Chapter 1: Problem 15
Show that the image of an open set under a continuous mapping need not be open.
Short Answer
Expert verified
An example is \( f(x) = x^2 \) mapping \((-1, 1)\) to \([0, 1)\), which is not open.
Step by step solution
01
Determine Definitions
First, we need to clarify the definitions involved. An **open set** in a topological space is a set that, broadly speaking, does not include its boundary points. A function \( f: X \rightarrow Y \) is said to be **continuous** if for every open set \( V \subseteq Y \), the preimage \( f^{-1}(V) \) is an open set in \( X \).
02
Choose the Topological Spaces
Consider the function \( f: \mathbb{R} \rightarrow \mathbb{R} \) with the standard topology on both domain and codomain. \( f(x) = x^2 \) is a continuous function in this context because polynomials are continuous functions on \( \mathbb{R} \).
03
Select an Open Set in the Domain
Let's consider an open set in \( \mathbb{R} \), such as \((-1, 1)\). This is open in the standard topology on \( \mathbb{R} \).
04
Calculate the Image of the Open Set
Now calculate the image of this set under the mapping \( f(x) = x^2 \). The image will be \( f((-1, 1)) = [0, 1) \), as \( x^2 \) will map \( x \) from \(-1 \) to \( 1 \) into the interval \([0, 1)\).
05
Evaluate if the Image is Open
The set \([0, 1)\) is **not open** in \( \mathbb{R} \) under the standard topology because it includes 0, a boundary point that cannot be approached from values less than 0 within \( \mathbb{R} \).
06
Conclude the Argument
Since \( f((-1, 1)) = [0, 1) \), which is not open in the codomain \( \mathbb{R} \), we have an open set \((-1, 1)\) in the domain whose image under the continuous mapping \( f(x) = x^2 \) is not open. This demonstrates that the image of an open set under a continuous mapping need not be open.
Unlock Step-by-Step Solutions & Ace Your Exams!
-
Full Textbook Solutions
Get detailed explanations and key concepts
-
Unlimited Al creation
Al flashcards, explanations, exams and more...
-
Ads-free access
To over 500 millions flashcards
-
Money-back guarantee
We refund you if you fail your exam.
Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Open Sets
An open set is a crucial concept in topology. Open sets are the building blocks for defining the structure of a topological space. Imagine a set that doesn't "touch" its boundary points. In simple terms, if you have a point in an open set, there exists a small "wiggle room" around that point which is completely contained within the set.
It's like being inside a room without any corners where you can always move a tiny bit and still remain within the room. Mathematically, a set is open if, for every point in that set, there is some neighborhood that is also contained within the set.
It's like being inside a room without any corners where you can always move a tiny bit and still remain within the room. Mathematically, a set is open if, for every point in that set, there is some neighborhood that is also contained within the set.
- No boundary points in an open set are inside the set itself.
- Open sets help in defining concepts like convergence and continuity in topology.
Continuous Mapping
Continuous mapping is a concept that ensures that small changes in the input result in small changes in the output. Think of it as a smooth journey without any abrupt jumps or drops. In mathematical terms, a function between topological spaces is continuous if it "preserves" the openness of sets in a specific way.
Here's how it works: given a function \( f: X \rightarrow Y \), if you take an open set \( V \subseteq Y \), then the preimage of that set, denoted as \( f^{-1}(V) \), should also be open in \( X \). Essentially, if \( V \) is open in \( Y \), then all the points that "lead" to \( V \) via the function \( f \) should also form an open set in \( X \).
Here's how it works: given a function \( f: X \rightarrow Y \), if you take an open set \( V \subseteq Y \), then the preimage of that set, denoted as \( f^{-1}(V) \), should also be open in \( X \). Essentially, if \( V \) is open in \( Y \), then all the points that "lead" to \( V \) via the function \( f \) should also form an open set in \( X \).
- Continuity is fundamentally about preserving the structure of open sets across spaces.
- In the realm of real functions, familiar continuous functions include polynomials and trigonometric functions.
Topological Spaces
Topological spaces are more about relationships and properties than about measurements. They provide a framework to define concepts like "nearness" without necessarily dealing with distances. A topological space consists of a set and a collection of open sets that satisfy certain requirements.
To define a topological space \( (X, \mathcal{T}) \):
To define a topological space \( (X, \mathcal{T}) \):
- There is a set \( X \), and \( \mathcal{T} \) is a collection of subsets of \( X \), which we call the topology.
- The empty set and \( X \) itself must be in \( \mathcal{T} \).
- The union of any collection of sets in \( \mathcal{T} \) must also be in \( \mathcal{T} \).
- The intersection of a finite number of sets in \( \mathcal{T} \) must also be in \( \mathcal{T} \).