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Repeat Prob. 23.4, but for the first derivative of \(\ln x\) at \(x=5\) using \(h_{1}=2\) and \(h_{2}=1.\)

Short Answer

Expert verified
The approximate values of the first derivative of \(ln(x)\) at \(x=5\) using the given values of \(h_1\) and \(h_2\) are as follows: 1. Forward Difference with \(h_1=2\): \(\frac{ln(7) - ln(5)}{2}\) 2. Forward Difference with \(h_2=1\): \(ln(6) - ln(5)\) 3. Backward Difference with \(h_1=2\): \(\frac{ln(5) - ln(3)}{2}\) 4. Backward Difference with \(h_2=1\): \(ln(5) - ln(4)\) 5. Central Difference with \(h_1=2\): \(\frac{ln(7) - ln(3)}{4}\) 6. Central Difference with \(h_2=1\): \(\frac{ln(6) - ln(4)}{2}\)

Step by step solution

01

Calculate the forward difference approximation with \(h_1=2\)

The forward difference formula is given by: \(f'(x) 鈮 \frac{f(x + h) - f(x)}{h}\) Here, \(f(x) = ln(x)\) and we want to find the first derivative at \(x=5\) using \(h_1=2\). Plug in the values and compute: \(f'(5) 鈮 \frac{ln(5 + 2) - ln(5)}{2}\) \(f'(5) 鈮 \frac{ln(7) - ln(5)}{2}\)
02

Calculate the forward difference approximation with \(h_2=1\)

Repeat the forward difference formula calculation using \(h_2=1\). Plug in the values and compute: \(f'(5) 鈮 \frac{ln(5 + 1) - ln(5)}{1}\) \(f'(5) 鈮 ln(6) - ln(5)\)
03

Calculate the backward difference approximation with \(h_1=2\)

The backward difference formula is given by: \(f'(x) 鈮 \frac{f(x) - f(x - h)}{h}\) Compute the backward difference approximation using \(h_1=2\): \(f'(5) 鈮 \frac{ln(5) - ln(5 - 2)}{2}\) \(f'(5) 鈮 \frac{ln(5) - ln(3)}{2}\)
04

Calculate the backward difference approximation with \(h_2=1\)

Repeat the backward difference formula calculation using \(h_2=1\). Plug in the values and compute: \(f'(5) 鈮 \frac{ln(5) - ln(5 - 1)}{1}\) \(f'(5) 鈮 ln(5) - ln(4)\)
05

Calculate the central difference approximation with \(h_1=2\)

The central difference formula is given by: \(f'(x) 鈮 \frac{f(x + h) - f(x - h)}{2h}\) Compute the central difference approximation using \(h_1=2\): \(f'(5) 鈮 \frac{ln(5 + 2) - ln(5 - 2)}{2(2)}\) \(f'(5) 鈮 \frac{ln(7) - ln(3)}{4}\)
06

Calculate the central difference approximation with \(h_2=1\)

Repeat the central difference formula calculation using \(h_2=1\). Plug in the values and compute: \(f'(5) 鈮 \frac{ln(5 + 1) - ln(5 - 1)}{2(1)}\) \(f'(5) 鈮 \frac{ln(6) - ln(4)}{2}\) The approximate values of the first derivative of ln(x) at x=5 using the given values of h鈧 and h鈧 are obtained using the three different methods: Forward Difference with h鈧: \(\frac{ln(7) - ln(5)}{2}\) Forward Difference with h鈧: \(ln(6) - ln(5)\) Backward Difference with h鈧: \(\frac{ln(5) - ln(3)}{2}\) Backward Difference with h鈧: \(ln(5) - ln(4)\) Central Difference with h鈧: \(\frac{ln(7) - ln(3)}{4}\) Central Difference with h鈧: \(\frac{ln(6) - ln(4)}{2}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Understanding Forward Difference Approximation
Forward difference approximation is a numerical technique used to estimate the derivative of a function. It is particularly useful when we do not have an analytical form or when dealing with discrete data. The formula for the forward difference is defined as:
  • \(f'(x) \approx \frac{f(x + h) - f(x)}{h}\)
Here, \(h\) represents a small step size from our point \(x\). This approach calculates the slope of the secant line between the points \((x, f(x))\) and \((x + h, f(x+h))\).

Using this method to find the derivative of \(\ln x\) at \(x=5\), we compute with \(h_1=2\) and \(h_2=1\). The calculations entail substituting the values of \(x + h\) into the logarithm function and computing the difference quotient. This technique is straightforward and relatively simple to implement, making it a favored approach for quick approximations.
Exploring Backward Difference Approximation
Backward difference approximation works similarly to the forward difference but uses a previous point to approximate the derivative. It is especially handy when we are given data up to a certain point and cannot look ahead. The formula is given by:
  • \(f'(x) \approx \frac{f(x) - f(x - h)}{h}\)
In this method, \(h\) is adjustable, just like in the forward difference method.

