/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 1 State the null and alternative h... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

State the null and alternative hypotheses for each of the following situations. (That is, identify the correct number \(\mu_{0}\) and write \(H_{0} \cdot \mu=\mu_{0}\) and the appropriate analogous expression for \(H_{a}\).) a. The average July temperature in a region historically has been \(74.5^{\circ} \mathrm{F}\). Perhaps it is higher now. b. The average weight of a female airline passenger with luggage was 145 pounds ten years ago. The FAA believes it to be higher now. c. The average stipend for doctoral students in a particular discipline at a state university is \(\$ 14,756\). The department chairman believes that the national average is higher. d. The average room rate in hotels in a certain region is \(\$ 82.53 .\) A travel agent believes that the average in a particular resort area is different. e. The average farm size in a predominately rural state was 69.4 acres. The secretary of agriculture of that state asserts that it is less today.

Short Answer

Expert verified
Null and alternative hypotheses are given based on whether the claim is one-tailed or two-tailed.

Step by step solution

01

Define Hypotheses for Part a

For this part, we have the historical average July temperature of \(74.5^{\circ} \mathrm{F}\). We want to determine if the current average is higher, which suggests a one-tailed test.**Null Hypothesis (\(H_0\))**: \( \mu = 74.5 \)**Alternative Hypothesis (\(H_a\))**: \( \mu > 74.5 \)
02

Define Hypotheses for Part b

For this part, the average weight of a female airline passenger with luggage was 145 pounds ten years ago. We want to determine if it's higher now, suggesting another one-tailed test.**Null Hypothesis (\(H_0\))**: \( \mu = 145 \)**Alternative Hypothesis (\(H_a\))**: \( \mu > 145 \)
03

Define Hypotheses for Part c

For this part, the average stipend for doctoral students is \(\$14,756\). The department chairman believes the national average is higher, which again implies a one-tailed test.**Null Hypothesis (\(H_0\))**: \( \mu = 14756 \)**Alternative Hypothesis (\(H_a\))**: \( \mu > 14756 \)
04

Define Hypotheses for Part d

For this part, the average room rate in hotels is \(\$82.53\). The belief is that the average in a particular resort area is different, implying a two-tailed test.**Null Hypothesis (\(H_0\))**: \( \mu = 82.53 \)**Alternative Hypothesis (\(H_a\))**: \( \mu eq 82.53 \)
05

Define Hypotheses for Part e

For this part, the average farm size was 69.4 acres. The assertion is that it is less today, suggesting a one-tailed test.**Null Hypothesis (\(H_0\))**: \( \mu = 69.4 \)**Alternative Hypothesis (\(H_a\))**: \( \mu < 69.4 \)

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Null Hypothesis
In any hypothesis test, the null hypothesis ( H_0 ) serves as the statement we initially assume to be true. It is a 'no effect' or 'status quo' proposition that we attempt to find evidence against. The null hypothesis typically states that there is no change or difference from the known or historical value. For example, when considering a scenario where we check if the current average temperature deviates from the historical 74.5°F, the null hypothesis would assert that the average temperature remains at 74.5°F. This serves as the benchmark against which alternative claims are tested.
  • Stable Assertion: Example scenarios reiterate past data as still valid.
  • Test of Change: It helps to validate assumptions against collected data.
Alternative Hypothesis
The alternative hypothesis ( H_a ) directly contrasts with the null hypothesis. It reflects the statement we want to test and is usually the claim that needs backing up with statistical evidence. The alternative hypothesis introduces a change or a new observation that challenges the status quo expressed in the null hypothesis. In a situation where the company believes the average room rate is different from $82.53, the alternative hypothesis would state that the average rate is not the same as this known value.
  • Expresses Difference or Change: Proposes specifics such as increase, decrease, or not equal to.
  • Requires Evidence: Needs data support to reject the null hypothesis.
One-tailed Test
A one-tailed test evaluates the direction of an effect, checking if a parameter is either greater than or less than a specific value. It moves in one direction. This test is used when we have a specific hypothesis about the direction of an effect. For instance, if we hypothesize that the average weight of passengers is greater than it was ten years ago, a one-tailed test would assess evidence supporting this specific direction of change.
  • Directional Hypothesis: Specifically tests greater-than or less-than conditions.
  • Efficiency: More powerful for detecting an effect in a specified direction.
Common in situations where a precise direction of change is expected, one-tailed tests can offer clearer insights when only one outcome is of interest.
Two-tailed Test
A two-tailed test assesses whether there is any change or difference, without focusing on the supposed direction of that change. It's employed when we want to determine if a value is simply different from a benchmark, whether higher or lower. This type of test is suitable when there are no assumptions about which direction the test will take. For example, if there's doubt about whether the average room rate in a resort area is different from $82.53, a two-tailed test would evaluate evidence for change in both directions.
  • Non-directional Test: Checks for any departure from the null, either high or low.
  • Comprehensive: Effectively captures any form of deviation from expected value.
Two-tailed tests provide a broader check against the null hypothesis, often employed when no exact increase or decrease is assumed.

