/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 7 Perform the indicated test of hy... [FREE SOLUTION] | 91Ó°ÊÓ

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Perform the indicated test of hypotheses, based on the information given. a. Test \(\mathrm{Ho}: \mu=212\) vs. Ha: \(\mu<212 @ \alpha=0.10, \sigma\) unknown, \(n=36, x-211.2, \mathrm{~s}=2.2\) b. Test \(H_{0}: \mu=-18\) vs. Ha: \(\mu>-18\) \(@ \alpha=0.05, \sigma=3.3, n=44, x-=-17.2, s=3.1\) c. Test \(H_{0}: \mu=24\) vs. Ha: \(\mu \neq 24 @ \alpha=0.02, \sigma\) unknown, \(n=50, x-=22.8, s=1.9\)

Short Answer

Expert verified
a. Reject \( H_0 \); b. Do not reject \( H_0 \); c. Reject \( H_0 \).

Step by step solution

01

Formulate Hypotheses for Part a

The null hypothesis (\( H_0 \)) is \( \mu = 212 \), and the alternative hypothesis (\( H_a \)) is \( \mu < 212 \). This is a left-tailed test at \( \alpha = 0.10 \).
02

Calculate Test Statistic for Part a

Since the population standard deviation is unknown, we use the t-test statistic. The test statistic is calculated as:\[t = \frac{\bar{x} - \mu_0}{s / \sqrt{n}} = \frac{211.2 - 212}{2.2 / \sqrt{36}} = \frac{-0.8}{0.3667} \approx -2.18\]
03

Determine Critical Value and Decision for Part a

Using a t-distribution table with \( df = n - 1 = 35 \), and \( \alpha = 0.10 \), find the critical t-value. The critical value \( t_{0.10, 35} \) is approximately \( -1.304 \). Since the calculated t-value \( -2.18 \) is less than \( -1.304 \), reject \( H_0 \).
04

Formulate Hypotheses for Part b

The null hypothesis (\( H_0 \)) is \( \mu = -18 \) and the alternative hypothesis (\( H_a \)) is \( \mu > -18 \). This is a right-tailed test at \( \alpha = 0.05 \).
05

Calculate Test Statistic for Part b

Use the z-test since the population standard deviation is known. The test statistic is calculated as:\[z = \frac{\bar{x} - \mu_0}{\sigma / \sqrt{n}} = \frac{-17.2 - (-18)}{3.3 / \sqrt{44}} = \frac{0.8}{0.497} \approx 1.61\]
06

Determine Critical Value and Decision for Part b

For a right-tailed test at \( \alpha = 0.05 \), the critical z-value is \( 1.645 \). Since the calculated z-value \( 1.61 \) is less than \( 1.645 \), do not reject \( H_0 \).
07

Formulate Hypotheses for Part c

The null hypothesis (\( H_0 \)) is \( \mu = 24 \) and the alternative hypothesis (\( H_a \)) is \( \mu eq 24 \). This is a two-tailed test at \( \alpha = 0.02 \).
08

Calculate Test Statistic for Part c

Since the population standard deviation is unknown, use a t-test. The test statistic is:\[t = \frac{\bar{x} - \mu_0}{s / \sqrt{n}} = \frac{22.8 - 24}{1.9 / \sqrt{50}} = \frac{-1.2}{0.2687} \approx -4.47\]
09

Determine Critical Values and Decision for Part c

Using a t-distribution table with \( df = n - 1 = 49 \), and \( \alpha/2 = 0.01 \) for a two-tailed test, find the critical t-values \( \pm t_{0.01, 49} \), which are approximately \( \pm 2.682 \). Since the calculated t-value, \( -4.47 \), is outside the interval \( (-2.682, 2.682) \), reject \( H_0 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

