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A corporation has advertised heavily to try to insure that over half the adult population recognizes the brand name of its products. In a random sample of 20 adults, 14 recognized its brand name. What is the probability that 14 or more people in such a sample would recognize its brand name if the actual proportion \(p\) of all adults who recognize the brand name were only \(0.50 ?\)

Short Answer

Expert verified
The probability is approximately 0.057.

Step by step solution

01

Define the Problem

We need to find the probability that 14 or more people in a sample of 20 recognize the brand name, assuming the actual proportion \( p \) of recognizers is 0.50. This is a binomial probability problem, where \( n = 20 \), \( p = 0.50 \), and variable of interest is \( X \), the number of recognizers.
02

Write the Binomial Probability Formula

The probability of exactly \( k \) successes in \( n \) trials, where the probability of success in each trial is \( p \), is given by the formula:\[ P(X = k) = \binom{n}{k} p^k (1-p)^{n-k} \]For our problem, substitute \( n = 20 \) and \( p = 0.50 \). We need this formula to calculate probabilities for \( k = 14, 15, 16, 17, 18, 19, 20 \).
03

Calculate Individual Probabilities

Calculate the probability for each value of \( X \) from 14 to 20 using the binomial formula. For instance, for \( X = 14 \):\[ P(X = 14) = \binom{20}{14} (0.50)^{14} (0.50)^{6} \]
04

Use Cumulative Probability

Calculate the cumulative probability that 14 or more adults recognize the brand. This is the sum of probabilities from step 3:\[ P(X \geq 14) = P(X = 14) + P(X = 15) + \dots + P(X = 20) \]
05

Compute and Sum the Probabilities

Using a calculator or statistical software, compute each probability and sum them. For instance, Calculate:\[ P(X = 14) \approx 0.060 \P(X = 15) \approx 0.033 \... \P(X = 20) \approx 0.0001 \]Then sum:\[ P(X \geq 14) \approx 0.060 + 0.033 + 0.014 + 0.004 + 0.001 + 0.0003 + 0.0001 \approx 0.057 \]
06

Interpret the Result

The total probability of observing 14 or more recognizers, if the true probability is 0.50, is approximately 0.057. Since this probability is relatively low, it indicates that such an extreme result would be unusual under the assumption \( p = 0.50 \).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Binomial Distribution
Binomial distribution is a powerful and commonly used statistical concept. It's utilized to describe the outcome of a sequence of experiments where each experiment can result in one of two possible outcomes. These outcomes are often referred to as "success" and "failure." The key characteristics of a binomial distribution include:
  • The number of trials, denoted as \( n \).
  • The probability of success in each trial, \( p \).
  • Each trial is independent of the others.
For example, consider a corporation's marketing campaign where the goal is to recognize its brand name. If you were to sample 20 adults, and each one has a 50% chance of recognizing the brand, this situation follows a binomial distribution with \( n = 20 \) and \( p = 0.50 \). Calculating probabilities using this distribution involves using the binomial probability formula: \[P(X = k) = \binom{n}{k} p^k (1-p)^{n-k}\]where \( k \) represents the number of successes you are calculating for. This formula helps calculate the likelihood of observing a certain number of successes in the sample.
Cumulative Probability
Cumulative probability refers to the likelihood that a random variable falls within a specified range. In practical terms, it involves adding up individual probabilities to get a total that reflects the chance of multiple events occurring. This is particularly useful when we're interested in the probability of observing "at least" or "at most" a certain number of successes.
In the case of the brand recognition exercise, we want to find the probability that 14 or more adults in a sample of 20 recognize the brand. This cumulative probability is the sum of probabilities for all outcomes starting from 14 up to 20:\[P(X \geq 14) = P(X = 14) + P(X = 15) + \cdots + P(X = 20) \]Computing cumulative probabilities often requires careful calculation or the use of statistical software. Such cumulative insights can help in making informed decisions about the likelihood of achieving particular outcomes.
Statistical Hypothesis Testing
Statistical hypothesis testing is a method used to make decisions based on data. It involves forming a hypothesis and then using statistical evidence to determine whether the hypothesis should be rejected or not. This process helps to quantitatively assess the evidence provided by the sample data.In the brand recognition scenario, the hypothesis might be that at least half of the population recognizes the brand, meaning \( p \geq 0.50 \). However, if we assume \( p = 0.50 \) and find a much lower probability of the observed sample (14 out of 20 recognizing the brand), it suggests that our assumption may not be correct. By calculating a cumulative probability, we use this evidence to interpret our assumption.
The key elements of the hypothesis testing process involve:
  • Null hypothesis \( H_0 \) and alternative hypothesis \( H_1 \).
  • Calculating a test statistic based on the sample data.
  • Determining the p-value, which quantifies the evidence against \( H_0 \).
  • Drawing conclusions: if the p-value is below a certain threshold (like 0.05), we reject \( H_0 \).
This structured approach provides a framework for making statistically sound judgments about population parameters based on sample data.

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Most popular questions from this chapter

An insurance company estimates that the probability that an individual in a particular risk group will survive one year is \(0.99 .\) Such a person wishes to buy a \(\$ 75,000\) one-year term life insurance policy. Let \(C\) denote how much the insurance company charges such a person for such a policy. a. Construct the probability distribution of \(X\). (Two entries in the table will containC.) b. Compute the expected value \(E(\boldsymbol{X})\) of \(X\). c. Determine the value \(C\) must have in order for the company to break even on all such policies (that is, to average a net gain of zero per policy on such policies). d. Determine the value \(C\) must have in order for the company to average a net gain of \(\$ 150\) per policy on all such policies.

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Borachio works in an automotive tire factory. The number \(X\) of sound but blemished tires that he produces on a random day has the probability distribution $$ \begin{array}{c|cccc} x & 2 & 3 & 4 & 5 \\ \hline P(x) & 0.48 & 0.36 & 0.12 & 0.04 \end{array} $$ a. Find the probability that Borachio will produce more than three blemished tires tomorrow. b. Find the probability that Borachio will produce at most two blemished tires c. Compute the mean and standard deviation of \(X\). Interpret the mean in the context of the problem.

Let \(X\) denote the number of times a fair coin lands heads in three tosses. Construct the probability distribution of \(X\).

Determine whether or not the table is a valid probability distribution of a discrete random variable. Explain fully. a. \begin{tabular}{c|ccccc} & 0 & 1 & 1 & 3 & 4 \\ \hline\(P(x)\) & -0.85 & 0.50 & 0.25 & 0.10 & 0.30 \end{tabular}b. \begin{tabular}{c|ccc} & 1 & 1 & 3 \\ \hline\(P(x)\) & 0.325 & 0.406 & 0.164 \end{tabular} C. \begin{tabular}{c|ccccc} & 25 & 26 & 27 & 28 & 20 \\ \hline\(P(x)\) & 0.13 & 0.27 & 0.28 & 0.18 & 0.14 \end{tabular}

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