Chapter 8: Problem 11
Compute the Stirling numbers of the second kind \(S(8, k),(k=0,1, \ldots, 8)\).
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 8: Problem 11
Compute the Stirling numbers of the second kind \(S(8, k),(k=0,1, \ldots, 8)\).
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
Use the generating function for the large Schröder numbers to compute the first few large Schröder numbers.
Let \(t_{1}, t_{2}, \ldots, t_{m}\) be distinct positive integers, and let $$q_{n}=q_{n}\left(t_{1}, t_{2}, \ldots, t_{m}\right)$$ equal the number of partitions of \(n\) in which all parts are taken from \(t_{1}, t_{2}, \ldots, t_{m}\). Define \(q_{0}=1\). Show that the generating function for \(q_{0}, q_{1}, \ldots, q_{n}, \ldots\) is$$\prod_{k=1}^{m}\left(1-x^{t_{k}}\right)^{-1} .$$
Determine the triangularization of a convex polygonal region corresponding to the following multiplication schemes: (a) \(\left(a_{1} \times\left(\left(\left(a_{2} \times a_{3}\right) \times\left(a_{4} \times a_{5}\right)\right) \times a_{6}\right)\right)\) (b) \(\left(\left(\left(a_{1} \times a_{2}\right) \times\left(a_{3} \times\left(a_{4} \times a_{5}\right)\right)\right) \times\left(\left(a_{6} \times a_{7}\right) \times a_{8}\right)\right)\)
Prove that the number of partitions of the positive integer \(n\) into parts each of which is at most 2 equals \(\lfloor n / 2\rfloor+1\). (Remark: There is a formula, namely the nearest integer to \(\frac{(n+3)^{2}}{12}\), for the number of partitions of \(n\) into parts each of which is at most 3 but it is much more difficult to prove. There is also one for partitions with no part more than 4, but it is even more complicated and difficult to prove.)
Find and verify a general formula for $$\sum_{k=0}^{n} k^{p}$$ involving Stirling numbers of the second kind.
What do you think about this solution?
We value your feedback to improve our textbook solutions.