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Multiply as indicated. $$\frac{x^{2}+6 x+9}{x^{3}+27} \cdot \frac{1}{x+3}$$

Short Answer

Expert verified
So, the product of the given fractions will be \(\frac{1}{x^2-3x+9}\)

Step by step solution

01

Rewrite the First Polynomial

The given fraction can be written as \((x+3)^2\) for the numerator and \((x+3)(x^2-3x+9)\) for the denominator. Therefore, the expression can now be rewritten as \(\frac{(x+3)^2}{(x+3)(x^2-3x+9)}\cdot\frac{1}{x+3}\). This makes it possible to cancel out certain terms.
02

Simplify the Complex Fraction

In order to simplify the expression, cancel out the terms that appear in both the numerator and the denominator. So, the first \((x+3)\) in the numerator and the \((x+3)\) in the denominator cancel each other out. The expression now becomes \(\frac{(x+3)}{(x^2-3x+9)}\cdot\frac{1}{x+3}\)
03

Perform the Multiplication

The multiplication of these two fractions will result in another cancellation of \((x+3)\) from the numerator and the denominator. We are thus left by \(\frac{1}{x^2-3x+9}\) as the product.

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Simplifying Rational Expressions
Rational expressions are fractions where both the numerator and the denominator are polynomials. Simplifying them involves reducing the expression to its simplest form. This helps in tackling more complex calculations down the line.
When simplifying rational expressions, look for common terms in both the numerator and the denominator.
  • First, break down or factorize any polynomial involved to identify the common terms.
  • Once identified, these common terms can be canceled out because they are in both the numerator and the denominator, simplifying the expression significantly.
For example, let's take the rational expression \( \frac{(x+3)^2}{(x+3)(x^2-3x+9)} \) multiplied by \( \frac{1}{x+3} \). Here, \((x+3)\) is a common factor in both fractions, allowing us to cancel it out, step-by-step, leading to a much simpler form. Through this process, we are left with \( \frac{1}{x^2-3x+9} \) as the final simplified rational expression.
Factoring Polynomials
Factoring polynomials is the process of breaking down a polynomial into simpler polynomials that, when multiplied together, give the original polynomial back. This is an essential step in simplifying rational expressions as it identifies common factors easily.
Here’s a simple way to factor polynomials:
  • Start by looking for common terms that each term in the polynomial shares. This could be a number, variable, or both.
  • Utilize methods like grouping, the difference of squares, or recognizing perfect squares like \((x+3)^2\), as shown in our exercise, to break down complex polynomials.
In the provided solution, \(x^2 + 6x + 9\) was identified as \((x+3)^2\), and \(x^3 + 27\) was factored into \((x+3)(x^2-3x+9)\). These factored forms then made simplifying the rational expression far easier by allowing for cancellation of common terms.
Canceling Common Factors
Canceling common factors in rational expressions allows us to simplify them to their most reduced form. This involves identifying and removing identical terms that appear in both the numerator and the denominator.
The cancellation process depends on successful factoring to expose these common terms. Look for matching polynomial expressions in the numerator and denominator which can be canceled.
  • This action mirrors the simplification of simple fractions like \( \frac{8}{4} \) to \( 2 \), by canceling the common factor 4.
  • Through canceling, calculations become easier and less prone to errors.
For instance, throughout our exercise, the factor \((x+3)\) appeared multiple times across the fractions. By canceling this commonality step-by-step, each occurrence was removed, ultimately simplifying the entire expression to \( \frac{1}{x^2 - 3x + 9} \). This demonstrates the power of cancellation in simplifying complex rational expressions.

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Most popular questions from this chapter

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