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

At every setting a high-speed packing machine delivers a product in amounts that vary from container to container with a normal distribution of standard deviation 0.12 ounce. To compare the amount delivered at the current setting to the desired amount 64.1 ounce, a quality inspector randomly selects five containers and measures the contents of each, obtaining sample mean 63.9 ounces and sample standard deviation 0.10 ounce. Test whether the data provide sufficient evidence, at the \(5 \%\) level of significance, to conclude that the mean of all containers at the current setting is less than 64.1 ounces.

One water quality standard for water that is discharged into a particular type of stream or pond is that the average daily water temperature be at most \(18^{\circ} \mathrm{C}\). Six samples taken throughout the day gave the data: $$ 16.821 .519 .112 .818 .020 .7 $$ The sample mean \(x^{\wedge-=18.15}\) exceeds \(18,\) but perhaps this is only sampling error. Determine whether the data provide sufficient evidence, at the \(10 \%\) level of significance, to conclude that the mean temperature for the entire day exceeds \(18^{\circ} \mathrm{C}\).

Pasteurized milk may not have a standardized plate count (SPC) above 20,000 colony-forming bacteria per milliliter (cfu/ml). The mean SPC for five samples was \(21,500 \mathrm{cfu} / \mathrm{ml}\) with sample standard deviation \(750 \mathrm{cfu} / \mathrm{m} 1\). Test the null hypothesis that the mean \(\mathrm{SPC}\) for this milk is 20,000 versus the alternative that it is greater than 20,000 , at the \(10 \%\) level of significance. Assume that the SPC follows a normal distribution.

The recommended daily allowance of iron for females aged \(19-50\) is \(18 \mathrm{mg} /\) day. A careful measurement of the daily iron intake of 15 women yielded a mean daily intake of \(16.2 \mathrm{mg}\) with sample standard deviation 4.7 \(\mathrm{mg} .\) a. Assuming that daily iron intake in women is normally distributed, perform the test that the actual mean daily intake for all women is different from \(18 \mathrm{mg} /\) day, at the \(10 \%\) level of significance. b. The sample mean is less than 18, suggesting that the actual population mean is less than 18 \(\mathrm{mg} /\) day. Perform this test, also at the \(10 \%\) level of significance. (The computation of the test statistic done in part (a) still applies here.)

Compute the value of the test statistic for the indicated test, based on the information given. a. Testing \(H_{0}: \mu=342\) vs. \(H a: \mu<342, \sigma=11.2, n=40, x-=339, s=10.3\) b. Testing \(H_{0}: \mu=105\) vs. Ha: \(\mu>105, \sigma=5.3, n=80, x-=107, s=5.1\) c. Testing \(H_{0}: \mu=-13.5\) vs. Ha: \(\mu \neq-13.5, \sigma\) unknown, \(n=32, x-=-13.8, s=1.5\) d. Testing \(H_{0}: \mu=28\) vs. \(H a: \mu \neq 28, \sigma\) unknown, \(n=68, x-27.8, s=1.3\)

See all solutions

Recommended explanations on Math Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.