Chapter 7: Problem 14
\(x^{\prime \prime}+16 x=0\)
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Chapter 7: Problem 14
\(x^{\prime \prime}+16 x=0\)
These are the key concepts you need to understand to accurately answer the question.
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\(x^{\prime \prime}+10 x^{\prime}+25 x=0\)
Solve the two-loop \(L-R-C\) circuit with \(L=\) \(1 \mathrm{H}, R_{1}=R_{2}=40 \Omega, C=1 / 250 \mathrm{~F}\), and \(E(t)=220 \cos t \mathrm{~V} .\left(Q(0)=0 \mathrm{C}, I_{2}(0)=0 \mathrm{~A} .\right)\)
Solve the one-loop \(L-R-C\) circuit with \(L=\) \(1 \mathrm{H}, R=40 \Omega, C=1 / 250 \mathrm{~F}\), and \(E(t)=\) \(120 \sin t \mathrm{~V} .(Q(0)=0 \mathrm{C}, I(0)=0 \mathrm{~A}\). \()\)
Consider a brake that acts on a wheel. Assuming that the force due to friction depends only on the angular velocity of the wheel, \(d \theta / d t\), we have \(I d^{2} \theta / d t^{2}=\) \(-F R \operatorname{sgn}(d \theta / d t)\) to describe the spinning motion of the wheel, where \(R\) is the radius of the brake drum, \(F\) is the frictional force, \(I\) is the moment of inertia of the wheel, and \(\operatorname{sgn}(x)=\left\\{\begin{array}{l}1, x>0 \\ 0, x=0 \\\ -1, x<0\end{array}\right.\). (a) Let \(d \theta / d t=y\) and transform this second order equation into a system of first order equations. (b) What are the equilibrium points of this system? (c) Show that \(\frac{d^{2} \theta}{d t}=\) \(\frac{d \theta}{d t} \frac{d}{d \theta}\left(\frac{d \theta}{d t}\right)\). (d) Use the relationship in (c) to show that the paths in the phase plane are \(I(d \theta / d t)^{2}=-2 F R \theta+C, d \theta / d t>0\) and \(I(d \theta / d t)^{2}=2 F R \theta+C, d \theta / d t<0\). What are these paths?
(See Exercise 18.) What are the paths in the phase plane if \(V(x)=-\frac{1}{2} x^{2}\) ? How does this compare with the classification of the equilibrium point of the corresponding system of first order equations? Notice that if \(V\) has a local maximum at \(x=a\), the system has a saddle at the corresponding point in the phase plane.
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