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(Principle of Superposition for Nonhomogeneous Equations) Show that if \(\phi_{1}=\phi_{1}(t)\) is a solution of \(d y / d t+p(t) y=f_{1}(t)\) and \(\phi_{2}=\phi_{2}(t)\) is a solution of \(d y / d t+p(t) y=\) \(f_{2}(t)\) then \(\phi=\phi_{1}+\phi_{2}\) is a solution of \(d y / d t+p(t) y=f_{1}(t)+f_{2}(t)\).

Short Answer

Expert verified
The combined solution \(\phi = \phi_1 + \phi_2\) satisfies the equation \(\frac{d}{dt}[ \phi ] + p(t) \phi = f_1(t) + f_2(t)\), by substitution and differentiation.

Step by step solution

01

Write down the given solutions

The solutions given are \(\phi_1 = \phi_1(t)\) for the equation \(\frac{d}{dt}[ \phi_1 ] + p(t) \phi_1 = f_1(t)\) and \(\phi_2 = \phi_2(t)\) for \(\frac{d}{dt}[ \phi_2 ] + p(t) \phi_2 = f_2(t)\).
02

Propose a combined solution

We need to show that the combined function \(\phi = \phi_1 + \phi_2\) satisfies the equation \(\frac{d}{dt}[ \phi ] + p(t) \phi = f_1(t) + f_2(t)\).
03

Differentiate the combined solution

Differentiate \(\phi = \phi_1 + \phi_2 \), which gives \(\frac{d}{dt}[ \phi ] = \frac{d}{dt}[ \phi_1 + \phi_2 ] = \frac{d}{dt}[ \phi_1 ] + \frac{d}{dt}[ \phi_2 ]\).
04

Substitute derivatives into the left-hand side

Substitute \(\frac{d}{dt}[ \phi ] \) and \(\phi = \phi_1 + \phi_2\) into the left-hand side of the combined equation: \(\frac{d}{dt}[ \phi ] + p(t) \phi = \frac{d}{dt}[ \phi_1 ] + \frac{d}{dt}[ \phi_2 ] + p(t)( \phi_1 + \phi_2 )\).
05

Use the original differential equations

Replace \(\frac{d}{dt}[ \phi_1 ] + p(t) \phi_1\) with \(f_1(t)\) and \(\frac{d}{dt}[ \phi_2 ] + p(t) \phi_2\) with \(f_2(t)\), which derive from the given solutions: \(\frac{d}{dt}[ \phi ] + p(t) \phi = f_1(t) + f_2(t)\).
06

Conclude the proof

The combined function \(\phi = \phi_1 + \phi_2\) satisfies the differential equation \(\frac{d}{dt}[ \phi ] + p(t) \phi = f_1(t) + f_2(t)\), proving the principle of superposition.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Nonhomogeneous Differential Equations
A nonhomogeneous differential equation is a type of differential equation that includes a non-zero term, typically referred to as the 'forcing function' or 'nonhomogeneous term'. This distinguishes them from homogeneous differential equations, which have a right-hand side equal to zero.
The general form of a first-order nonhomogeneous differential equation is:
\[ \frac{dy}{dt} + p(t)y = f(t) \]
In this equation:
  • \( \frac{dy}{dt} \) is the first derivative of the function \( y \) with respect to \( t \).
  • \( p(t) \) is a function of \( t \).
  • \( f(t) \) is the nonhomogeneous term dependent on \( t \).
The presence of \( f(t) \) means the solution will not be simply scaled versions of each other as in homogeneous cases. Instead, it has a particular solution that addresses the specific form of \( f(t) \).
The principle of superposition plays a key role in solving these equations, especially when combined with solutions to homogeneous parts.
Linear Differential Equations
Linear differential equations are those in which the dependent variable and its derivatives appear to the first power and are not multiplied together. They can be first-order or higher-order.
The general form of a first-order linear differential equation is:
\[ \frac{dy}{dt} + p(t)y = f(t) \]
Here, 'linear' means:
  • \( y \) and its derivative appear to the first power.
  • There are no products or powers of \( y \) and its derivatives.
Linear equations enable the use of strong analytical techniques, such as the superposition principle, described in the initial exercise.
This same principle helps us solve linear equations by breaking them into simpler parts, verifying their individual contributions, and then combining these parts.
Understanding linear differential equations is crucial as it provides a strong foundation for studying more complex non-linear differential equations.
Solution of Differential Equations
Finding the solution to differential equations involves determining a function or set of functions that satisfy the equation. For nonhomogeneous linear differential equations, solutions typically include:
  • Particular Solution: A specific solution that satisfies the nonhomogeneous differential equation.

