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Determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. The smallest real number in the solution set of \(2 x>6\) is 4.

Short Answer

Expert verified
The statement is false. The correct statement is 'The smallest real number in the solution set of \(2x > 6\) is any number greater than 3'.

Step by step solution

01

Solve the inequality

To do this, divide both sides of the inequality by 2 to isolate x on the left side. \(2x > 6\) becomes \(x > 3\) when divide each side by 2.
02

Compare the result with the given statement

The statement 'The smallest real number in the solution set of \(2x > 6\) is 4', suggests that the solution the inequality begins at x = 4. This would not be true in our case, because any number greater than 3 is part of the solution.
03

Correct the false statement

The statement can be corrected by saying: 'The smallest real number in the solution set of \(2x > 6\) is greater than 3'.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Inequality Solutions
Inequalities are mathematical statements that compare two expressions and use signs like '>','<','eq' to show the relationship between them. Solving an inequality means finding all the real numbers that make the inequality true. Unlike equations, where typically there's a single solution, inequalities often have a range of solutions forming an interval.

For instance, in the given exercise, we start by solving the inequality by dividing both sides by 2, obtaining the simplified inequality, \(x > 3\). This tells us that any number greater than 3 is the solution. Therefore, there is not a single 'smallest' real number that satisfies the inequality because numbers such as 3.1, 3.01, or even 3.0001 are all solutions, and you can always find a number closer to but greater than 3. Inequality solutions can be expressed in several ways, including number line diagrams, interval notation, and set builder notation, emphasizing the range of possible solutions.
Real Numbers
Real numbers include all the numbers on the number line, embracing whole numbers, fractions, decimals, and irrational numbers. They are fundamental to the study of algebra because they are the solutions we often seek when solving algebraic expressions and equations.

In the context of inequalities, when we say that the solution set consists of real numbers greater than 3, we're including every decimal and fraction that is just above 3, an endless continuum. It’s essential to understand that there is no 'smallest' real number next to another, as real numbers are densely packed on the number line. This dense nature implies that between any two real numbers there are infinitely many other real numbers, no matter how close these two might be.
Algebraic Expressions
Algebraic expressions are combinations of variables, numbers, and at least one arithmetic operation. In the context of inequalities and equations, variables represent unknown values we are attempting to find. Variables combined with numbers through operations create algebraic statements that mathematically model real-world situations or pure numeric relationships.

Given the inequality \(2x > 6\), '2x' is an algebraic expression with 'x' as the variable. When we solve the inequality, as in the exercise provided, we manipulate these expressions to isolate the variable and ascertain the range of values that make the inequality true. Clarifying these expressions and understanding how to solve them are key to mastering many areas of algebra, including solving inequalities.

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Most popular questions from this chapter

Determine whether each statement "makes sense" or "does not make sense" and explain your reasoning. It's not a good thing for a business if \(R(x)>C(x)\)

Will help you prepare for the material covered in the next section. Find all values of \(x\) satisfying \(1-4 x=3\) or \(1-4 x=-3\)

In more U.S. marriages, spouses have different faiths. The bar graph shows the percentage of households with an interfaith marriage in 1988 and \(2008 .\) Also shown is the percentage of households in which a person of faith is married to someone with no religion. (GRAPH CANT COPY) The formula $$1-\frac{1}{2} x+2=$$ models the percentage of U.S. households with an interfaith marriage, \(I, x\) years after \(1988 .\) The formula $$N=\frac{1}{4} x+6$$ models the percentage of U.S. households in which a person of faith is married to someone with no religion, \(N, x\) years after I988. Use these models to solve. a. In which years will more than \(34 \%\) of U.S. households have an interfaith marriage? b. In which years will more than \(15 \%\) of U.S. households have a person of faith married to someone with no religion? c. Based on your answers to parts (a) and (b), in which years will more than \(34 \%\) of households have an interfaith marriage and more than \(15 \%\) have a faith/no religion marriage? d. Based on your answers to parts (a) and (b), in which years will more than \(34 \%\) of households have an interfaith marriage or more than \(15 \%\) have a faith/no religion marriage?

Solve by graphing: $$\left\\{\begin{array}{l}y=3 x-2 \\\y=-2 x+8\end{array}\right.$$

Solve: \(|2 x+5|=3 x+4\)

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