Chapter 8: Problem 15
Find the indicated function values. $$f(x)=2 x^{2}+3 x-1$$ a. \(f(0)\) b. \(f(3)\) c. \(f(-4)\) d. \(f(b)\) e. \(f(5 a)\)
Short Answer
Expert verified
The calculated function values are: a. \(f(0) = -1\), b. \(f(3) = 20\), c. \(f(-4) = 23\), d. \(f(b) = 2b^2 + 3b - 1\), e. \(f(5a) = 50a^2 + 15a - 1\)
Step by step solution
01
Calculate f(0)
To calculate \(f(0)\), just input \(x=0\) into the function. So, \(f(0)=2(0)^{2}+3(0)-1 = -1\)
02
Calculate f(3)
To calculate \(f(3)\), input \(x=3\) into the function. \(f(3)=2(3)^2+3(3)-1=20\)
03
Calculate f(-4)
To calculate \(f(-4)\), input \(x=-4\) into the function. \(f(-4)=2(-4)^2+3(-4)-1=23\)
04
Calculate f(b)
To calculate \(f(b)\), input \(x=b\) into the function. \(f(b)=2(b)^2+3b-1\)
05
Calculate f(5a)
To calculate \(f(5a)\), input \(x=5a\) into the function. \(f(5a)=2(5a)^2+3(5a)-1=50a^2 + 15a - 1\)
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Key Concepts
These are the key concepts you need to understand to accurately answer the question.
Quadratic Function
A quadratic function is a type of polynomial function that follows the standard form \(f(x) = ax^2 + bx + c\), where \(a\), \(b\), and \(c\) are constants and \(a eq 0\). These functions form a parabola when graphed, which can either open upwards or downwards depending on the sign of the coefficient \(a\).
Quadratic functions are used to model real-world situations such as projectile motion, optimization problems, and more. In the given exercise, the function is \(f(x) = 2x^2 + 3x - 1\). This is a typical quadratic equation characterized by:
Quadratic functions are used to model real-world situations such as projectile motion, optimization problems, and more. In the given exercise, the function is \(f(x) = 2x^2 + 3x - 1\). This is a typical quadratic equation characterized by:
- The quadratic coefficient \(a = 2\), which dictates the parabola's width and direction.
- The linear coefficient \(b = 3\), which affects the slope of the parabola.
- The constant \(c = -1\), which shifts the parabola along the vertical axis.
Substitution Method
The substitution method in the context of function evaluation involves replacing the variable \(x\) with a specific value to find the function's output at that point. It is a straightforward technique used to compute outputs for various inputs.
Here’s how the process works step-by-step:
Here’s how the process works step-by-step:
- Identify the value you need to evaluate. For example, for \(f(0)\), replace \(x\) with 0.
- Substitute this value into every instance of \(x\) in the function.
- Perform the arithmetic operations to simplify and find the result.
- To find \(f(0)\), you replace \(x\) with 0, leading to the calculation: \(f(0) = 2(0)^2 + 3(0) - 1 = -1\).
- Similarly, to find \(f(3)\), substitute \(x = 3\), performing the calculation: \(f(3) = 2(3)^2 + 3(3) - 1 = 20\).
Algebraic Expressions
An algebraic expression is a combination of variables, constants, and arithmetic operations (addition, subtraction, multiplication, division). In the context of the exercise, we see expressions like \(2x^2 + 3x - 1\) that represent the quadratic function. Let's break down some useful components:
- **Terms:** The individual parts of an expression separated by plus or minus signs, such as \(2x^2\), \(3x\), and \(-1\).
- **Coefficients:** Numbers that multiply variables, such as 2 for \(x^2\) and 3 for \(x\).
- **Constants:** Numbers on their own, such as \(-1\) in this function.
Polynomial Functions
Polynomial functions are mathematical expressions that involve sums of powers of variables, each multiplied by a coefficient. They take the general form \(a_n x^n + a_{n-1} x^{n-1} + \, ... \, + a_1 x + a_0\), where \(n\) is a non-negative integer.
Quadratic functions, like the one in this exercise, are a specific type of polynomial where the highest power is 2. Here are a few key points about polynomial functions:
Quadratic functions, like the one in this exercise, are a specific type of polynomial where the highest power is 2. Here are a few key points about polynomial functions:
- A polynomial’s degree is the highest power of the variable; for quadratics, it's always 2.
- The coefficients decide the shape and the slope of the graph.
- Polynomial functions are continuous and smooth, meaning they have no breaks or sharp corners.