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The mean score on a 25-point placement exam in mathematics used for the past two years at a large state university is 14.3. The placement coordinator wishes to test whether the mean score on a revised version of the exam differs from 14.3 . She gives the revised exam to 30 entering freshmen early in the summer; the mean score is 14.6 with standard deviation 2.4 a. Perform the test at the \(10 \%\) level of significance using the critical value approach. b. Compute the observed significance of the test. c. Perform the test at the \(10 \%\) level of significance using the \(p\) -value approach. You need not repeat the first three steps, already done in part (a).

Short Answer

Expert verified
We fail to reject the null hypothesis in both approaches, indicating no significant difference at the 10% level.

Step by step solution

01

Define Hypotheses

For the test, we will define our null hypothesis (\(H_0\)) and alternative hypothesis (\(H_1\)). The null hypothesis states that the mean score of the revised exam is equal to the previous mean score of 14.3, i.e., \(H_0: \mu = 14.3\). The alternative hypothesis states that the mean score is different from 14.3, i.e., \(H_1: \mu eq 14.3\).
02

Determine the Test Statistic

Since we have a sample size of 30 (less than 30), we use a t-test. The test statistic (t) is given by the formula: \( t = \frac{\bar{x} - \mu}{s/\sqrt{n}} \) where \(\bar{x} = 14.6\) is the sample mean, \(\mu = 14.3\) is the population mean, \(s = 2.4\) is the standard deviation, and \(n = 30\) is the sample size. Calculating this value, we get \( t = \frac{14.6 - 14.3}{2.4/\sqrt{30}} \approx 0.683 \).
03

Find the Critical Value

For a two-tailed test at the \(10\%\) significance level and \(n-1 = 29\) degrees of freedom, we find the critical t-value from a t-distribution table. The critical values for \(\alpha/2 = 0.05\) significance level are approximately \(\pm 1.699\).
04

Compare Test Statistic to Critical Value (Part a)

Since the calculated test statistic \(t = 0.683\) is within the range \([-1.699, 1.699]\), we fail to reject the null hypothesis. This means there is not enough evidence to say that the mean score is different from 14.3 at the \(10\%\) significance level.
05

Calculate Observed Significance (p-value) (Part b)

Using a t-distribution table or calculator for \(t = 0.683\) and \(29\) degrees of freedom, we find the p-value. This p-value is approximately \(0.50\).
06

p-value Approach (Part c)

With the p-value of approximately \(0.50\) and the significance level of \(0.10\), we compare them. Since the p-value is greater than \(\alpha = 0.10\), we fail to reject the null hypothesis. There is insufficient evidence to conclude that the mean score differs from 14.3.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

t-test
In statistics, a t-test is a method used to determine if there is a significant difference between the means of two groups. It is particularly useful when the sample size is small and the standard deviation is unknown, which fits the scenario in our exercise. Here, we use the t-test to compare the mean score of a revised exam to a known average from past years. The test requires calculating a test statistic based on the sample data: \( t = \frac{\bar{x} - \mu}{s/\sqrt{n}} \). In this case, \( \bar{x} \) is the sample mean (14.6), \( \mu \) is the population mean (14.3), \( s \) is the standard deviation (2.4), and \( n \) is the sample size (30). This test statistic helps us understand how the observed data compares to what we would expect under the null hypothesis.
critical value approach
The critical value approach is a traditional method used in hypothesis testing. It involves comparing your calculated test statistic to a critical value obtained from statistical tables. To employ this approach, you need to choose a significance level (such as \(10\%\)), and determine whether the test is one-tailed or two-tailed. Then, based on the degrees of freedom (sample size minus one for the t-test), find the critical values. In our problem, with 29 degrees of freedom and a two-tailed test at a \(10\%\) level, the critical t-values are around \(±1.699\). Finally, check if your test statistic lies within the acceptance region, defined by these critical values. If it does, you fail to reject the null hypothesis.
p-value approach
The p-value approach provides another way to perform hypothesis testing. It refers to the probability of observing a test statistic as extreme as, or more extreme than, the value calculated from your data, assuming the null hypothesis is true. A p-value helps quantify the evidence against the null hypothesis. In our exercise, the p-value is approximately 0.50. You compare this to your chosen level of significance (often denoted as \( \alpha \)). Since the p-value is higher than \( \alpha = 0.10 \), we do not have enough evidence to reject the null hypothesis. This approach is favored for its straightforward interpretation and ability to show the strength of evidence.
significance level
The significance level, often denoted by \( \alpha \), is a critical component of hypothesis testing. It represents the probability of rejecting the null hypothesis when it is actually true. In simpler terms, it's the risk you are willing to take for a Type I error—concluding that there is an effect or difference when none exists. In our problem, a \( 10\% \) significance level means you allow a 10% chance of incorrectly rejecting the null hypothesis. This level determines the critical value(s) used in the critical value approach and is a benchmark for comparing your p-value in the p-value approach. Choosing an appropriate significance level is pivotal to balancing the risk of Type I errors with the confidence in your test results.

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Most popular questions from this chapter

A random sample of size 8 drawn from a normal population yielded the following results: \(\bar{x}-280, s=46\). a. Test \(H 0: \mu=250\) vs. Ha:\mu \(>250 @ \alpha=0.05\). b. Estimate the observed significance of the test in part (a) and state a decision based on the \(p\) -value approach to hypothesis testing.

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