t-test
The t-test is a type of hypothesis test used when the population standard deviation is unknown and the sample size is relatively small. It helps determine whether there is a significant difference between a sample mean and a known value (often a population mean). There are different types of t-tests, including:
  • One-sample t-test: Compares the sample mean to a known value or theoretical expectation.
  • Independent t-test: Compares the means of two independent groups.
  • Paired t-test: Compares means from the same group at different times or under two different conditions.
In our exercise, the t-test is needed because the population standard deviation, denoted by \( \sigma \), is unknown for parts a and c. The formula for the t-test statistic is:\[t = \frac{\bar{x} - \mu_0}{s / \sqrt{n}}\]where \( \bar{x} \) is the sample mean, \( \mu_0 \) is the population mean under the null hypothesis, \( s \) is the sample standard deviation, and \( n \) is the sample size. The goal is to compare this value against a critical value to decide whether to reject the null hypothesis.
z-test
The z-test is another method of hypothesis testing, typically used when the population standard deviation is known and the sample size is larger. It assesses if a sample mean significantly differs from a hypothesized population mean. The types are similar to those of the t-tests, such as one-sample z-test and two-sample z-test.In part b of our exercise, the z-test is appropriate because the population standard deviation, \( \sigma \), is given. The z-test statistic formula is:\[z = \frac{\bar{x} - \mu_0}{\sigma / \sqrt{n}}\]where \( \bar{x} \) is the sample mean, \( \mu_0 \) is the population mean under the null hypothesis, \( \sigma \) is the population standard deviation, and \( n \) is the sample size. The calculated z-value is then compared to a critical z-value obtained from the standard normal distribution to make a decision regarding the null hypothesis.
critical value
The critical value is a point on the test statistic distribution that is compared against the calculated test statistic to decide whether to reject the null hypothesis. It depends on the significance level \( \alpha \) and the nature of the test (one-tailed or two-tailed).
  • One-tailed test: Uses one critical value in one direction, either left or right, based on the hypothesis.
  • Two-tailed test: Has two critical values, one on each tail, allowing for deviations in both directions from the hypothesized mean.
For the t-tests in parts a and c of our exercise, critical t-values are used, which depend on the degrees of freedom (\( df = n - 1 \)). In part a, the critical t-value was approximately \( -1.304 \) for a left-tailed test at \( \alpha = 0.10 \). For the z-test in part b, the critical z-value was \( 1.645 \) for a right-tailed test at \( \alpha = 0.05 \). These critical values determine the threshold for rejecting the null hypothesis.
test statistic
The test statistic is a standardized value computed from sample data during a hypothesis test. It quantifies the degree of deviation from the null hypothesis. The kind of test statistic (t or z) depends on what information is known about the population.
  • For a t-test, the test statistic is calculated using the sample standard deviation \( s \) (when \( \sigma \), the population standard deviation, is unknown).
  • For a z-test, the population standard deviation \( \sigma \) is known, and thus, the test statistic is computed with it.
The test statistic aggregates sample data in a way that can be directly compared to a critical value from a statistical distribution. For example, in part a of our exercise, the t-test statistic was approximately \( -2.18 \). By contrast, in part b, the z-test statistic was approximately \( 1.61 \). These values help in determining if the results are statistically significant enough to reject the null hypothesis.

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Most popular questions from this chapter

The recommended daily calorie intake for teenage girls is 2,200 calories/day. A nutritionist at a state university believes the average daily caloric intake of girls in that state to be lower. Test that hypothesis, at the \(5 \%\) level of significance, against the null hypothesis that the population average is 2,200 calories/day using the following sample data: \(n=36, x-2,150, s=203\).

State the null and alternative hypotheses for each of the following situations. (That is, identify the correct number \(\mu_{0}\) and write \(H_{0} \mu=\mu_{0}\) and the appropriate analogous expression for \(H_{a}\).) a. The average time workers spent commuting to work in Verona five years ago was 38.2 minutes. The Verona Chamber of Commerce asserts that the average is less now. b. The mean salary for all men in a certain profession is \(\$ 58,291\). A special interest group thinks that the mean salary for women in the same profession is different. c. The accepted figure for the caffeine content of an 8 -ounce cup of coffee is \(133 \mathrm{mg}\). A dietitian believes that the average for coffee served in a local restaurants is higher. d. The average yield per acre for all types of corn in a recent year was 161.9 bushels. An economist believes that the average yield per acre is different this year. e. An industry association asserts that the average age of all self-described fly fishermen is 42.8 years. A sociologist suspects that it is higher.

Authors of a computer algebra system wish to compare the speed of a new computational algorithm to the currently implemented algorithm. They apply the new algorithm to 50 standard problems; it averages 8.16 seconds with standard deviation 0.17 second. The current algorithm averages 8.21 seconds on such problems. Test, at the \(1 \%\) level of significance, the alternative hypothesis that the new algorithm has a lower average time than the current algorithm.

The average amount of time that visitors spent looking at a retail company's old home page on the world wide web was 23.6 seconds. The company commissions a new home page. On its first day in place the mean time spent at the new page by 7,628 visitors was 23.5 seconds with standard deviation 5.1 seconds. a. Test at the \(5 \%\) level of significance whether the mean visit time for the new page is less than the former mean of 23.6 seconds, using the critical value approach. b. Compute the observed significance of the test. c. Perform the test at the \(5 \%\) level of significance using the \(p\) -value approach. You need not repeat the first three steps, already done in part (a).

Large Data Set 6 records results of a random survey of 200 voters in each of two regions, in which they were asked to express whether they prefer Candidate \(A\) for a U.S. Senate seat or prefer some other candidate. Use the full data set (400 observations) to test the hypothesis that the proportion \(p\) of all voters who prefer Candidate \(A\) exceeds \(0.35 .\) Test at the \(10 \%\) level of significance.

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