Chapter 6: Problem 9
In Exercises \(1-26,\) factor each difference of two squares. $$1-49 x^{2}$$
Short Answer
Step by step solution
Key Concepts
These are the key concepts you need to understand to accurately answer the question.
/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none}
Learning Materials
Features
Discover
Chapter 6: Problem 9
In Exercises \(1-26,\) factor each difference of two squares. $$1-49 x^{2}$$
These are the key concepts you need to understand to accurately answer the question.
All the tools & learning materials you need for study success - in one app.
Get started for free
Use factoring to solve quadratic equation. Check by substitution or by using a graphing utility and identifying \(x\)-intercepts. \(4 x(x+1)=15\)
Solve each equation. \(\left(x^{2}-5 x+5\right)^{3}=1\)
Solve equation and check your solutions. \((x-2)^{2}-5(x-2)+6=0\)
In Exercises \(119-122\), determine whether each statement is true or false. If the statement is false, make the necessary change(s) to produce a true statement. $$\begin{aligned} &\text { Because } x^{2}-25=(x+5)(x-5), \text { then } x^{2}+25=\\\ &(x-5)(x+5) \end{aligned}$$
If \((x+2)(x-4)=0\) indicates that \(x+2=0\) or \(x-4=0,\) explain why \((x+2)(x-4)=6\) does not mean \(x+2=6\) or \(x-4=6 .\) Could we solve the equation using \(x+2=3\) and \(x-4=2\) because \(3 \cdot 2=6 ?\)
What do you think about this solution?
We value your feedback to improve our textbook solutions.