Chapter 4: Problem 8
Let \(X\) be a normed space and \(X^{\prime}\) its dual space. If \(X \neq\\{0\\}\), show that \(X^{\prime}\) cannot be \(\\{0\\}\).
Short Answer
Expert verified
The dual space \(X'\) of a non-zero normed space \(X\) cannot be the zero space; it must contain non-zero functional.
Step by step solution
01
Understand the Definitions
A normed space \(X\) is a vector space with a norm associated with each vector. The dual space \(X'\) of \(X\) consists of all bounded linear functionals, which are mappings from \(X\) to the field of scalars (usually \(\mathbb{R}\) or \(\mathbb{C}\)). A functional \(f: X \to \mathbb{R}\) (or \(\mathbb{C}\)) is bounded if there is some constant \(C\) such that for all \(x \in X\), \(|f(x)| \leq C \|x\|\).
02
Assume Towards a Contradiction
Suppose, for contradiction, that \(X' = \{0\}\). This would mean that there are no non-zero bounded linear functionals on \(X\), so the only functional in \(X'\) is the zero functional, which maps every vector in \(X\) to zero.
03
Construct a Non-Zero Linear Functional
Since \(X eq \{0\}\), there exists at least one non-zero vector \(x_0 \in X\). Define a functional \(f: X \to \mathbb{R}\) (or \(\mathbb{C}\)) such that \(f(x) = \frac{x}{\|x_0\|}x_0\), where \(\frac{x}{\|x_0\|}\) is a chosen scalar from the respective field, ensuring linearity. By this construction, \(f\) is non-zero when \(x = x_0.\)
04
Verify Boundedness
We need to show that the constructed functional \(f\) is bounded. For any \(x \in X\), \(|f(x)| = \left|\frac{x}{\|x_0\|}x_0\right| = \left|\frac{x}{\|x_0\|}\right|\cdot\|x_0\| = \|x\|\). Therefore, \(f\) is bounded with constant \(C = 1\).
05
Conclude by Contradiction
The constructed non-zero bounded linear functional \(f\) implies that \(X'\) is not the zero space. This contradicts our initial assumption. Therefore, \(X'\) must contain at least one non-zero functional, proving \(X' eq \{0\}\).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Normed Space
In functional analysis, a **normed space** forms the cornerstone of various mathematical frameworks. A normed space, denoted as \(X\), is a vector space equipped with a function called a norm. The norm, typically symbolized by \(\| \cdot \|\), assigns a non-negative scalar to each vector in the space. This scalar serves as a measure of the 'size' or 'length' of the vector.
Key properties of a norm include:
Key properties of a norm include:
- **Non-negativity**: The norm of any vector \(x\) is always zero or positive, \(\|x\| \geq 0\).
- **Definiteness**: \(\|x\| = 0\) if and only if \(x\) is the zero vector.
- **Scalability**: \(\|\alpha x\| = |\alpha| \cdot \|x\|\), where \(\alpha\) is a scalar.
- **Triangle Inequality**: \(\|x + y\| \leq \|x\| + \|y\|\).
Dual Space
The **dual space** of a normed space \(X\), denoted \(X'\), is a critical concept in understanding how functionals operate within these spaces. The dual space consists of all bounded linear functionals which map vectors from \(X\) into the scalar field (typically \(\mathbb{R}\) or \(\mathbb{C}\)).
A functional \(f : X \to \mathbb{R}\) (or \(\mathbb{C}\)) is termed *linear* if it satisfies:
The significance of the dual space reflects in numerous mathematical disciplines, offering insight and tools for solving various equations and confirming properties of the spaces.
A functional \(f : X \to \mathbb{R}\) (or \(\mathbb{C}\)) is termed *linear* if it satisfies:
- **Additivity**: \(f(x + y) = f(x) + f(y)\)
- **Homogeneity**: \(f(\alpha x) = \alpha f(x)\)
The significance of the dual space reflects in numerous mathematical disciplines, offering insight and tools for solving various equations and confirming properties of the spaces.
Bounded Linear Functional
A **bounded linear functional** is an essential element of functional analysis, residing within the dual space of a normed space. It is a linear transformation from a vector space to its underlying field (like \(\mathbb{R}\) or \(\mathbb{C}\)), ensuring both linearity and boundedness.
Bounded linear functionals must respect the following conditions:
Bounded linear functionals must respect the following conditions:
- **Linearity**: For vectors \(x, y \in X\) and scalars \(\alpha\), the functional \(f\) satisfies \(f(x + y) = f(x) + f(y)\) and \(f(\alpha x) = \alpha f(x)\).
- **Boundedness**: There exists a constant \(C\) such that \(|f(x)| \leq C \|x\|\) for all \(x \in X\). This ensures the functional does not grow excessively with the vector's magnitude, preserving a type of controlled growth.