  • Homogeneous Solution: A solution of the associated homogeneous equation (i.e., where \( f(t) = 0 \)).
The total solution is the sum of the particular solution and the homogeneous solution, utilizing the principle of superposition. This combination ensures that all terms of the differential equation, including the nonhomogeneous part, are satisfied:
\[ y = y_h + y_p \]
Where:\( y_h \) is the homogeneous solution and \( y_p \) is the particular solution.
Understanding and achieving these solutions often involves techniques like undetermined coefficients or variation of parameters for particular solutions.
Differential Operator
The differential operator is a powerful tool used in calculus and differential equations. It simplifies the expressions by providing a convenient shorthand notation for taking derivatives.
An example of a differential operator is:
\[ D = \frac{d}{dt} \]
When applying this to a function, it operates as follows:
\[ Dy = \frac{d}{dt} y \]
This operator notation allows us to recast differential equations into more compact and tractable forms. For instance, the operator form of a linear differential equation is:
\[ (D + p(t)) y = f(t) \]
Here, using differential operators simplifies manipulation and makes the application of linear algebra techniques possible.
Differential operators play a crucial role in solving both homogeneous and nonhomogeneous differential equations, especially when combined with methods such as the superposition principle.

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Most popular questions from this chapter

(First Order Linear Equations with Periodic Forcing Function) Consider the differential equation \(d y / d t+c y=f(t)\), where \(f(t)\) is a periodic function and \(c\) is a constant. The goal of this exercise is to determine if equations of this form have a periodic solution. (a) Solve the IVP \(y^{\prime}+y / 2=\) \(\sin t, y(0)=a\). For what values of \(a\) does the IVP have a periodic solution? Graph the slope field for this ODE. Describe the behavior of the other solutions. Do they approach the periodic solution found in (a) as \(t \rightarrow \infty\) or \(t \rightarrow-\infty\) ? (b) Solve the IVP \(y^{\prime}-y / 2=\sin t, y(0)=a\). For what values of \(a\) does the IVP have a periodic solution? Graph the slope field for this ODE. Describe the behavior of the other solutions. Do they approach the periodic solution found in (b) as \(t \rightarrow \infty\) or \(t \rightarrow-\infty\) ? (c) Based on your findings in (a) and (b), does the ODE \(y^{\prime}+\) \(c y=f(t)\), where \(f(t)\) is a periodic function and \(c\) is a constant, have a periodic solution? How does the value of \(c\) affect the other solutions?

(Pollution) Under normal atmospheric conditions, the density of soot particles \(N(t)\) satisfies the differential equation $$ \frac{d N}{d t}=-k_{c} N^{2}+k_{d} N, $$ where \(k_{c}\), called the coagulation constant, is a constant that relates to how well particles stick together; and \(k_{d}\), called the dissociation constant, is a constant that relates to how well particles fall apart. Both of these constants depend on temperature, pressure, particle size, and other external forces. \({ }^{3}\) (a) Find a general solution of this Bernoulli equation. (b) Find the solution that satisfies the initial condition \(N(0)=N_{0} \cdot\left(N_{0}>0\right)\) The following table lists typical values of \(k_{c}\) and \(k_{d}\). \begin{tabular}{l|l} \hline\(k_{c}\) & \(k_{d}\) \\ \hline 163 & 5 \\ 125 & 26 \\ 95 & 57 \\ 49 & 85 \\ 300 & 26 \\ \hline \end{tabular} (c) For each pair of values in the previous table, sketch the graph of \(N(t)\) if \(N(0)=N_{0}\) for \(N_{0}=0.01,0.05,0.1,0.5\), \(0.75,1,1.5\), and 2. Regardless of the ini-tial condition \(N(0)=N_{0}\), what do you notice in each case? Do pollution levels seem to be more sensitive to \(k_{c}\) or \(k_{d}\) ? Does your result make sense? Why? (d) Show that if \(k_{d}>0, \lim _{t \rightarrow \infty} N(t)=\) \(k_{d} / k_{c}\). Why is the assumption that \(k_{d}>\) 0 reasonable? (e) For each pair in the table, calculate \(\lim _{t \rightarrow \infty} N(t)=k_{d} / k_{c}\). Which situation results in the highest pollution levels? How could the situation be changed?

Graph the solution of \(y^{\prime}=\sin (x y)\) subject to the initial condition \(y(0)=i\) on the interval \([0,7]\) for \(i=0.5,1.0,1.5,2.0\), and \(2.5\). In each case, approximate the value of the solution if \(x=0.5\).

\((t+y) d t-t d y=0, y(1)=1\)

\(2 t y d t+\left(t^{2}+y^{2}\right) d y=0\)

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