Chapter 7: Problem 9
If a square matrix \(A=\left(\alpha_{j k}\right)\) has eigenvalues \(\lambda_{i}, j=1, \cdots, n\), show that \(k A\) has the eigenvalues \(k \lambda_{i}\) and \(A^{m}(m \in \mathbf{N})\) has the eigenvalues \(\lambda_{i}^{m}\).
Short Answer
Expert verified
Eigenvalues of \(kA\) are \(k\lambda_i\); of \(A^m\) are \(\lambda_i^m\).
Step by step solution
01
Understanding Eigenvalues
To understand the problem, we'll first clarify the concept of eigenvalues. For a square matrix \(A\), if there exists a non-zero vector \(v\) such that \(Av = \lambda v\), then \(\lambda\) is an eigenvalue of \(A\) and \(v\) is the corresponding eigenvector.
02
Eigenvalues of Scaled Matrix
Let's consider the matrix \(kA\), where \(k\) is a scalar. If \(\lambda\) is an eigenvalue of \(A\), then by definition, \(Av = \lambda v\). Multiply both sides by \(k\) to obtain \(kAv = k(\lambda v)\). This is equivalent to \((kA)v = k\lambda v\), indicating that \(k\lambda\) is an eigenvalue of \(kA\).
03
Eigenvalues of Matrix Powers
Next, consider the matrix power \(A^m\). Suppose \(A\) has an eigenvalue \(\lambda\) with corresponding eigenvector \(v\), so \(Av = \lambda v\). Then, \(A^2v = A(Av) = A(\lambda v) = \lambda(Av) = \lambda(\lambda v) = \lambda^2 v\). Applying this logic recursively, \(A^m v = \lambda^m v\). Therefore, \(\lambda^m\) is an eigenvalue of \(A^m\).
04
Conclusion on Eigenvalues of Scaled and Powered Matrix
Combining our results from above, we concluded that for a square matrix \(A\):1. The eigenvalues of \(kA\) are \(k\lambda_i\), where \(\lambda_i\) are the eigenvalues of \(A\).2. The eigenvalues of \(A^m\) are \(\lambda_i^m\), confirming that these properties hold for all eigenvalues of \(A\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Square Matrix
A square matrix is a type of matrix with an equal number of rows and columns. You can think of it as a grid that's perfectly square. If a matrix has dimensions \( n \times n \), it's called a square matrix of order \( n \). Square matrices are fundamental in linear algebra because many operations, like finding eigenvalues, are defined for these matrices.
There are several characteristics unique to square matrices:
There are several characteristics unique to square matrices:
- Their diagonals are especially important; ones with non-zero values on the diagonal and zero elsewhere are called diagonal matrices.
- They can have determinants, which is a special number that can show if a matrix has an inverse.
- You can perform operations like finding powers of the matrix \( (A^m) \), especially when analyzing eigenvectors and eigenvalues.
Eigenvectors
Eigenvectors are special vectors associated with a matrix. When you multiply a matrix by one of its eigenvectors, the result is the same as if you just scaled that eigenvector by a specific value called an eigenvalue. In simple terms, eigenvectors show the directions that are stretched or shrunk by the transformation described by the matrix.
So, if you have a square matrix \( A \), an eigenvector \( v \), and its associated eigenvalue \( \lambda \), the defining relationship is \( Av = \lambda v \). Solving for the eigenvectors involves several steps:
So, if you have a square matrix \( A \), an eigenvector \( v \), and its associated eigenvalue \( \lambda \), the defining relationship is \( Av = \lambda v \). Solving for the eigenvectors involves several steps:
- Compute \( A - \lambda I \), where \( I \) is the identity matrix of the same size as \( A \).
- Find the non-zero solutions of the equation resulting from \( (A - \lambda I)v = 0 \).
Matrix Powers
Matrix powers are a fascinating operation for square matrices. Raising a matrix to a power, such as \( A^m \), involves multiplying the matrix by itself multiple times (m times, precisely). Matrix powers are particularly useful when analyzing dynamic systems that evolve over time.
For a matrix \( A \) with an eigenvalue \( \lambda \), when we consider \( A^m \), an interesting property is observed: the eigenvalues of \( A^m \) become \( \lambda^m \). Here’s a quick overview of how it works:
For a matrix \( A \) with an eigenvalue \( \lambda \), when we consider \( A^m \), an interesting property is observed: the eigenvalues of \( A^m \) become \( \lambda^m \). Here’s a quick overview of how it works:
- Start with the relation \( Av = \lambda v \) for an eigenvector \( v \).
- Multiply through by \( A \) to show \( A^2v = \lambda^2 v \).
- Continue this multiplication process until you reach \( A^m v = \lambda^m v \).
Scaled Matrix
A scaled matrix is what you get when you multiply every element of a matrix by a constant value, known as the scalar. For instance, if you have a matrix \( A \) and a scalar \( k \), the scaled matrix is represented by \( kA \).
The interesting outcome of scaling a matrix is how it affects eigenvalues. For a square matrix \( A \) with eigenvalues \( \lambda_i \), the eigenvalues of the scaled matrix \( kA \) become \( k\lambda_i \). Here’s a simple breakdown of how it happens:
The interesting outcome of scaling a matrix is how it affects eigenvalues. For a square matrix \( A \) with eigenvalues \( \lambda_i \), the eigenvalues of the scaled matrix \( kA \) become \( k\lambda_i \). Here’s a simple breakdown of how it happens:
- Start from the eigenvalue equation \( Av = \lambda v \).
- Apply the scalar \( k \) to get \( k(Av) = k(\lambda v) \).
- This simplifies to \( (kA)v = (k\lambda)v \), illustrating that each eigenvalue is simply scaled by \( k \).