Chapter 1: Problem 22
Construct a pair of orthogonal Latin squares of order \(4 .\)
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Chapter 1: Problem 22
Construct a pair of orthogonal Latin squares of order \(4 .\)
These are the key concepts you need to understand to accurately answer the question.
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Show how to cut a cube, 3 feet on an edge, into 27 cubes, 1 foot on an edge, using exactly 6 cuts but making a nontrivial rearrangement of the pieces between two of the cuts.
(a) Let \(f(n)\) count the number of different perfect covers of a 2 -by- \(n\) chessboard by dominoes. Evaluate \(f(1), f(2), f(3), f(4)\), and \(f(5) .\) Try to find (and verify) a simple relation that the counting function \(f\) satisfies. Use this relation to compute \(f(12)\). (b) * Let \(g(n)\) be the number of different perfect covers of a 3 -by-n chessboard by dominoes. Evaluate \(g(1), g(2), \ldots, g(6)\).
Let \(n\) be a positive integer divisible by 4 , say \(n=4 m\). Consider the following construction of an \(n\) -by-n array: (1) Proceeding from left to right and from first row to nth row, fill in the places of the array with the integers \(1,2, \ldots, n^{2}\) in order. (2) Partition the resulting square array into \(m^{2} 4\) -by-4 smaller arrays. Replace each number \(a\) on the two diagonals of each of the 4 -by-4 arrays with its "complement" \(n^{2}+1-a\). Verify that this construction produces a magic square of order \(n\) when \(n=4\) and \(n=8\). (Actually it produces a magic square for each \(n\) divisible by 4.)
Show that the result of replacing every integer \(a\) in a magic square of order \(n\) with \(n^{2}+1-a\) is a magic square of order \(n\).
Imagine a prison consisting of 64 cells arranged like the squares of an 8 -by-8 chessboard. There are doors between all adjoining cells. A prisoner in one of the corner cells is told that he will be released, provided he can get into the diagonally opposite corner cell after passing through every other cell exactly once. Can the prisoner obtain his freedom?
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