/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Problem 25 \(F(s)=\left(s^{3}-s^{2}+2 s-6\r... [FREE SOLUTION] | 91Ó°ÊÓ

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\(F(s)=\left(s^{3}-s^{2}+2 s-6\right) / s^{5}\)

Short Answer

Expert verified
The simplified form is \( F(s) = s^{-2} - s^{-3} + 2s^{-4} - 6s^{-5} \).

Step by step solution

01

Simplify the Fraction

First, let's simplify the fraction by separating each term in the numerator: \[ F(s) = \frac{s^3}{s^5} - \frac{s^2}{s^5} + \frac{2s}{s^5} - \frac{6}{s^5} \] Now simplify each term.
02

Simplify Individual Terms

Now we simplify each individual term: \[ F(s) = s^{3-5} - s^{2-5} + \frac{2s}{s^5} - \frac{6}{s^5} \] This gives us: \[ F(s) = s^{-2} - s^{-3} + 2s^{-4} - 6s^{-5} \]
03

Combine the Simplified Terms

Combine all the simplified terms to get the final simplified function: \[ F(s) = s^{-2} - s^{-3} + 2s^{-4} - 6s^{-5} \]

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Laplace Transforms
The Laplace transform is a powerful mathematical technique used to transform functions of a real variable (usually time) into functions of a complex variable (frequency). This method is incredibly useful for solving differential equations and analyzing linear time-invariant systems. The basic idea is to change a function from the time domain to the frequency domain, which can simplify the problem of solving differential equations.
The Laplace transform of a function, denoted by \(\text{L}\{\text{(f(t))}} = F(s)\), where \( s \) is a complex number, is defined as:
\[\text{L}\text{(f(t))} = \text{F}\text{(s)} = \int_0^{\text{∞}} \text{e}^{-\text{s}\text{t}}\text{f(t)}\text{d}\text{t} \]
To use Laplace transforms effectively, you should become familiar with common Laplace transform pairs and properties such as linearity, time-shifting, and the final value theorem.
Fraction Simplification
Fraction simplification involves breaking down a complex fraction into simpler parts. In our example, the fraction is given as:
\[\text{F(s)} = \frac{s^3 - s^2 + 2s - 6}{s^5} \]
Simplifying involves separating each term in the numerator and dividing them individually by the denominator. This can be written like:
\[\text{F(s)} = \frac{s^3}{s^5} - \frac{s^2}{s^5} + \frac{2s}{s^5} - \frac{6}{s^5} \]
As we break down each term and simplify, we get:
\[\text{F(s)} = s^{-2} - s^{-3} + 2s^{-4} - 6s^{-5} \]
This method helps in dealing with high degrees in the numerator or complex polynomial expressions.
Polynomial Division
Polynomial division is a fundamental technique used to simplify rational functions. It involves dividing one polynomial by another polynomial.
In our problem, each term in the numerator \(\text{s}^3 - \text{s}^2 + 2\text{s} - 6\) is divided individually by \(\text{s}^5\). This is a straightforward example of polynomial division where the division is done term by term:
- For \(\text{s}^3 \div s^5 \), you subtract the exponents: \(\text{s}^{3-5} = s^{-2}\)
- Repeat for each subsequent term: \(\text{s}^2 \div s^5 = s^{-3}\), \( 2\text{s} \div s^5 = 2s^{-4} \), and \( \frac{6}{s^5} = 6s^{-5}\)
Polynomial division can simplify functions and make it easier to perform operations like Laplace transforms, as seen in our example.

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