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91Ó°ÊÓ

The lottery commissioner's office in a state wanted to find if the percentages of men and women who play the lottery often are different. A sample of 500 men taken by the commissioner's office showed that 160 of them play the lottery often. Another sample of 300 women showed that 66 of them play the lottery often. a. What is the point estimate of the difference between the two population proportions? b. Construct a \(99 \%\) confidence interval for the difference between the proportions of all men and all women who play the lottery often. c. Testing at the \(1 \%\) significance level, can you conclude that the proportions of all men and all women who play the lottery often are different?

Short Answer

Expert verified
a) The point estimate of the difference between the two population proportions is 0.10. b) The 99% confidence interval for the difference between the proportions of men and women who play the lottery often is given by \(0.10 \pm 2.576 \sqrt{ \frac{(0.32(0.68))}{500} + \frac{(0.22(0.78))}{300} }\). c) At 1% significance level, we cannot conclude that the proportions of men and women who play the lottery often are significantly different.

Step by step solution

01

Calculate the proportions

Using the given data, first calculate the proportions for men \(p_m\) and women \(p_w\). \(p_m = 160/500 = 0.32\), \(p_w = 66/300 = 0.22\).
02

Compute point estimate

The point estimate for the difference between two proportions is simply the difference between the proportions of the two samples. Therefore, the point estimate \(P\) is \(P = p_m - p_w = 0.32 - 0.22 = 0.10\).
03

Construct 99% Confidence Interval

To find a confidence interval for the difference of the proportions, one uses the formula: \[ \[ P \pm Z \sqrt{ \frac{(p_m(1 - p_m))}{n_m} + \frac{(p_w(1 - p_w))}{n_w} } \] With \(Z = 2.576\) (for 99% confidence), \(n_m = 500\), and \(n_w = 300\), the CI is: \[ \[ 0.10 \pm 2.576 \sqrt{ \frac{(0.32(0.68))}{500} + \frac{(0.22(0.78))}{300} } \] \].
04

Conduct Hypothesis Test

At the 1% significance level (which equates to a Z-score of 2.576), the critical region lies beyond \(-2.576\) and \(+2.576\). When the test statistic (i.e., the point estimate of 0.1) lies within this critical region, we reject the null hypothesis, which in this case is that the proportions are equal. Thus, since \(0.1\) falls outside the critical region, we cannot reject the null hypothesis at a 1% significance level. The proportions are not significantly different.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Population Proportions
Population proportions are an important concept in statistics, particularly when comparing different groups. A population proportion is the ratio of members in a group with a particular characteristic compared to the total number of members in the entire group. In our exercise, we are talking about the proportion of men and women who play the lottery often.

To calculate population proportions, you divide the number of successes (people who fit the characteristic) by the total count. For the men in the study, the proportion was calculated as follows:
  • Number of men who play often = 160
  • Total number of men surveyed = 500
  • Proportion for men, \( p_m = \frac{160}{500} = 0.32 \)
For the women, the calculation was:
  • Number of women who play often = 66
  • Total number of women surveyed = 300
  • Proportion for women, \( p_w = \frac{66}{300} = 0.22 \)
These proportions help us understand the prevalence of the behavior in each group and are crucial for further statistical analysis, like hypothesis testing.
Confidence Interval
A confidence interval provides a range of values that is used to estimate the true difference between two population proportions, with a certain level of confidence. In other words, it gives us an interval where we expect the true difference to lie, with some degree of certainty.

In our exercise, a 99% confidence interval was constructed for the difference between the proportions of men and women who play the lottery often. The formula used was:

\(0.10 \pm 2.576 \sqrt{ \frac{(0.32 \cdot 0.68)}{500} + \frac{(0.22 \cdot 0.78)}{300} }\).

Here's what each part means:
  • \(0.10\) is the point estimate, which is the observed difference between the two proportions.
  • The \(\pm 2.576\) is the Z-score associated with a 99% confidence level, showing how many standard deviations our estimate can deviate from the true value.
  • The term under the square root accounts for the variances of both sample proportions.
This confidence interval helps to determine if the observed difference is statistically significant or if it might be due to sampling variability.
Null Hypothesis
The null hypothesis is a key concept in hypothesis testing. It represents a default position that there's no effect or difference between the populations being studied. In our exercise, the null hypothesis states that the proportions of men and women who play the lottery often are equal.

Mathematically, the null hypothesis can be expressed as:
  • \( H_0: p_m = p_w \)
This hypothesis serves as a starting point for statistical testing. We use sample data to determine whether there is enough evidence to reject this null hypothesis in favor of an alternative hypothesis.

The hypothesis test often involves calculating a test statistic (like the point estimate difference), which then is compared against critical values that decide whether we should reject or not reject the null hypothesis. If we cannot reject the null hypothesis, it implies that any observed difference could be due to random chance.
Significance Level
The significance level, often denoted as \(\alpha\), is the probability of rejecting the null hypothesis when it is actually true. It is a threshold for determining when we should support or reject our initial assumptions and is crucial in hypothesis testing.

In statistical testing, the significance level helps you decide whether a result is statistically significant. Common significance levels are 0.05, 0.01, and 0.10, corresponding to 5%, 1%, and 10% respectively.

For our exercise, a 1% significance level was used. This means:
  • We are willing to accept a 1% risk of concluding there is a difference between proportions when there isn't one.
  • The critical region, or the range of values where we would reject the null hypothesis, is determined based on this \(\alpha\).
  • A 1% significance level corresponds to a Z-score of about 2.576.
In the exercise, the observed difference was not significant at the 1% level because the test statistic did not fall in the critical region. Thus, we could not reject the null hypothesis, indicating the differences in proportions are not statistically significant.

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Most popular questions from this chapter

A study in the July 7,2009 , issue of \(U S A\) TODAY stated that the \(401(\mathrm{k})\) participation rate among U.S. employees of Asian heritage is \(76 \%\), whereas the participation rate among U.S. employees of Hispanic heritage is \(66 \%\). Suppose that these results were based on random samples of 100 U.S. employees from each group. a. Construct a \(95 \%\) confidence interval for the difference between the two population proportions. b. Using the \(5 \%\) significance level, can you conclude that the \(401(\mathrm{k})\) participation rates are different for all U.S. employees of Asian heritage and all U.S. employees of Hispanic heritage? Use the critical- value and \(p\) -value approaches. c. Repeat parts a and b for both sample sizes of 200 instead of 100 . Does your conclusion change in part b?

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Briefly explain the meaning of independent and dependent samples. Give one example of each.

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