Chapter 2: Problem 55
\(d y / d x=e^{2 x-y}, y(0)=1\)
Short Answer
Expert verified
y = ln((1/2) e^{2x} + e - 1/2)
Step by step solution
01
- Write the differential equation
Given the differential equation: dy/dx = e^{2x - y}and the initial condition: y(0) = 1
02
- Separate the variables
To solve the differential equation, separate the variables: Rewrite it as: e^y dy = e^{2x} dx
03
- Integrate both sides
Integrate both sides of the equation: ∫ e^y dy = ∫ e^{2x} dxThis gives: e^y = (1/2) e^{2x} + C
04
- Apply the initial condition
Use the initial condition y(0) = 1 to find the constant C: e^1 = (1/2) e^0 + CThus: e = 1/2 + CC = e - 1/2
05
- Solve for y
Now solve for y: e^y = (1/2) e^{2x} + e - 1/2 Take the natural logarithm of both sides: y = ln((1/2) e^{2x} + e - 1/2)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
initial condition
An initial condition in differential equations is a value that the solution must satisfy at a particular point. In the given problem, the initial condition is y(0) = 1.
It's important because it allows us to find the specific solution to the differential equation rather than a general one. Here, once we integrate and solve for the constant of integration, the initial condition y(0) = 1 helps us determine this constant accurately.
One essential step is substituting x = 0 and y = 1 into the integrated equation. By doing this, we ensure the solution curve correctly matches the given starting point. This typically narrows it down to a precise solution rather than an infinite number of potential solutions.
It's important because it allows us to find the specific solution to the differential equation rather than a general one. Here, once we integrate and solve for the constant of integration, the initial condition y(0) = 1 helps us determine this constant accurately.
One essential step is substituting x = 0 and y = 1 into the integrated equation. By doing this, we ensure the solution curve correctly matches the given starting point. This typically narrows it down to a precise solution rather than an infinite number of potential solutions.
separation of variables
Separation of variables is a method used to solve differential equations. The goal is to rearrange the equation so that each variable appears on one side. In the problem given, we start with the equation: \(\frac{dy}{dx} = e^{2x - y}\).
To use separation of variables:
To use separation of variables:
- Rearrange the equation: \(e^y dy = e^{2x} dx\)
- Now, both sides are ready for integration. Notice, all terms involving y are on the left, and x terms are on the right. This allows us to treat the differentials separately and solve the equation more easily.
integration
Integration is the process of finding the integral of a function, which is essential in solving differential equations. In this problem, after separation of variables, we need to integrate both sides:
\begin{aligned} &\int e^y dy = \int e^{2x} dx \ &e^y = \frac{1}{2} e^{2x} + C \end{aligned}\ Here, integration transforms the initial differential equation into an algebraic form.
On the left, we integrate \(e^y\) with respect to y and on the right, \(e^{2x}\) with respect to x. After integration, we get an equation that includes a constant of integration (C).
Following integration, the initial condition \(y(0) = 1\) is used to find C. Integration is fundamental for solving differential equations because it simplifies them, enabling us to apply initial conditions or boundary values to find one specific solution.
\begin{aligned} &\int e^y dy = \int e^{2x} dx \ &e^y = \frac{1}{2} e^{2x} + C \end{aligned}\ Here, integration transforms the initial differential equation into an algebraic form.
On the left, we integrate \(e^y\) with respect to y and on the right, \(e^{2x}\) with respect to x. After integration, we get an equation that includes a constant of integration (C).
Following integration, the initial condition \(y(0) = 1\) is used to find C. Integration is fundamental for solving differential equations because it simplifies them, enabling us to apply initial conditions or boundary values to find one specific solution.