Chapter 3: Problem 3
If \(z\) is any fixed element of an inner product space \(X\), show that \(f(x)=\langle x, z\rangle\) defines a bounded linear functional \(f\) on \(X\), of norm \(\|z\|\).
Short Answer
Expert verified
The function \( f(x) = \langle x, z \rangle \) is a bounded linear functional with norm \( \|z\| \).
Step by step solution
01
Check Linearity
Start by checking the linearity of the function \( f(x) = \langle x, z \rangle \). A function is linear if, for all vectors \( x, y \) in \( X \) and scalar \( a \), the following properties hold:1. **Additivity:** \( f(x+y) = f(x) + f(y) \). - Proof: \( f(x+y) = \langle x+y, z \rangle = \langle x, z \rangle + \langle y, z \rangle = f(x) + f(y) \)2. **Homogeneity:** \( f(ax) = a \, f(x) \). - Proof: \( f(ax) = \langle ax, z \rangle = a \, \langle x, z \rangle = a \, f(x) \)Thus, the function \( f(x) = \langle x, z \rangle \) is linear.
02
Prove Boundedness
Now we show that \( f(x) \) is a bounded linear functional, meaning there exists \( C \geq 0 \) such that \( |f(x)| \leq C \|x\| \) for all \( x \in X \).Using the Cauchy-Schwarz inequality:\( |f(x)| = |\langle x, z \rangle| \leq \|x\| \|z\|\)This inequality shows that we can take \( C = \|z\| \), as it satisfies the boundedness condition. Therefore, \( f \) is a bounded linear functional.
03
Confirm Norm of Functional
Finally, find the norm of this functional \( \|f\| \), defined as \( \sup_{\|x\|=1} |f(x)| \).By choosing \( x = \frac{z}{\|z\|} \) when \( z eq 0 \), we have that \( \|x\| = 1 \) and:\[ |f(x)| = \left| \left\langle \frac{z}{\|z\|}, z \right\rangle \right| = \left| \frac{\langle z, z \rangle}{\|z\|} \right| = \|z\|\]This confirms that \( \|f\| = \|z\| \), as it achieves the supremum value \( \|z\| \).
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Inner Product Space
An inner product space is a special type of vector space equipped with an additional structure called an "inner product." This inner product is a way to multiply vectors together to get a scalar (a real number or a complex number). The inner product is denoted by \(\langle x, y \rangle\) for vectors \(x\) and \(y\). It must satisfy three properties:
- Conjugate Symmetry: \(\langle x, y \rangle = \overline{\langle y, x \rangle}\)
- Linearity in the First Argument: \(\langle ax + by, z \rangle = a\langle x, z \rangle + b\langle y, z \rangle\)
- Positive-Definiteness: \(\langle x, x \rangle \geq 0\) and \(\langle x, x \rangle = 0\) if and only if \(x = 0\)
Bounded Linear Functional
In functional analysis, a bounded linear functional is a linear map \(f\) from a vector space \(X\) to the field of scalars (usually the real or complex numbers). This map must satisfy two conditions:
- Linearity: For any vectors \(x, y\) in \(X\) and scalar \(a\), the properties \(f(x+y) = f(x) + f(y)\) and \(f(ax) = a\, f(x)\) hold.
- Boundedness: There is a constant \(C\) such that \(|f(x)| \leq C \|x\|\) for all \(x\) in \(X\).
Cauchy-Schwarz Inequality
The Cauchy-Schwarz inequality is a fundamental inequality used in many areas of mathematics, particularly in the context of inner product spaces. Formally, it states:\[|\langle x, y \rangle| \leq \|x\| \|y\|\]for any vectors \(x\) and \(y\) in an inner product space. Here's what it entails:
- It provides a bound: The absolute value of the inner product is limited by the product of the magnitudes (norms) of the two involved vectors.
- Ensures positivity: When the Cauchy-Schwarz equality holds, it often indicates geometrically that the vectors are parallel or collinear.
Linearity
Linearity is a crucial concept in functional analysis, describing functions that preserve vector addition and scalar multiplication properties. A function \(f\) is linear if:
- Additivity: \(f(x+y) = f(x) + f(y)\) for any vectors \(x\) and \(y\).
- Homogeneity: \(f(ax) = a\,f(x)\) for any vector \(x\) and scalar \(a\).