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Suppose a poker hand contains seven cards rather than five. Compute the probabilities of the following poker hands: (a) a seven-card straight (b) four cards of one rank and three of a different rank (c) three cards of one rank and two cards of each of two different ranks (d) two cards of each of three different ranks, and a card of a fourth rank (e) three cards of one rank and four cards of each of four different ranks (f) seven cards each of different rank

Short Answer

Expert verified
The probability for (a) seven-card straight is approximately \(1.943 * 10^{-3}\). For (b) four cards of one rank and three of a different rank is approximately \(9.743 * 10^{-3}\). For (c) three cards of one rank and two cards of each of two different ranks is approximately \(1.060 * 10^{-2}\). For (d) two cards of each of three different ranks, and a card of a fourth rank is approximately \(1.770 * 10^{-2}\). For (e) three cards of one rank and four cards of each of four different ranks is 0 (impossible). For (f) seven cards each of different rank is approximately \(1.679 * 10^{-2}\).

Step by step solution

01

Calculation for part (a)

For a seven-card straight, first count the number of ways to get a 7 sequential cards from a deck. There are 8 possible sequences (A-7, 2-8, 3-9, 4-10, 5-J, 6-Q, 7-K, 10-A). Multiply by 4 to get the outcomes for each suit, and then by 4 again as any of the 7 cards can have a different suit. Total outcomes = 133784560 (total 7-card combinations). So \(P = \frac{(8*4^4)}{133784560}\)
02

Calculation for part (b)

For four cards of one rank and three of a different rank: count the number of ways to select 2 ranks out of 13 and ways to select suits for those cards. Total outcomes is same as before. So \(P = \frac{(\binom{13}{2} * \binom{4}{4} * \binom{4}{3})}{133784560}\)
03

Calculation for part (c)

For three cards of one rank and two cards of each of two different ranks: count the number of ways to select 3 ranks out of 13 and ways to select suits for those cards. Total outcomes remain same. So, \(P = \frac{(\binom{13}{3} * \binom{4}{3} * \binom{4}{2} * \binom{4}{2})}{133784560}\)
04

Calculation for part (d)

For two cards of each of three different ranks, and a card of a fourth rank: count the number of ways to select 4 ranks out of 13 and ways to select suits for those cards. Total outcomes remain same. So, \(P = \frac{(\binom{13}{4} *{\binom{4}{2}}^{3} * \binom{4}{1})}{133784560}\)
05

Calculation for part (e)

For three cards of one rank and four cards of each of four different ranks: It's not possible as there would be 16 cards which is greater than 7. So, probability here is 0.
06

Calculation for part (f)

For seven cards each of different rank: count the number of ways to select 7 ranks out of 13 and ways to select suits for those cards. Total outcomes remain same. So, \(P = \frac{(\binom{13}{7} * \binom{4}{1}^7)}{133784560}\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Combinatorics
Combinatorics is an essential field of mathematics primarily concerned with counting, arrangement, and combination of elements within a set according to certain rules. It plays a vital role in calculating probabilities of poker hands, where the elements are the cards and the rules are dictated by the hand rankings and the game itself.

For anyone diving into poker probabilities, understanding the basics of combinatorial mathematics, often simply called 'combinatorics', is crucial. When calculating the odds of getting a specific poker hand, we use combinatorial principles to figure out how many different ways cards can be arranged to form that hand.
Probability of Poker Hands
In the realm of poker, each hand's probability is calculated based on how many possible combinations can result in that hand, divided by all possible card combinations. Since a standard deck contains 52 cards, when dealing with a typical five-card hand, the number of combinations is given by the binomial coefficient, often represented by \( \binom{n}{k} \) where \( n \) is the total number of available distinct elements (52 cards), and \( k \) is the number of elements chosen (5 cards, in this case).

For our exercise, extending the hand size to seven cards alters these probabilities significantly. Calculating these in a seven-card scenario requires careful combination of hand conditions (like sequentials or suits) with the fundamental counting principles to determine the number of favorable outcomes for each hand type.
Calculating Combinations
When it comes to calculating combinations, which is fundamental in assessing poker hand probabilities, the binomial coefficient formula \( \binom{n}{k} = \frac{n!}{k! (n-k)!} \) comes into play. Here, \( n! \) denotes the factorial of \( n \) – the product of all positive integers up to \( n \). This formula helps determine the number of ways to choose \( k \) elements from a set of \( n \) distinct elements without regard to the order.

In poker, for instance, choosing 2 ranks out of the 13 available in a deck can do done in \( \binom{13}{2} \) ways. Additionally, for a specific hand, card suits become a factor – you might need to select 4 cards of the same suit from the 4 available suits (\( \binom{4}{4} \) ways) or maybe just 2, which can be done in \( \binom{4}{2} \) ways. These counting strategies are applied to compute the total number of possible hands for the various categories mentioned in the exercise.

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