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In Exercises \(1-46,\) solve each rational equation. $$x+\frac{6}{x}=-7$$

Short Answer

Expert verified
The solutions to the equation are \(x = -1\) and \(x = -6\)

Step by step solution

01

Repositioning the terms

Shift the term containing the variable \(x\) to the right hand side of the equation in order to consolidate terms. Our equation becomes \(-x = -7 - \frac{6}{x} \)
02

Multiplying through by \(x\)

Multiply every term in the equation by \(x\) to eliminate the fraction and obtain a quadratic equation. The equation now becomes \(-x^2 = -7x - 6\)
03

Re-arrange the quadratic equation

Bring all the terms to one side of the equation to get the quadratic equation in standard form. The equation will then be \(x^2 +7x + 6 = 0\)
04

Factoring the quadratic equation

Express the quadratic equation \(x^2 +7x + 6 = 0\) in factored form as \((x+1)(x+6) = 0\)
05

Solving for \(x\)

By setting each factor equal to zero and solving for x, we get two solutions: \(x = -1\) and \(x = -6\)

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Key Concepts

These are the key concepts you need to understand to accurately answer the question.

Quadratic Equations
Quadratic equations are a fundamental aspect of algebra and appear frequently in various mathematical problems. They take on the general form of \(ax^2 + bx + c = 0\), where \(a\), \(b\), and \(c\) are constants and \(a \eq 0\).
When solving a quadratic equation, the goal is to find the value of \(x\) that satisfies the equation. There are multiple methods to solve these equations, such as factoring, completing the square, or using the quadratic formula \(x = \frac{{-b \pm \sqrt{{b^2-4ac}}}}{{2a}}\).
In the given exercise, the quadratic equation appears after eliminating the algebraic fraction and rearranging the terms. Recognizing and solving this kind of equation is integral to success in algebra and higher-level mathematics.
Factoring Polynomials
Factoring polynomials is a skill that can simplify many types of algebraic problems, especially solving quadratic equations. When a polynomial is factored, it's expressed as a product of its factors, which are polynomials of a lower degree. For instance, a quadratic polynomial \(ax^2 + bx + c\) can often be factored into two first-degree binomials as \(a(x - r)(x - s)\), where \(r\) and \(s\) are the roots of the polynomial.
In practice, factoring can be straightforward for some polynomials, such as when there are common factors or when a quadratic is a perfect square. However, it may not be possible to factor all polynomials with rational coefficients, and in such cases, other methods of solving equations must be used. In our step-by-step solution, the process of factoring was crucial to finding the equation's roots conveniently.
Algebraic Fractions
Algebraic fractions, also known as rational expressions, are fractions where the numerator, the denominator, or both contain algebraic expressions. Solving equations with algebraic fractions often involves finding a common denominator or clearing the fraction by multiplying both sides of the equation by the denominator.
It's essential to remember that the denominator should never equal zero since division by zero is undefined. Once the fractions are cleared, the resultant equation can be linear, quadratic, or even higher-order, depending on the expressions involved. The initial exercise features an algebraic fraction that leads to a quadratic equation; this process highlights the interconnectedness of mathematical concepts and emphasizes the importance of understanding how different algebraic operations interact with one another.

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