This approach computes the slope of the secant line between \((x, f(x))\) and \((x - h, f(x-h))\). For the function \(\ln x\) at \(x=5\), the backward difference with \(h_1=2\) and \(h_2=1\) involves substituting values into our equation to easily find the slope between the given point and a prior point. This approximation can be more accurate than the forward difference when approaching an endpoint from the left.
Central Difference Approximation for Balanced Results
Central difference approximation takes the average of forward and backward differences, resulting in a more balanced estimate of the derivative. It is often more accurate than using forward or backward differences alone. Its formula is:
  • \(f'(x) \approx \frac{f(x + h) - f(x - h)}{2h}\)

This method determines the derivative by calculating the average rate of change around the point \(x\), leveraging equal steps forward and backward.
For example, estimating the derivative of \(\ln x\) at \(x=5\) with \(h_1=2\) and \(h_2=1\) involves computing the difference in \(\ln\) values at these points and substituting them into the formula.
Central difference is favored in scenarios requiring higher precision without extending the range of \(h\), offering a compelling trade-off between forward and backward approximation results.
Working with Logarithmic Functions
Logarithmic functions, especially the natural logarithm denoted as \(\ln x\), appear in many scientific and engineering applications due to their unique properties. The base of the natural logarithm \(e\), where \(e \approx 2.718\), is particularly significant because it inversely corresponds to exponential functions.

When differentiating \(\ln x\), an analytical method gives us \(f'(x) = \frac{1}{x}\). However, numerical differentiation methods like the ones discussed are instrumental when dealing with discrete points or data sets where the explicit function may not be well-defined.
Understanding how to work with numerical approximations of the derivative of \(\ln x\) requires not just plugging numbers into formulas but also an appreciation of how those formulas work given the continuous and monotonically increasing nature of logarithm functions. Such skills are indispensable in problem-solving across varied disciplines, facilitating insights that extend beyond analytical calculations.

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Most popular questions from this chapter

Evaluate \(\partial f / \partial x, \partial f / \partial y,\) and \(\partial f /(\partial x \partial y)\) for the following function at \(x=y=1\) (a) analytically and (b) numerically \(\Delta x=\Delta y=\) 0.0001, $$f(x, y)=3 x y+3 x-x^{3}-3 y^{3}$$

Compute forward and backward difference approximations of \(O(h)\) and \(O\left(h^{2}\right),\) and central difference approximations of \(O\left(H^{2}\right)\) and \(O\left(h^{4}\right)\) for the first derivative of \(y=\sin x\) at \(x=\pi / 4\) using a value of \(h=\pi / 12 .\) Estimate the true percent relative error \(\varepsilon_{t}\) for each approximation.

Evaluate the following integral with MATLAB, $$\int_{0}^{2 \pi} \frac{\sin t}{t} d t$$ using both the quad and quadl functions. To learn more about quad1, type help quadl at the MATLAB prompt.

Recall that for the falling parachutist problem, the velocity is given by $$v(t)=\frac{g m}{c}\left(1-e^{-(c / m) t}\right) \quad (P23.13a)$$ and the distance traveled can be obtained by $$d(t)=\frac{g m}{c} \int_{0}^{t}\left(1-e^{-(c / m) t}\right) d t \quad (P23.13b)$$ Given \(g=9.81, m=70,\) and \(c=12,\) (a) Use MATLAB or Mathcad to integrate Eq. (P23.13a) from \(t=0\) to 10. (b) Analytically integrate Eq. (P23.13b) with the initial condition that \(d=0\) at \(t=0 .\) Evaluate the result at \(t=10\) to confirm (a). (c) Use MATLAB or Mathcad to differentiate Eq. (P23.13a) at \(t=10.\) (d) Analytically differentiate Eq. (P23.13a) at \(t=10\) to confirm (c).

The objective of this problem is to compare second-order accurate forward, backward, and centered finite-difference approximations of the first derivative of a function to the actual value of the derivative. This will be done for $$f(x)=e^{-2 x}-x$$ (a) Use calculus to determine the correct value of the derivative at \(x=2.\) (b) To evaluate the centered finite-difference approximations, start with \(x=0.5 .\) Thus, for the first evaluation, the \(x\) values for the centered difference approximation will be \(x=2 \pm 0.5\) or \(x=1.5\) and \(2.5 .\) Then, decrease in increments of 0.01 down to a minimum value of \(\Delta x=0.01.\) (c) Repeat part (b) for the second-order forward and backward differences. (Note that these can be done at the same time that the centered difference is computed in the loop.) (d) Plot the results of (b) and (c) versus \(x\). Include the exact result on the plot for comparison.

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