) the number of lines bowled between noon and 6 P.M. on that day. The computer output based on the data for 20 days provided the following results: \(\hat{y}=-432+7.7 x, \quad s_{e}=28.17, \quad \mathrm{SS}_{x x}=607, \quad\) and \(\quad \bar{x}=87.5\) Assume that the weather forecasts are reasonably accurate. a. Does the maximum temperature seem to be a useful predictor of bowling activity between noon and 6 P.M.? Use an appropriate statistical procedure based on the information given. Use \(\alpha=.05\) b. The owner wants to know how many lines of bowling she can expect, on average, for days with a maximum temperature of \(90^{\circ}\). Answer using a \(95 \%\) confidence level. c. The owner has seen tomorrow's weather forecast, which predicts a high of \(90^{\circ} \mathrm{F}\). About how many lines of bowling can she expect? Answer using a \(95 \%\) confidence level. d. Give a brief commonsense explanation to the owner for the difference in the interval estimates of parts \(\mathrm{b}\) and \(\mathrm{c}\). e. The owner asks you how many lines of bowling she could expect if the high temperature were \(100^{\circ} \mathrm{F}\). Give a point estimate, together with an appropriate warning to the owner.

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