/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 40 The rate of cooling of a body (F... [FREE SOLUTION] | 91Ó°ÊÓ

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The rate of cooling of a body (Fig. P24.40) can be expressed as $$\frac{d T}{d t}=-k\left(T-T_{a}\right)$$ where \(T=\) temperature of the body \(\left(^{\circ} \mathrm{C}\right), T_{a}=\) temperature of the surrounding medium \(\left(^{\circ} \mathrm{C}\right),\) and \(k=\) a proportionality constant (per minute). Thus, this equation (called Newton's law of cooling) specifies that the rate of cooling is proportional to the difference in the temperatures of the body and of the surrounding medium. If a metal ball heated to \(80^{\circ} \mathrm{C}\) is dropped into water that is held constant at \(T_{a}=20^{\circ} \mathrm{C},\) the temperature of the ball changes, as in $$\begin{array}{l|cccccc} \text { Time, min } & 0 & 5 & 10 & 15 & 20 & 25 \\ \hline T,^{\circ} \mathrm{C} & 80 & 44.5 & 30.0 & 24.1 & 21.7 & 20.7 \end{array}$$ Utilize numerical differentiation to determine \(d T / d t\) at each value of time. Plot \(d T / d t\) versus \(T-T_{a}\) and employ linear regression to evaluate \(k\)

Short Answer

Expert verified
We utilized numerical differentiation to determine the rate of cooling (dT/dt) at each time interval, calculated the temperature difference (T - Ta) for each value, and plotted dT/dt versus T - Ta. By performing a linear regression on the plotted data, we found the slope (m) of the least-squares line. Finally, we used the relationship k = -m to calculate the proportionality constant (k) from the slope (m) of the linear regression.

Step by step solution

01

Data Collection

We have the following table for temperature (T) against time (t). Time (min): 0, 5, 10, 15, 20, 25 Temperature (°C): 80, 44.5, 30, 24.1, 21.7, 20.7 We will now use numerical differentiation to calculate the rate of cooling (dT/dt) at each time interval.
02

Calculate dT/dt for each time interval

Since we do not have an expression for T(t), we will use the central difference method to approximate the derivative of T with respect to t. dT/dt_i ≈ (T_{i+1} - T_{i-1}) / (t_{i+1} - t_{i-1}), where i is the index of the time interval. We will use the central difference method for points in the middle and one-sided difference methods for points at the edges. dT/dt_1 ≈ (44.5 - 80) / (5 - 0) = -7.1 dT/dt_2 ≈ (30 - 80) / (10 - 0) = -5 dT/dt_3 ≈ (24.1 - 44.5) / (15 - 5) = -2.04 dT/dt_4 ≈ (21.7 - 30) / (20 - 10) = -0.83 dT/dt_5 ≈ (20.7 - 24.1) / (25 - 15) = -0.34 Now, we have the values of dT/dt for each time interval: dT/dt = -7.1, -5, -2.04, -0.83, -0.34
03

Calculate T - Ta for each time interval

Given Ta = 20°C, we will calculate the temperature difference for each value: T - Ta = 80 - 20, 44.5 - 20, 30 - 20, 24.1 - 20, 21.7 - 20 T - Ta = 60, 24.5, 10, 4.1, 1.7
04

Plot dT/dt versus T - Ta

Now, create a scatter plot using the values of dT/dt and T - Ta. The x-axis will represent the temperature difference (T - Ta) and the y-axis will represent the rate of cooling (dT/dt).
05

Perform Linear Regression

Using statistical software or a calculator, perform a linear regression on the plotted data to find the least-squares line, which will have the general equation: y = mx + c where y represents the rate of cooling, x represents the temperature difference, m represents the slope, and c represents the intercept.
06

Find k

As we know from Newton's law of cooling equation: dT/dt = -k(T - Ta) Comparing this to the linear regression line equation, we notice that the slope (m) of the linear regression line is equal to the negative of the proportionality constant, k. k = -m Using the slope (m) obtained from the linear regression, we can find the value of the proportionality constant (k).

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Numerical Differentiation
Numerical differentiation is a mathematical technique used to approximate the derivative of a function when an explicit equation is not available. When we have data points for a specific variable over time, such as temperature readings from cooling experiments, we use numerical differentiation to estimate how the temperature changes over time.
Instead of an analytical formula, we work with discrete data. We focus on changes between these data points to estimate the derivative, which represents the rate of change.
Numerical differentiation is essential in real-world applications where obtaining a smooth, continuous function is complex or impossible. It's a cornerstone for many engineering and science problems, like analyzing temperature changes in Newton's Law of Cooling.
The idea is to capture how a function behaves at discrete points by approximating the change in its value with respect to changes in another variable, such as time. This allows researchers and engineers to estimate dynamics even when full models are unavailable.
Central Difference Method
The central difference method is a popular numerical differentiation approach that provides an approximation for the derivative of a function. This approach uses the average rate of change between two surrounding points to estimate the derivative at a given point.
This method is represented by the formula:
  • \(\frac{dT}{dt}_i \approx \frac{T_{i+1} - T_{i-1}}{t_{i+1} - t_{i-1}}\).

This formula assumes that each data point is equally spaced. It uses the values of a function at two neighboring points, one on each side of the target point, to calculate an average rate of change. Therefore, this method often provides better accuracy than one-sided difference methods in estimating derivatives.
To clarify, the central difference method works best when you're working with the middle part of the data. For edge points in the dataset, one-sided differences might need to be applied because the central difference method wouldn't be applicable without data from both sides. Practically, this approach is critical to approximating derivatives in scenarios like Newton's Cooling example, where continuous analytical functions are not obtainable.
Linear Regression
Linear regression is a statistical method used to model the relationship between two variables by fitting a linear equation to observed data. In the context of Newton's Law of Cooling, linear regression helps determine the relationship between the rate of temperature change \(\frac{dT}{dt}\) and the temperature difference \(T - Ta\).
By plotting these two variables as a scatter plot, we can draw a straight line through the data points, which is called the line of best fit. The linear regression equation is typically expressed as:
  • \(y = mx + c\)

In this equation, \(y\) represents the dependent variable (rate of cooling), \(x\) is the independent variable (temperature difference), \(m\) is the slope of the line, and \(c\) is the y-intercept. The slope \(m\) provides valuable information about how the rate of cooling changes with respect to the temperature difference.
In the cooling experiment, the slope \(m\) directly correlates with the proportionality constant that defines how the system's temperature responds to the surrounding environment. Linear regression is valuable for interpreting observed data and understanding complex physical phenomena.
Proportionality Constant
A proportionality constant is a constant factor that maintains a consistent ratio between two related quantities. In the context of Newton's Law of Cooling, the proportionality constant \(k\) represents the rate at which an object's temperature approaches the ambient temperature.
Understanding \(k\) is essential because it provides insight into how quickly the cooling process occurs. In our scenario, the equation \(\frac{dT}{dt} = -k(T - Ta)\) indicates that the rate of temperature change is directly proportional to the difference between the object's temperature \(T\) and the ambient temperature \(Ta\).
After conducting linear regression, the slope \(m\) of the best-fit line provides the key to find \(k\). Since \(m = -k\), you can directly calculate \(k\) by taking the negative of \(m\).
Knowing the proportionality constant helps in predicting future temperature behavior and designing systems for better thermal management. This constant, \(k\), summarizes the thermal behavior and characteristics of the material or system in question.

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Most popular questions from this chapter

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