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$$\text { In Exercises } 61-68, \text { solve or simplify, whichever is appropriate.}$$ $$\frac{x^{2}+4 x-2}{x^{2}-2 x-8}-1-\frac{4}{x-4}$$

Short Answer

Expert verified
\(- \frac{x^{2}-6x-6}{(x - 4)(x + 2)}\)

Step by step solution

01

Factorize the Polynomials

The second polynomial in the denominator \(x^{2}-2x-8\) can be factored as \((x-4)(x+2)\). The first fraction becomes \(\frac{x^{2}+4x-2}{(x-4)(x+2)}\). The expression now can be rewritten as \(\frac{x^{2}+4x-2}{(x-4)(x+2)} - 1 - \frac{4}{x-4}\).
02

Find a Common Denominator

You now need to find a common denominator for the three terms to combine them. The common denominator of \((x-4)(x+2)\), \(x-4\), and 1 would be \((x-4)(x+2)\). So, the whole expression is transformed into \(\frac{x^{2}+4x-2}{(x-4)(x+2)} - \frac{(x-4)(x+2)}{(x-4)(x+2)} - \frac{4(x+2)}{(x-4)(x+2)}\).
03

Combine the Fractions

Now combine all the terms over the single denominator \((x-4)(x+2)\), this results in \(\frac{x^{2}+4x-2 - (x-4)(x+2) - 4(x+2)}{(x-4)(x+2)}\).
04

Simplify the Numerator

Expand and simplify the numerator: \(x^{2}+4x-2 - (x^{2}-2x-8) - 4x-8\), eventually becomes: \(-x^{2}+6x+6\).
05

Final Result

Replacing the simplified numerator in the fraction you get \(- \frac{x^{2}-6x-6}{(x - 4)(x + 2)}\) as the final result.

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